Chapter 4, Problem 47QP

Interpretation Introduction

Interpretation:

The oxidation number isto be determined for the underlined atoms.

Concept introduction:

The oxidation number can be assigned using the following rules:

In free state, an element is always in $0$ oxidation state.

For a neutral compound, oxidation numbers of atoms add upto $0$.

In a polyatomic ion, oxidation number of atoms add up to the charge on the ion.

The oxidation number of monoatomic ions is the same as its charge.

Oxygen is usually in $-2$ oxidation state except in peroxides and in compounds with halogen.

Hydrogen is usually in $+1$ oxidation state except in metal hydrides.

Group 1 elements are always in $+1$ oxidation state and group 2 elements in $+2$.