PRINT COMPANION ENGINEER THERMO
9th Edition
ISBN: 9781119778011
Author: MORAN
Publisher: WILEY
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Chapter 4, Problem 4.27CU
To determine
Prove that, at a steady-state, mass entering the system is equal to mass leaving the system.
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Students have asked these similar questions
3.
Steam enters a diffuser operating at steady state with a pressure of 3 bar, a temperature of
200 °C, and a velocity of 100 m/s. Steam exits the diffuser as a saturated vapor, with a
velocity of 10 m/s. Heat transfer occurs from the steam to its surroundings at a rate of 200
kJ/kg of steam flowing. Neglecting potential energy effects, determine the exit pressure,
in bar. (Note: 1 kJ/kg-1000 m²/s²)
(1)
(2)
Quick handwritten,no gpt.
TABLE A-3
Qe
Pressure Conversions: Properties of Saturated Water (Liquid-Vapor): Pressure Table
1 bar -0.1 MPa
Specific Volume
m/kg
Internal Energy
10 kPa
kj/kg
Enthalpy
kj/kg
Entropy
kj/kg K
Sat.
Sat.
Sat.
Press.
bar
0.04 28.96
0.06 36.16
Temp.
"C
Liquid
Vapor
Liquid
Sat.
Vapor
Sat.
By x10
Evap. Vapor
he
1.0040 34.800
1.0064 23.739
0.08 41.51
1.0084 18.103
0.10
45.81
1.0102
14.674
0.20
60.06
1.0172
7.649
121.45 2415.2
151.53 2425.0
173.87 2432.2
191.82 2437.9
251.38 2456.7
Sat.
Liquid
hi
his
121.46 2432.9 2554.4 0.4226 8.4746
151.53 2415.9 2567.4 0.5210…
The system shown is at steady state, steady flow. At inlet 1, the rates of kinetic
energy, potential energy and enthalpy entering the system are: KE1 = 0.10 kW, PE1
%3D
0.22 kW, and H1 = 27.0 kW. At inlet 2, the rates are: KE2 = 0.23 kW, PE2 = 0.18 kW,
and H2 = 18.0 kVW. At exit 3, the rates are: KE3 = 0.52 kW, PE3 = 0.28 kW, and H3 =
7.0 kW. If the system gives up 5.0 kW of heat to the surroundings, what is the rate of
work transfer of the system? Express the answer in kw.
%3D
KE3
PE3
1
KE.
РЕ
H.
KE2
PE2
На
Control volume
boundary
Air expands through a turbine operating at steady state. At the inlet, p1 = 150 lbf/in.2, T1 = 1400°R, and at the exit, p2 = 14.8 lbf/in.2, T2 = 800°R. The mass flow rate of air entering the turbine is 5 lb/s, and 65,000 Btu/h of energy is rejected by heat transfer.Neglecting kinetic and potential energy effects, determine the power developed, in hp.
Chapter 4 Solutions
PRINT COMPANION ENGINEER THERMO
Ch. 4 - Prob. 4.1ECh. 4 - Prob. 4.2ECh. 4 - Prob. 4.3ECh. 4 - Prob. 4.4ECh. 4 - Prob. 4.5ECh. 4 - Prob. 4.6ECh. 4 - Prob. 4.7ECh. 4 - Prob. 4.8ECh. 4 - Prob. 4.9ECh. 4 - Prob. 4.10E
Ch. 4 - Prob. 4.11ECh. 4 - Prob. 4.12ECh. 4 - Prob. 4.13ECh. 4 - Prob. 4.14ECh. 4 - Prob. 4.15ECh. 4 - Prob. 4.1CUCh. 4 - Prob. 4.2CUCh. 4 - Prob. 4.3CUCh. 4 - Prob. 4.4CUCh. 4 - Prob. 4.5CUCh. 4 - Prob. 4.6CUCh. 4 - Prob. 4.7CUCh. 4 - Prob. 4.8CUCh. 4 - Prob. 4.9CUCh. 4 - Prob. 4.10CUCh. 4 - Prob. 4.11CUCh. 4 - Prob. 4.12CUCh. 4 - Prob. 4.13CUCh. 4 - Prob. 4.14CUCh. 4 - Prob. 4.15CUCh. 4 - Prob. 4.16CUCh. 4 - Prob. 4.17CUCh. 4 - Prob. 4.18CUCh. 4 - Prob. 4.19CUCh. 4 - Prob. 4.20CUCh. 4 - Prob. 4.21CUCh. 4 - Prob. 4.22CUCh. 4 - Prob. 4.23CUCh. 4 - Prob. 4.24CUCh. 4 - Prob. 4.25CUCh. 4 - Prob. 4.26CUCh. 4 - Prob. 4.27CUCh. 4 - Prob. 4.28CUCh. 4 - Prob. 4.29CUCh. 4 - Prob. 4.30CUCh. 4 - Prob. 4.31CUCh. 4 - Prob. 4.32CUCh. 4 - Prob. 4.33CUCh. 4 - Prob. 4.34CUCh. 4 - Prob. 4.35CUCh. 4 - Prob. 4.36CUCh. 4 - Prob. 4.37CUCh. 4 - Prob. 4.38CUCh. 4 - Prob. 4.39CUCh. 4 - Prob. 4.40CUCh. 4 - Prob. 4.41CUCh. 4 - Prob. 4.42CUCh. 4 - Prob. 4.43CUCh. 4 - Prob. 4.44CUCh. 4 - Prob. 4.45CUCh. 4 - Prob. 4.46CUCh. 4 - Prob. 4.47CUCh. 4 - Prob. 4.48CUCh. 4 - Prob. 4.49CUCh. 4 - Prob. 4.50CUCh. 4 - Prob. 4.51CUCh. 4 - Prob. 4.1PCh. 4 - Prob. 4.2PCh. 4 - Prob. 4.3PCh. 4 - Prob. 4.4PCh. 4 - Prob. 4.5PCh. 4 - Prob. 4.6PCh. 4 - Prob. 4.7PCh. 4 - Prob. 4.8PCh. 4 - Prob. 4.9PCh. 4 - Prob. 4.10PCh. 4 - Prob. 4.11PCh. 4 - Prob. 4.12PCh. 4 - Prob. 4.13PCh. 4 - Prob. 4.14PCh. 4 - Prob. 4.15PCh. 4 - Prob. 4.16PCh. 4 - Prob. 4.17PCh. 4 - Prob. 4.18PCh. 4 - Prob. 4.19PCh. 4 - Prob. 4.20PCh. 4 - Prob. 4.21PCh. 4 - Prob. 4.22PCh. 4 - Prob. 4.23PCh. 4 - Prob. 4.24PCh. 4 - Prob. 4.25PCh. 4 - Prob. 4.26PCh. 4 - Prob. 4.27PCh. 4 - Prob. 4.28PCh. 4 - Prob. 4.29PCh. 4 - Prob. 4.30PCh. 4 - Prob. 4.31PCh. 4 - Prob. 4.32PCh. 4 - Prob. 4.33PCh. 4 - Prob. 4.34PCh. 4 - Prob. 4.35PCh. 4 - Prob. 4.36PCh. 4 - Prob. 4.37PCh. 4 - Prob. 4.38PCh. 4 - Prob. 4.39PCh. 4 - Prob. 4.40PCh. 4 - Prob. 4.41PCh. 4 - Prob. 4.42PCh. 4 - Prob. 4.43PCh. 4 - Prob. 4.44PCh. 4 - Prob. 4.45PCh. 4 - Prob. 4.46PCh. 4 - Prob. 4.47PCh. 4 - Prob. 4.48PCh. 4 - Prob. 4.49PCh. 4 - Prob. 4.50PCh. 4 - Prob. 4.51PCh. 4 - Prob. 4.52PCh. 4 - Prob. 4.53PCh. 4 - Prob. 4.54PCh. 4 - Prob. 4.55PCh. 4 - Prob. 4.56PCh. 4 - Prob. 4.57PCh. 4 - Prob. 4.58PCh. 4 - Prob. 4.59PCh. 4 - Prob. 4.60PCh. 4 - Prob. 4.61PCh. 4 - Prob. 4.62PCh. 4 - Prob. 4.63PCh. 4 - Prob. 4.64PCh. 4 - Prob. 4.65PCh. 4 - Prob. 4.66PCh. 4 - Prob. 4.67PCh. 4 - Prob. 4.68PCh. 4 - Prob. 4.69PCh. 4 - Prob. 4.70PCh. 4 - Prob. 4.71PCh. 4 - Prob. 4.72PCh. 4 - Prob. 4.73PCh. 4 - Prob. 4.74PCh. 4 - Prob. 4.75PCh. 4 - Prob. 4.76PCh. 4 - Prob. 4.77PCh. 4 - Prob. 4.78PCh. 4 - Prob. 4.79PCh. 4 - Prob. 4.80PCh. 4 - Prob. 4.81PCh. 4 - Prob. 4.82PCh. 4 - Prob. 4.83PCh. 4 - Prob. 4.84PCh. 4 - Prob. 4.85PCh. 4 - Prob. 4.86PCh. 4 - Prob. 4.87PCh. 4 - Prob. 4.88P
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- Air expands through a turbine operating at steady state. At the inlet, p₁= 150 lbf/in.², T₁ = 1400°R, and at the exit, p2 = 14.8 lbf/in.², T₂ = 900°R. The mass flow rate of air entering the turbine is 17 lb/s, and 65,000 Btu/h of energy is rejected by heat transfer. Neglecting kinetic and potential energy effects, determine the power developed, in hp. Wcv = i hparrow_forwardAir expands through a turbine operating at steady state. At the inlet, p₁ = 150 lbf/in.², T₁ = 1400°R, and at the exit, p2 = 14.8 lbf/in.², T2 = 800°R. The mass flow rate of air entering the turbine is 17 lb/s, and 65,000 Btu/h of energy is rejected by heat transfer. Neglecting kinetic and potential energy effects, determine the power developed, in hp. Wev = i 6396.24 hparrow_forwardAir expands through a turbine operating at steady state. At the inlet, p1 = 150 lbf/in.2, T1 = 1400°R, and at the exit, p2 = 14.8 lbf/in.2, T2 = 800°R. The mass flow rate of air entering the turbine is 11 lb/s, and 65,000 Btu/h of energy is rejected by heat transfer.Neglecting kinetic and potential energy effects, determine the power developed, in hp.arrow_forward
