
Concept explainers
Interpretation:
The more stable of the two species A and B is to be determined.
Concept introduction:
A chair flip converts one cyclohexane chair conformer to the other. This also changes the orientations of the hydrogen atoms. The ones that were in axial positions initially move to equatorial positions and vice versa. In cyclohexane, these are indistinguishable. However, if one or more of these hydrogens is/are substituted by other atoms, the two can be distinguished. The stability of the conformer depends on orientation of the substituents. This is particularly true of bulky substituents. Large substituents are more stable in equatorial position. In axial position, steric interaction with the hydrogen atoms (or other groups) on the 3rd carbon reduce the stability of the conformer with bulky substituent in an axial position.

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Chapter 4 Solutions
Organic Chemistry: Principles And Mechanisms
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- TRANSMITTANCE เบบ Please identify the one structure below that is consistent with the 'H NMR and IR spectra shown and draw its complete structure in the box below with the protons alphabetically labeled as shown in the NMR spectrum and label the IR bands, including sp³C-H and sp2C-H stretch, indicated by the arrows. D 4000 OH LOH H₂C CH3 OH H₂C OCH3 CH3 OH 3000 2000 1500 HAVENUMBERI-11 1000 LOCH3 Draw your structure below and label its equivalent protons according to the peak labeling that is used in the NMR spectrum in order to assign the peaks. Integrals indicate number of equivalent protons. Splitting patterns are: s=singlet, d=doublet, m-multiplet 8 3Hb s m 1Hd s 3Hf m 2Hcd 2Had 1He 鄙视 m 7 7 6 5 4 3 22 500 T 1 0arrow_forwardRelative Transmittance 0.995 0.99 0.985 0.98 Please draw the structure that is consistent with all the spectral data below in the box and alphabetically label the equivalent protons in the structure (Ha, Hb, Hc ....) in order to assign all the proton NMR peaks. Label the absorption bands in the IR spectrum indicated by the arrows. INFRARED SPECTRUM 1 0.975 3000 2000 Wavenumber (cm-1) 1000 Structure with assigned H peaks 1 3 180 160 140 120 100 f1 (ppm) 80 60 40 20 0 C-13 NMR note that there are 4 peaks between 120-140ppm Integral values equal the number of equivalent protons 10.0 9.0 8.0 7.0 6.0 5.0 4.0 3.0 2.0 1.0 0.0 fl (ppm)arrow_forwardCalculate the pH of 0.0025 M phenol.arrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning
