Chapter 4, Problem 46P

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SOLVE ASAPThe line of action of force F₁ = 388 N is passing through point A(+2,+3,+1) towards B(+5,+5, +4), while that of force F₂ = 488 N is through point C(+3,+1,−1) towards D(-2, -3, -4). Use a right-handed coordinate system.a. Determine the moment of force F₁ about the origin.b. Determine the moment of force F2 about the origin. c. Determine the magnitude of the resultant moment of forces Fi and F₂ about segment OE. Point O is the origin and point E is at (+5,+5,-3).

3) The man in the figure pulls the rope tied at point A.It pulls with a force of F=150 N. According to thisthe force F exerted by the man as a cartesian vector.Write it down and determine its moment about point O.

Q4\ Determine the moment of the force about point 0. Neglect the thickness of the member. 50 N -100 mm- 60° 45° 200 mm -100 mm-

Determine the moment of the force about point O if F is 350N.

Determine the moment about point O in Cartesian vector. Given the magnitude force, F is 60N and unit vector BC, ugc={(2i-2j-k)}/3. F 1 m 2 m 1 m A 2 m O a. {0.67j-1.33k} N.m O b. {60j-120k} N.m O c. {j-2k} N.m O d. {40j-80k} N.m

Determine the moment of the force about point A as shown in the Figure below.

Y. -5 m 100 N 100 N -5 m 1. DETERMINE THE MOMENTS OF THE TWO FORCES ABOUT X, Y, AND Z AXES SHOWN IN THE FIGURE 3 m

Solve it correctly please.