Chapter 4.9, Problem 4.17PP

(a)

Interpretation Introduction

Interpretation:

The balanced equation for the metallic iron reacts with ${\text{O}}_{\text{2}}$ gas to produce iron $\text{(III)}$ oxide has to be written.

Concept Introduction:

Balanced Chemical equation:

A balanced chemical equation is an equation which contains same elements in same number on both the sides (reactant and product side) of the chemical equation thereby obeying the law of conservation of mass.

(b)

Interpretation Introduction

Interpretation:

The amout (in $\text{g}$) of iron that is required to produce $\text{5}\text{.00 g}$ of product has to be calculated.

Concept Introduction:

Moles:

Mole of the compound is found by dividing mass of the substance with its molar mass.

  $\text{No}\text{. of moles (n) = }\frac{\text{mass}}{\text{Molar mass}}$

Mass:

Mass of the compound is calculated by mole of the compound multiplied with molar mass of the compound.

  $\text{Mass}\text{=}\text{Molar}\text{mass}\text{×}\text{mole}$