The number of molecules present in 4 × 10 5 tons of SO 2 has to be found.

Question

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Answer 1

Question

Chapter 4, Problem 4CP

(a)

Interpretation Introduction

Interpretation:

The number of molecules present in $4 × 105 tons$ of $SO2$ has to be found.

(a)

Expert Solution

Explanation of Solution

Given,

The mass of $SO2$ is $4 × 105 tons$ .

$1 ton = 1000 kg4 ×105 tons = 4 ×105 × 1000 = 4×108$

$Number of moles = Mass in gramMolar massMolar mass of SO2= (32.065 g/mol S) + (2 × 15.9994 g/mol O) = 64.0638 g/molMass = 4 × 108 kg = 4 × 1011 gNumber of moles = 4 × 1011 g64.0638 g/mol = 6.24× 109 molesNumber of molecules = 6.24× 109 moles × 6.022×1023 = 3.76×1033 molecules$

(b)

Interpretation Introduction

Interpretation:

The number of molecules present in $25.0 lb$ of $SO2$ has to be found.

(b)

Expert Solution

Explanation of Solution

Given,

The mass of $SO2$ is $25.0 lb$ .

$1 lb = 0.45359 kgMass in kg = 25.01× 0.45359= 11.344 kg = 11344 g$

$Number of moles = Mass in gramMolar massMolar mass of SO2= (32.065 g/mol S) + (2 × 15.9994 g/mol O) = 64.0638 g/molMass = 11344 gNumber of moles = 11344 g64.0638 g/mol = 177.07 molesNumber of molecules = 177.07 moles × 6.022×1023 = 1.066×1026 molecules$

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Answer 2

Question

Chapter 4, Problem 4CP

(a)

Interpretation Introduction

Interpretation:

The number of molecules present in $4 × 105 tons$ of $SO2$ has to be found.

(a)

Expert Solution

Explanation of Solution

Given,

The mass of $SO2$ is $4 × 105 tons$ .

$1 ton = 1000 kg4 ×105 tons = 4 ×105 × 1000 = 4×108$

$Number of moles = Mass in gramMolar massMolar mass of SO2= (32.065 g/mol S) + (2 × 15.9994 g/mol O) = 64.0638 g/molMass = 4 × 108 kg = 4 × 1011 gNumber of moles = 4 × 1011 g64.0638 g/mol = 6.24× 109 molesNumber of molecules = 6.24× 109 moles × 6.022×1023 = 3.76×1033 molecules$

(b)

Interpretation Introduction

Interpretation:

The number of molecules present in $25.0 lb$ of $SO2$ has to be found.

(b)

Expert Solution

Explanation of Solution

Given,

The mass of $SO2$ is $25.0 lb$ .

$1 lb = 0.45359 kgMass in kg = 25.01× 0.45359= 11.344 kg = 11344 g$

$Number of moles = Mass in gramMolar massMolar mass of SO2= (32.065 g/mol S) + (2 × 15.9994 g/mol O) = 64.0638 g/molMass = 11344 gNumber of moles = 11344 g64.0638 g/mol = 177.07 molesNumber of molecules = 177.07 moles × 6.022×1023 = 1.066×1026 molecules$

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Answer 3

Question

Chapter 4, Problem 4CP

(a)

Interpretation Introduction

Interpretation:

The number of molecules present in $4 × 105 tons$ of $SO2$ has to be found.

(a)

Expert Solution

Explanation of Solution

Given,

The mass of $SO2$ is $4 × 105 tons$ .

$1 ton = 1000 kg4 ×105 tons = 4 ×105 × 1000 = 4×108$

$Number of moles = Mass in gramMolar massMolar mass of SO2= (32.065 g/mol S) + (2 × 15.9994 g/mol O) = 64.0638 g/molMass = 4 × 108 kg = 4 × 1011 gNumber of moles = 4 × 1011 g64.0638 g/mol = 6.24× 109 molesNumber of molecules = 6.24× 109 moles × 6.022×1023 = 3.76×1033 molecules$

(b)

Interpretation Introduction

Interpretation:

The number of molecules present in $25.0 lb$ of $SO2$ has to be found.

(b)

Expert Solution

Explanation of Solution

Given,

The mass of $SO2$ is $25.0 lb$ .

$1 lb = 0.45359 kgMass in kg = 25.01× 0.45359= 11.344 kg = 11344 g$

$Number of moles = Mass in gramMolar massMolar mass of SO2= (32.065 g/mol S) + (2 × 15.9994 g/mol O) = 64.0638 g/molMass = 11344 gNumber of moles = 11344 g64.0638 g/mol = 177.07 molesNumber of molecules = 177.07 moles × 6.022×1023 = 1.066×1026 molecules$

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Answer 4

Question

Chapter 4, Problem 4CP

(a)

Interpretation Introduction

Interpretation:

The number of molecules present in $4 × 105 tons$ of $SO2$ has to be found.

(a)

Expert Solution

Explanation of Solution

Given,

The mass of $SO2$ is $4 × 105 tons$ .

$1 ton = 1000 kg4 ×105 tons = 4 ×105 × 1000 = 4×108$

$Number of moles = Mass in gramMolar massMolar mass of SO2= (32.065 g/mol S) + (2 × 15.9994 g/mol O) = 64.0638 g/molMass = 4 × 108 kg = 4 × 1011 gNumber of moles = 4 × 1011 g64.0638 g/mol = 6.24× 109 molesNumber of molecules = 6.24× 109 moles × 6.022×1023 = 3.76×1033 molecules$

(b)

Interpretation Introduction

Interpretation:

The number of molecules present in $25.0 lb$ of $SO2$ has to be found.

