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Concept explainers
(a)
Interpretation:
The number of valence electrons and the type of multiple bonds present if the compound is having a multiple bonds has to be determined for
Concept introduction:
Covalent bonds are formed by sharing of electrons between atoms.
The valence electrons of Carbon are 4 electrons (requires 4 electrons to achieve octet).
The valence electrons of Oxygen are 6 electrons (requires 2 electrons to achieve octet).
The valence electrons of Hydrogen are 1 electron.
The valence electrons of Nitrogen are 5 electrons.
The sharing of one electron from two atoms constitutes a single bond between the two atoms. The sharing of two electrons from two atoms constitutes a double bond between the two atoms
(b)
Interpretation:
The number of valence electrons and the type of multiple bonds present if the compound is having a multiple bond has to be determined for
Concept introduction:
Covalent bonds are formed by sharing of electrons between atoms.
The valence electrons of Oxygen are 6 electrons (requires 2 electrons to achieve octet).
The valence electrons of Chlorine are 7 electrons.
The valence electrons of Nitrogen are 5 electrons.
The sharing of one electron from two atoms constitutes a single bond between the two atoms. The sharing of two electrons from two atoms constitutes a double bond between the two atoms
(c)
Interpretation:
The number of valence electrons and the type of multiple bonds present if the compound is having a multiple bond has to be determined for compound
Concept introduction:
Covalent bonds are formed by sharing of electrons between atoms.
The valence electrons of Carbon are 4 electrons (requires 4 electrons to achieve octet).
The valence electrons of Oxygen are 6 electrons (requires 2 electrons to achieve octet).
The valence electrons of Hydrogen are 1 electron.
The sharing of one electron from two atoms constitutes a single bond between the two atoms. The sharing of two electrons from two atoms constitutes a double bond between the two atoms
(d)
Interpretation:
The number of valence electrons and the type of multiple bonds present if the compound is having a multiple bond has to be determined for
Concept introduction:
Covalent bonds are formed by sharing of electrons between atoms.
The valence electrons of Fluorine are 7 electrons (requires 1 electrons to achieve octet).
The valence electrons of Oxygen are 6 electrons (requires 2 electrons to achieve octet).
The sharing of one electron from two atoms constitutes a single bond between the two atoms. The sharing of two electrons from two atoms constitutes a double bond between the two atoms
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Chapter 4 Solutions
FUND.OF GEN CHEM CHAP 1-13 W/ACCESS
- Draw the product of this reaction. Ignore inorganic byproducts. H H ⚫OH HO- -H H- -OH H- -OH CH2OH Ag*, NH4OH, H2O Draw Fischer Projectionarrow_forwardDraw the product of this reaction. Ignore inorganic byproducts. H₂O -OH H ⚫OH HO H HO- CH2OH Cu2+ Draw Fischer Projectionarrow_forwardDraw the product of this reaction. Ignore inorganic byproducts. H、 H -OH H ⚫OH H -OH CH2OH Fehlings' solution ⑤ Draw Fischer Projectionarrow_forward
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- Draw the product of this reaction. Ignore inorganic byproducts. Но сво HO H HO H H OH H -OH CH2OH H2 Pd Draw Fischer Projectionarrow_forwardDraw the Haworth projection for Gulose-ẞ-1,6-sorbose and answer the following questions. (Gulose will be in the pyranose form and Sorbose will be in the furanose form) a. Label the reducing and nonreducing ends of the disaccharide b. Label the glycosidic bond c. Circle the anomeric carbons and label them as hemiacetals or acetals. d. Can this disaccharide undergo mutarotation?arrow_forwardDraw the product of the reaction below. Ignore inorganic byproducts. H OH HO HO HO ·H H OH H OH excess CH3CH2I KOHarrow_forward
- Draw the Haworth structures for the following: a. α-D-Gulopyranose b. ẞ-D-Sorbofuranose c. The two possible isomers of a-D-altrose (furanose and pyranose forms)arrow_forwardDraw the product of this reaction. Ignore inorganic byproducts. HO H ⚫OH HO- ∙H H- -OH H ⚫OH CH2OH HNO3, H2Oarrow_forwardDraw the product of the reaction below. Ignore inorganic byproducts. HO CH2OH OH OH OH excess CHзI Ag2Oarrow_forward
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