Chapter 4, Problem 4.61SP

Interpretation Introduction

Interpretation:

The method of preparing 250 mL of 0.150 M chloride ion solution from 3.0 M ${\text{CaCl}}_{\text{2}}$ solution needs to be explained.

Concept introduction:

The molarity or concentration of the solution can be calculated as follows:

$M=\frac{n}{V\left(L\right)}$

Here, n is number of moles and V is volume of solution in L.

The number of moles can be calculated from mass and molar mass as follows:

$n=\frac{m}{M}$

Here, m is mass and M is molar mass.