Solid Waste Engineering
3rd Edition
ISBN: 9781305635203
Author: Worrell, William A.
Publisher: Cengage Learning,
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 4, Problem 4.17P
To determine
Grate spacing and horsepower required by the shredder
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
the Nominal Maximum aggregate Size (N.M.S) for the aggregate gradation shown below is equal to ………………
1. Three samples of aggregates are sieved to obtain the grading curve. A set of different sieves is
stacked with the coarsest mesh at the top. The aggregate is then placed in the top sieve and the
stack is placed in a sieve shaker. The raw data is as follows:
Sieve size (mm)
19
9.5
4.75
2.36
1.18
0.6
0.3
0.15
Pan
Mass of sieve (g)
670
620
620
570
570
520
520
520
490
For each sample:
Plot the grading curve.
a.
b.
Identify the type of gradation.
c. Determine the fineness modulus.
Mass of sieve + aggregates retained (g)
Sample B
mass of the empty measure
mass of measure + water
Sample A
670
770
820
740
720
770
720
570
525
mass of measure + rodded aggregates
mass of measure + loose aggregates
670
1820
620
570
570
670
720
620
544
2. The rodded and loose bulk density of an aggregate sample is to be determined. The following
are acquired during the experiment:
- 12.15 kg
- 27.15 kg
- 34.60 kg
- 25.16 kg
Sample C
670
620
620
670
770
720
620
620
506
Can you answer please?
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.Similar questions
- Aggregate from three sources having bulk specific gravities of 2.90, 2.70, and 2.60 was blended at a ratio of 60:30:10 by weight, respectively. What is the bulk specific gravity of the aggregate bled? Select one: O a. 2.87 O b. 2.81 O c. 2.75 O d. 2.65arrow_forwardList the given and required. Box the final answer.arrow_forwardAn aggregate sample was collected in a container and weighed as 528.7 g. The sample was oven dried and theoven dry weight was measured as 506.4 g. If the empty weight of the container was 79.6 g, determine the MC of theaggregatesarrow_forward
- 7. Make a spread sheet blend template program to perform a blend gradation analysis for up to four stockpiles with the ability to produce automatically semilog or power 0.45 gradation charts. Use the table to demonstrate the template, and calculate the fineness modulus for the aggregate D. Aggregate Blend Percent (%) Sieve size (mm) 37.5 25 19 12.5 9.5 4.75 2.36 1.18 0.60 0.30 0.15 0.075 A 20 100 100 95 89 70 10 2 N|N 2 2 2 2 2 B 25 100 100 100 100 82 55 15 55 32 2 1 с 25 Percent Passing 100 100 100 100 100 100 69 55 35 22 15 6 D 30 100 100 100 100 100 100 86 54 34 25 14 5arrow_forward1. Why do you think there is a need to agitate the aggregates inside the cylinder mold by rodding? 2. Determine the unit weight of the aggregates from the video. a. Dry Loose Unit Weight of the Fine Aggregate b. Dry Rodded Unit Weight of the Fine Aggregate c. Dry Loose Unit Weight of the Coarse Aggregate d. Dry Rodded Unit Weight of the Coarse Aggregate 3. A coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained. a. Volume of Bucket = 0.0094m³ %3D b. Weight of empty bucket = 8,391 g c. Weight of bucket filled with dry rodded coarse aggregate = 25,355 g %3D Calculate the dry-rodded unit weight. 4. Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained. a. Volume of Bucket = 0.0142m³ %3D b. Weight of empty bucket = 9,207 g c. Weight of bucket filled with dry rodded coarse aggregate: i. Trial 1= 34,745 g ii. Trial 2 = 34,065 g…arrow_forwardI want the solution in less than 15 minutesarrow_forward
- PLease answer the question in the picture please, show all of your work please and post pictures of your work, Do not type it!arrow_forwardthe Nominal Maximum aggregate Size (N.M.S) for the aggregate gradation shown below is equal to Sieve size Passing % 3/4 inch 100 1/2 inch 3/8 inch 99 89 No.4 72 No.8 65 No.30 22 No.200 Your answer 4-arrow_forwardAnswer 5.32arrow_forward
- can you answer please?arrow_forwardFor Sample A: -Plot the grading curve. -Identify the type of gradation. -Determine the fineness modulus.arrow_forwardCoarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained: Volume of bucket ½ ft3 Weight of empty bucket Weight of bucket filled with dry rodded coarse aggregate 20.3 lb Trial 1 = 69.6 lb Trial 2 = 68.2 lb Trial 3 = 71.6 lb a. Calculate the average dry-rodded unit weight b. If the bulk dry specific gravity of the aggregate is 2.620, calculate the per- cent voids between aggregate particles for each trial.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Solid Waste EngineeringCivil EngineeringISBN:9781305635203Author:Worrell, William A.Publisher:Cengage Learning,
Solid Waste Engineering
Civil Engineering
ISBN:9781305635203
Author:Worrell, William A.
Publisher:Cengage Learning,