EBK COMPUTER SYSTEMS
3rd Edition
ISBN: 8220101459107
Author: O'HALLARON
Publisher: YUZU
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Chapter 4, Problem 4.59HW
Program Plan Intro
Cycles per element (CPE):
- The CPE denotes performance of program that helps in improving code.
- It helps to understand detailed level loop performance for an iterative program.
- It is appropriate for programs that use a repetitive computation.
- The processor’s activity sequencing is controlled by a clock that provides regular signal of some frequency.
Loop unrolling:
- It denotes a program transformation that would reduce count of iterations for a loop.
- It increases count of elements computed in each iteration.
- It reduces number of operations that is not dependent to program directly.
- It reduces count of operations in critical paths of overall computations.
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I need help to solve a simple problem using Grover’s algorithm, where the solution is not necessarily known beforehand. The problem is a 2×2 binary sudoku with two rules:
• No column may contain the same value twice.
• No row may contain the same value twice.
Each square in the sudoku is assigned to a variable as follows:
We want to design a quantum circuit that outputs a valid solution to this sudoku. While using Grover’s algorithm for this task is not necessarily practical, the goal is to demonstrate how classical decision problems can be converted into oracles for Grover’s algorithm.
Turning the Problem into a Circuit
To solve this, an oracle needs to be created that helps identify valid solutions. The first step is to construct a classical function within a quantum circuit that checks whether a given state satisfies the sudoku rules.
Since we need to check both columns and rows, there are four conditions to verify:
v0 ≠ v1 # Check top row
v2 ≠ v3 # Check bottom row…
I need help to solve a simple problem using Grover’s algorithm, where the solution is not necessarily known beforehand. The problem is a 2×2 binary sudoku with two rules:
• No column may contain the same value twice.
• No row may contain the same value twice.
Each square in the sudoku is assigned to a variable as follows:
We want to design a quantum circuit that outputs a valid solution to this sudoku. While using Grover’s algorithm for this task is not necessarily practical, the goal is to demonstrate how classical decision problems can be converted into oracles for Grover’s algorithm.
Turning the Problem into a Circuit
To solve this, an oracle needs to be created that helps identify valid solutions. The first step is to construct a classical function within a quantum circuit that checks whether a given state satisfies the sudoku rules.
Since we need to check both columns and rows, there are four conditions to verify:
v0 ≠ v1 # Check top row
v2 ≠ v3 # Check bottom row…
Don't use ai to answer I will report you answer
Chapter 4 Solutions
EBK COMPUTER SYSTEMS
Ch. 4.1 - Prob. 4.1PPCh. 4.1 - Prob. 4.2PPCh. 4.1 - Prob. 4.3PPCh. 4.1 - Prob. 4.4PPCh. 4.1 - Prob. 4.5PPCh. 4.1 - Prob. 4.6PPCh. 4.1 - Prob. 4.7PPCh. 4.1 - Prob. 4.8PPCh. 4.2 - Practice Problem 4.9 (solution page 484) Write an...Ch. 4.2 - Prob. 4.10PP
Ch. 4.2 - Prob. 4.11PPCh. 4.2 - Prob. 4.12PPCh. 4.3 - Prob. 4.13PPCh. 4.3 - Prob. 4.14PPCh. 4.3 - Prob. 4.15PPCh. 4.3 - Prob. 4.16PPCh. 4.3 - Prob. 4.17PPCh. 4.3 - Prob. 4.18PPCh. 4.3 - Prob. 4.19PPCh. 4.3 - Prob. 4.20PPCh. 4.3 - Prob. 4.21PPCh. 4.3 - Prob. 4.22PPCh. 4.3 - Prob. 4.23PPCh. 4.3 - Prob. 4.24PPCh. 4.3 - Prob. 4.25PPCh. 4.3 - Prob. 4.26PPCh. 4.3 - Prob. 4.27PPCh. 4.4 - Prob. 4.28PPCh. 4.4 - Prob. 4.29PPCh. 4.5 - Prob. 4.30PPCh. 4.5 - Prob. 4.31PPCh. 4.5 - Prob. 4.32PPCh. 4.5 - Prob. 4.33PPCh. 4.5 - Prob. 4.34PPCh. 4.5 - Prob. 4.35PPCh. 4.5 - Prob. 4.36PPCh. 4.5 - Prob. 4.37PPCh. 4.5 - Prob. 4.38PPCh. 4.5 - Prob. 4.39PPCh. 4.5 - Prob. 4.40PPCh. 4.5 - Prob. 4.41PPCh. 4.5 - Prob. 4.42PPCh. 4.5 - Prob. 4.43PPCh. 4.5 - Prob. 4.44PPCh. 4 - Prob. 4.45HWCh. 4 - Prob. 4.46HWCh. 4 - Prob. 4.47HWCh. 4 - Prob. 4.48HWCh. 4 - Modify the code you wrote for Problem 4.47 to...Ch. 4 - In Section 3.6.8, we saw that a common way to...Ch. 4 - Prob. 4.51HWCh. 4 - The file seq-full.hcl contains the HCL description...Ch. 4 - Prob. 4.53HWCh. 4 - The file pie=full. hcl contains a copy of the PIPE...Ch. 4 - Prob. 4.55HWCh. 4 - Prob. 4.56HWCh. 4 - Prob. 4.57HWCh. 4 - Our pipelined design is a bit unrealistic in that...Ch. 4 - Prob. 4.59HW
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