
Concept explainers
(a)
Interpretation:
R or S and E or Z configuration has to be assigned for the given compound.
Concept introduction:
The carbon-carbon double bond containing organic compounds are is known as alkenes or olefins, they are one of the class of hydrocarbon.
Cis–trans isomerism (or) geometric isomerism or configurational isomerism:
The two similar groups (or higher priority groups) are in same side in double bond of alkenes is called as cis isomer (or Z-isomer). Two similar groups (or higher priority groups) are opposite side in double bond of alkenes is called as trans isomer (or E-isomer).
Example:
(b)
Interpretation:
The systematic name should be given for the compound.
Concept introduction:
R and S nomenclature: it is used to assign the molecule using CIP rules.
The CIP rules are as follows:
Select the chiral carbon and assign the numbers according to the decreasing
If the numbering follows clockwise direction then the molecule is termed as R and if it follows anti-clockwise direction then molecule is termed as S.
(c)
Interpretation:
R or S and E or Z configuration has to be assigned for the given compound.
Concept introduction:
Cis–trans isomerism (or) geometric isomerism or configurational isomerism:
The two similar groups (or higher priority groups) are in same side in double bond of alkenes is called as cis isomer (or Z-isomer). Two similar groups (or higher priority groups) are opposite side in double bond of alkenes is called as trans isomer (or E-isomer).
Example:
(c)
Interpretation:
The systematic name should be given for the compound.
Concept introduction:
R and S nomenclature: it is used to assign the molecule using CIP rules.
The CIP rules are as follows:
Select the chiral carbon and assign the numbers according to the decreasing atomic mass of atoms attached to it.
If the numbering follows clockwise direction then the molecule is termed as R and if it follows anti-clockwise direction then molecule is termed as S.

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Chapter 4 Solutions
Essential Organic Chemistry (3rd Edition)
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- Identify priority of the substituents: CH3arrow_forwardHow many chiral carbons are in the molecule? OH F CI Brarrow_forwardA mixture of three compounds Phen-A, Acet-B and Rin-C was analyzed using TLC with 1:9 ethanol: hexane as the mobile phase. The TLC plate showed three spots of R, 0.1 and 0.2 and 0.3. Which of the three compounds (Phen-A; Acet-B or Rin-C) would have the highest (Blank 1), middle (Blank 2) and lowest (Blank 3) spot respectively? 0 CH: 0 CH, 0 H.C OH H.CN OH Acet-B Rin-C phen-A A A <arrow_forward
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