PEARSON ETEXT ENGINEERING MECH & STATS
15th Edition
ISBN: 9780137514724
Author: HIBBELER
Publisher: PEARSON
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Given the Position vector
R= 2i -j+ 3k (m)
and the Force vector
F = i+j+k (kN)
Determine the angle in degrees between the two vectors.
Answer:
Determine the moment of the force about point O if F is 350N.
NO NEED SOLUTION
The given force in the figure passes through the origin and point A(5,-12,16). Its z-component is
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- Part A If F, = {115i - 125j + 90k) lb and F2 = {-220i + 280j + 120k} lb, determine the resultant moment produced by these forces about point O. Express the result as a Cartesian vector. (Figure 1) Enter the r, y and z components of the moment of force separated by commas. V AEO vec Mo = Ib - ft Figure < 1 of 1 Submit Previous Answers Request Answer < Return to Assignment Provide Feedback 4 ft 3 ftarrow_forwardGiven: F1={9 i - 9 j+ 10 k}lb F2={-10 i+10 j+ 10 k}lb Find: the Magnitude of the Resultant moment in (Ib.ft) generated by the forces about point O. 4 ft 5 ft 3 ftarrow_forward*FIND THE MOMENT OF EACH FORCE AROUND POINT B, AND FIND THE RESULTANT AND DIRECTION MOMENT OF ALL FORCES ABOUT Barrow_forward
- 8aarrow_forward2- Replace the effect of the forces, with the resultant Fv and the moment M at point D, if the force F1 acts at point A, F2 at point B and F3 at point C. A = (1,5; 1,5: 2), B = (1; 3,5; 1), C=(-1; 5,5; 0), D= (1; 1,5; -0,5), F, = (1003; - 20; 0)N, F, = (- 40; - 30; 15)N , F, = (0; -80; 120)N. F. A rA F, k iarrow_forwardDetermine the resultant moment of the forces acting about the x, y, and z axes. Suppose that F1=250N, F2=90N, F3=105N, and F4=310N.arrow_forward
- . In Figure 1-31, the moment of a certain force is 400 ft-lb counterclockwise about A. If the slope of this force is 3/2 and its moment about O is zero, determine the magnitude of the force. Also, if the line of action of the force pass through point B at (6', y), determine the y- component of point B? y 2' Figure 1-31arrow_forwardY. -5 m 100 N 100 N -5 m 1. DETERMINE THE MOMENTS OF THE TWO FORCES ABOUT X, Y, AND Z AXES SHOWN IN THE FIGURE 3 marrow_forwardThe line of action of force F1 = 344 N is passing through point A(+2,+3,+1) towards B(+5,+5,+4), while that of force F2 = 422 N is through point C(+3,+1, –1) towards D(–2, –3, –4). Use a right-handed coordinate system. Determine the moment of force F1 about the origin, the moment of force F2 about the origin, the magnitude of the resultant moment of forces F1 and F2 about segment OE. Point O is the origin and point E is at (+5,+5,–3). i]k,arrow_forward
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