(b)

Expert Solution

Explanation of Solution

Given,

The mass of $SO2$ is $25.0 lb$ .

$1 lb = 0.45359 kgMass in kg = 25.01× 0.45359= 11.344 kg = 11344 g$

$Number of moles = Mass in gramMolar massMolar mass of SO2= (32.065 g/mol S) + (2 × 15.9994 g/mol O) = 64.0638 g/molMass = 11344 gNumber of moles = 11344 g64.0638 g/mol = 177.07 molesNumber of molecules = 177.07 moles × 6.022×1023 = 1.066×1026 molecules$

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Answer 5

Chapter 4, Problem 4CP

(a)

Interpretation Introduction

Interpretation:

The number of molecules present in $4 × 105 tons$ of $SO2$ has to be found.

(a)

Expert Solution

Explanation of Solution

Given,

The mass of $SO2$ is $4 × 105 tons$ .

$1 ton = 1000 kg4 ×105 tons = 4 ×105 × 1000 = 4×108$

$Number of moles = Mass in gramMolar massMolar mass of SO2= (32.065 g/mol S) + (2 × 15.9994 g/mol O) = 64.0638 g/molMass = 4 × 108 kg = 4 × 1011 gNumber of moles = 4 × 1011 g64.0638 g/mol = 6.24× 109 molesNumber of molecules = 6.24× 109 moles × 6.022×1023 = 3.76×1033 molecules$

(b)

Interpretation Introduction

Interpretation:

The number of molecules present in $25.0 lb$ of $SO2$ has to be found.

(b)

Expert Solution

Explanation of Solution

Given,

The mass of $SO2$ is $25.0 lb$ .

$1 lb = 0.45359 kgMass in kg = 25.01× 0.45359= 11.344 kg = 11344 g$

$Number of moles = Mass in gramMolar massMolar mass of SO2= (32.065 g/mol S) + (2 × 15.9994 g/mol O) = 64.0638 g/molMass = 11344 gNumber of moles = 11344 g64.0638 g/mol = 177.07 molesNumber of molecules = 177.07 moles × 6.022×1023 = 1.066×1026 molecules$

Answer 6

Chapter 4, Problem 4CP

(a)

Interpretation Introduction

Interpretation:

The number of molecules present in $4 × 105 tons$ of $SO2$ has to be found.

(a)

Expert Solution

Explanation of Solution

Given,

The mass of $SO2$ is $4 × 105 tons$ .

$1 ton = 1000 kg4 ×105 tons = 4 ×105 × 1000 = 4×108$

$Number of moles = Mass in gramMolar massMolar mass of SO2= (32.065 g/mol S) + (2 × 15.9994 g/mol O) = 64.0638 g/molMass = 4 × 108 kg = 4 × 1011 gNumber of moles = 4 × 1011 g64.0638 g/mol = 6.24× 109 molesNumber of molecules = 6.24× 109 moles × 6.022×1023 = 3.76×1033 molecules$

Answer 7

Chapter 4, Problem 4CP

(a)

Interpretation Introduction

Interpretation:

The number of molecules present in $4 × 105 tons$ of $SO2$ has to be found.

Answer 8

(a)

Expert Solution

Explanation of Solution

Given,

The mass of $SO2$ is $4 × 105 tons$ .

$1 ton = 1000 kg4 ×105 tons = 4 ×105 × 1000 = 4×108$

$Number of moles = Mass in gramMolar massMolar mass of SO2= (32.065 g/mol S) + (2 × 15.9994 g/mol O) = 64.0638 g/molMass = 4 × 108 kg = 4 × 1011 gNumber of moles = 4 × 1011 g64.0638 g/mol = 6.24× 109 molesNumber of molecules = 6.24× 109 moles × 6.022×1023 = 3.76×1033 molecules$

Answer 9

(a)

Expert Solution

Answer 10

(a)

Expert Solution

Answer 11

Expert Solution

Answer 12

(b)

Interpretation Introduction

Interpretation:

The number of molecules present in $25.0 lb$ of $SO2$ has to be found.

(b)

Expert Solution

Explanation of Solution

Given,

The mass of $SO2$ is $25.0 lb$ .

$1 lb = 0.45359 kgMass in kg = 25.01× 0.45359= 11.344 kg = 11344 g$

$Number of moles = Mass in gramMolar massMolar mass of SO2= (32.065 g/mol S) + (2 × 15.9994 g/mol O) = 64.0638 g/molMass = 11344 gNumber of moles = 11344 g64.0638 g/mol = 177.07 molesNumber of molecules = 177.07 moles × 6.022×1023 = 1.066×1026 molecules$

Answer 13

(b)

Interpretation Introduction

Interpretation:

The number of molecules present in $25.0 lb$ of $SO2$ has to be found.

Answer 14

(b)

Expert Solution

Explanation of Solution

Given,

The mass of $SO2$ is $25.0 lb$ .

$1 lb = 0.45359 kgMass in kg = 25.01× 0.45359= 11.344 kg = 11344 g$

$Number of moles = Mass in gramMolar massMolar mass of SO2= (32.065 g/mol S) + (2 × 15.9994 g/mol O) = 64.0638 g/molMass = 11344 gNumber of moles = 11344 g64.0638 g/mol = 177.07 molesNumber of molecules = 177.07 moles × 6.022×1023 = 1.066×1026 molecules$