- 9) The figure shows isentropic expansion through a turbine at steady state. The area on the diagram that represents the work developed by the turbine per unit mass flowing is area enclosed by the points 1-2-e-d-1. 1-2-e-c-a-1. 1-2-b-a-1.arrow_forwardLiquid octane enters an internal combustion engine operating at steady state with a mass flow rate of 0.004 lb/sand is mixed with the theoretical amount of air. The rate of heat transfer is 22.22 BTU/s. If the density of octane is 5.88 lb/gal, how many gallons of fuel would be used in 2 h of continuous operation of the engine?arrow_forwardAir expands through a turbine operating at steady state. At the inlet, p₁ = 150 lbf/in.², T₁ = 1400°R, and at the exit, p₂ = 14.8 lbf/in.2², T₂ = 800°R. The mass flow rate of air entering the turbine is 17 lb/s, and 65,000 Btu/h of energy is rejected by heat transfer. Neglecting kinetic and potential energy effects, determine the power developed, in hp. W cv = i hparrow_forward
- Air expands through a turbine operating at steady state. At the inlet, p1 = 150 lbf/in.?, T1 = 1400°R, and at the exit, p2 = 14.8 lbf/in.?, T2 = 900°R. The mass flow rate of air entering the turbine is 11 lb/s, and 65,000 Btu/h of energy is rejected by heat transfer. Neglecting kinetic and potential energy effects, determine the power developed, in hp. Wey = i hp cvarrow_forwardAn oil pump operating at steady state delivers oil at a rate of 12 lb/s through a 1-in.-diameter exit pipe. The oil, which can be modeled as incompressible, has a density of 85 lb/ft³ and experiences a pressure rise from inlet to exit of 40 lbf/in². There is no significant elevation difference between inlet and exit, and the inlet kinetic energy is negligible. Heat transfer between the pump and its surroundings is negligible, and there is no significant change in temperature as the oil passes through the pump. Determine the velocity of the oil at the exit of the pump, in ft/s, and the power required for the pump, in hp.arrow_forward12arrow_forward
- Liquid flows at steady state at a rate of 2 lb/s through a pump, which operates to raise the elevation of the liquid 100 ft from control volume inlet to exit. The liquid specific enthalpy at the inlet is 40.09 Btu/lb and at the exit is 40.94 Btu/lb. The pump requires 3 Btu/s of power to operate. If kinetic energy effects are negligible and gravitational acceleration is 32.174 ft/s2, the heat transfer rate associated with this steady state process is most closely: A) 2.02 Btu/s from the liquid to the surroundings. B) 3.98 Btu/s from the surroundings to the liquid. C) 4.96 Btu/s from the surroundings to the liquid. D) 1.04 Btu/s from the liquid to the surroundings.arrow_forward4.10arrow_forwardSteam enters a turbine operating at steady state at 750°F and 450 lbf/in² and leaves as a saturated vapor at 0.8 lbf/in². The turbine develops 12,000 hp, and heat transfer from the turbine to the surroundings occurs at a rate of 2 x 106 Btu/h. Neglect kinetic and potential energy changes from inlet to exit. Determine the exit temperature, in °F, and the volumetric flow rate of the steam at the inlet, in ft³/s. Step 1 Determine the exit temperature, in °F. T₂ = i °F.arrow_forward
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