(a) Interpretation: The given chemical equation needs to be determined. H 3 MO 3 (aq) + MnO 4 - (aq) → H 3 MO 4 (aq) + Mn 2 + (aq) (in acid) Concept introduction: A chemical equation is known as the written symbolic illustration of the chemical reaction . On the left-hand side of the equation, a reactant is present and on the right-hand side, the product is present. Both of them are connected with an arrow leading from left to right. According to the law of conservation of mass, no atoms are destroyed and created within the chemical reaction, therefore the number of atoms on the product as well as on reactant should be balanced on both sides.
(a) Interpretation: The given chemical equation needs to be determined. H 3 MO 3 (aq) + MnO 4 - (aq) → H 3 MO 4 (aq) + Mn 2 + (aq) (in acid) Concept introduction: A chemical equation is known as the written symbolic illustration of the chemical reaction . On the left-hand side of the equation, a reactant is present and on the right-hand side, the product is present. Both of them are connected with an arrow leading from left to right. According to the law of conservation of mass, no atoms are destroyed and created within the chemical reaction, therefore the number of atoms on the product as well as on reactant should be balanced on both sides.
Solution Summary: The author explains that a chemical equation is the written symbolic illustration of the chemical reaction.
The given chemical equation needs to be determined.
H3MO3(aq) + MnO4-(aq) → H3MO4(aq) + Mn2+(aq) (in acid)
Concept introduction:
A chemical equation is known as the written symbolic illustration of the chemical reaction. On the left-hand side of the equation, a reactant is present and on the right-hand side, the product is present. Both of them are connected with an arrow leading from left to right. According to the law of conservation of mass, no atoms are destroyed and created within the chemical reaction, therefore the number of atoms on the product as well as on reactant should be balanced on both sides.
Interpretation Introduction
(b)
Interpretation:
The moles of oxide formed and the number of moles of semimetal in the initial 0.200 g sample needs to be determined.
Concept introduction:
The mass is related to the number of moles and molar mass as follows:
n=mM
Here, m is mass and M is molar mass.
Interpretation Introduction
(c)
Interpretation:
The semimetal M needs to be identified.
Concept introduction:
The mass is related to number of moles and molar mass as follows:
20. The Brusselator. This hypothetical system was first proposed by a group work-
ing in Brussels [see Prigogine and Lefever (1968)] in connection with spatially
nonuniform chemical patterns. Because certain steps involve trimolecular reac
tions, it is not a model of any real chemical system but rather a prototype that
has been studied extensively. The reaction steps are
A-X.
B+X-Y+D.
2X+ Y-3X,
X-E.
305
It is assumed that concentrations of A, B, D, and E are kept artificially con
stant so that only X and Y vary with time.
(a) Show that if all rate constants are chosen appropriately, the equations de
scribing a Brusselator are:
dt
A-(B+ 1)x + x²y,
dy
=Bx-x²y.
di
Problem 3. Provide a mechanism for the following transformation:
H₂SO A
Me.
Me
Me
Me
Me
You are trying to decide if there is a single reagent you can add that will make the following synthesis possible without any other major side products:
xi
1. ☑
2. H₂O
хе
i
Draw the missing reagent X you think will make this synthesis work in the drawing area below.
If there is no reagent that will make your desired product in good yield or without complications, just check the box under the drawing area and leave it blank.
Click and drag to start drawing a
structure.
There is no reagent that will make this synthesis work without complications.
: ☐
S
☐
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell