(a) Interpretation: The given chemical equation needs to be determined. H 3 MO 3 (aq) + MnO 4 - (aq) → H 3 MO 4 (aq) + Mn 2 + (aq) (in acid) Concept introduction: A chemical equation is known as the written symbolic illustration of the chemical reaction . On the left-hand side of the equation, a reactant is present and on the right-hand side, the product is present. Both of them are connected with an arrow leading from left to right. According to the law of conservation of mass, no atoms are destroyed and created within the chemical reaction, therefore the number of atoms on the product as well as on reactant should be balanced on both sides.
(a) Interpretation: The given chemical equation needs to be determined. H 3 MO 3 (aq) + MnO 4 - (aq) → H 3 MO 4 (aq) + Mn 2 + (aq) (in acid) Concept introduction: A chemical equation is known as the written symbolic illustration of the chemical reaction . On the left-hand side of the equation, a reactant is present and on the right-hand side, the product is present. Both of them are connected with an arrow leading from left to right. According to the law of conservation of mass, no atoms are destroyed and created within the chemical reaction, therefore the number of atoms on the product as well as on reactant should be balanced on both sides.
Solution Summary: The author explains that a chemical equation is the written symbolic illustration of the chemical reaction.
The given chemical equation needs to be determined.
H3MO3(aq) + MnO4-(aq) → H3MO4(aq) + Mn2+(aq) (in acid)
Concept introduction:
A chemical equation is known as the written symbolic illustration of the chemical reaction. On the left-hand side of the equation, a reactant is present and on the right-hand side, the product is present. Both of them are connected with an arrow leading from left to right. According to the law of conservation of mass, no atoms are destroyed and created within the chemical reaction, therefore the number of atoms on the product as well as on reactant should be balanced on both sides.
Interpretation Introduction
(b)
Interpretation:
The moles of oxide formed and the number of moles of semimetal in the initial 0.200 g sample needs to be determined.
Concept introduction:
The mass is related to the number of moles and molar mass as follows:
n=mM
Here, m is mass and M is molar mass.
Interpretation Introduction
(c)
Interpretation:
The semimetal M needs to be identified.
Concept introduction:
The mass is related to number of moles and molar mass as follows:
we were assigned to dilute 900ppm
in to 18ppm by using only 250ml vol
flask. firstly we did calc and convert
900ppm to 0.9 ppm to dilute in 1 liter.
to begin the experiment we took
0,225g of kmno4 and dissolved in to
250 vol flask. then further we took 10
ml sample sol and dissolved in to 100
ml vol flask and put it in to a
spectrometer and got value of 0.145A
.
upon further calc we got v2 as 50ml
. need to find DF, % error (expval and
accptVal), molarity, molality. please
write the whole report. thank you
The format, tables, introduction,
procedure and observation, result,
calculations, discussion and
conclusion
Q5. Predict the organic product(s) for the following transformations. If no reaction will take place
(or the reaction is not synthetically useful), write "N.R.". Determine what type of transition state
is present for each reaction (think Hammond Postulate).
I
Br₂
CH3
F2, light
CH3
Heat
CH3
F₂
Heat
Br2, light
12, light
CH3
Cl2, light
No
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell