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(Another Dangling-else Problem) Based on the dangling-else discussion in Exercise 4.23, modify the following code to produce the output shown. Use proper indentation techniques. You must not make any additional changes other than inserting braces. We eliminated the indentation from the following code to make the problem more challenging. [Note: It’s possible that no modification is necessary.]
if(y = = 8) if (x = = 5) cout << “@@@@@” << endl ; else cout << ”#####” << endl ; cout << ”$$$$$” << endl ; cout << “&&&&&” << endl ; a) Assuming x = 5 and y = 8, the following output is produced. @@@@@ $$$$$$ &&&&& b) Assuming x = 5 and y = 8, the following output is produced. @@@@@ c) Assuming x =5 and y = 8, the following output is produced. @@@@@ &&&&& d) Assuming x = 5 and y = 7, the following output is produced. [Note: The last three out-put statements after the else are all part of a block.] ##### $$$$$ &&&&&
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- ( MindTap - Cenage )Example 5-6 implements the Number Guessing Game program. If the guessed number is not correct, the program outputs a message indicating whether the guess is low or high. Modify the program as follows: Suppose that the variables num and guess are as declared in Example 5-6 and diff is an int variable. Let diff = the absolute value of (num - guess). If diff is 0, then guess is correct and the program outputs a message indicating that the user guessed the correct number. Suppose diff is not 0. Then the program outputs the message as follows: If diff is greater than or equal to 50, the program outputs the message indicating that the guess is very high (if guess is greater than num) or very low (if guess is less than num). If diff is greater than or equal to 30 and less than 50, the program outputs the message indicating that the guess is high (if guess is greater than num) or low (if guess is less than num). If diff is greater than or equal to 15 and less than 30, the…arrow_forwardUrgent help needed!#!arrow_forward(Algebra: solve 2 x 2 linear equations) You can use Cramer's rule to solve the following 2 x 2 system of linear equation: ax + by = e ed – bf af- ec ad - bc cx + dy = f ad – bc y = Write a program that prompts the user to enter a and f and display the result. If ad - bc is 0 b, c, d , e, , report that The equation has no solution.arrow_forward
- C++ for Engineers and ScientistsComputer ScienceISBN:9781133187844Author:Bronson, Gary J.Publisher:Course Technology PtrC++ Programming: From Problem Analysis to Program...Computer ScienceISBN:9781337102087Author:D. S. MalikPublisher:Cengage Learning