Chapter 4, Problem 4.110EP

(a)

Interpretation Introduction

Interpretation:

The following table of chemical formulas for polyatomic ion containing ionic compounds is to be filled.

  $\begin{array}{ccccc}& {\text{OH}}^{\text{-}}& {\text{PO}}_{\text{4}}^{\text{3-}}& {\text{CO}}_{\text{3}}^{\text{2-}}& {\text{HSO}}_{\text{4}}^{\text{-}}\\ {\text{Cu}}^{\text{2+}}& & & & \end{array}$

Concept Introduction:

Chemical formulas and names for ionic compounds containing polyatomic ions:

Ionic compounds containing positive and negative charges present must add to zero.

If more than one polyatomic ion is present in a compound, the chemical formula can be written as a polyatomic ion is enclose in parentheses and a subscript, placed outside of the parentheses.  Example- ${\text{Fe(OH)}}_{\text{3}}$.

Sometimes same element is present in two different locations.  For example, ${\text{NH}}_{\text{4}}{\text{NO}}_{\text{3}}$- in this chemical formula “N” is present in two different locations as ${\text{NH}}_{\text{4}}^{\text{+}}{\text{ and NO}}_{\text{3}}^{\text{-}}$ ions.

Answer to Problem 4.110EP

The complete table as shown below:

  $\begin{array}{ccccc}& {\text{OH}}^{\text{-}}& {\text{PO}}_{\text{4}}^{\text{3-}}& {\text{CO}}_{\text{3}}^{\text{2-}}& {\text{HSO}}_{\text{4}}^{\text{-}}\\ {\text{Cu}}^{\text{2+}}& {\text{Cu(OH)}}_{\text{2}}& {\text{Cu}}_{\text{3}}{{\text{(PO}}_{\text{4}}\text{)}}_{\text{2}}& {\text{CuCO}}_{\text{3}}& {\text{Cu(HSO}}_{\text{4}}{\text{)}}_{\text{2}}\end{array}$

Explanation of Solution

The given two ions are ${\text{Cu}}^{\text{2+}}$ and ${\text{OH}}^{\text{-}}$.

Two hydroxide ions (1- charge) are required to balance the charge on one copper ion (2+ charge).  Hence, the chemical formula of the compound is ${\text{Cu(OH)}}_{\text{2}}$.

The given two ions are ${\text{Cu}}^{\text{2+}}$ and ${\text{PO}}_{\text{4}}^{\text{3-}}$.

Two phosphate ions (3- charge) are required to balance the charge on three copper ions (2+ charge).  Hence, the chemical formula of the compound is ${\text{Cu}}_{\text{3}}{{\text{(PO}}_{\text{4}}\text{)}}_{\text{2}}$.

The given two ions are ${\text{Cu}}^{\text{2+}}$ and ${\text{CO}}_{\text{3}}^{\text{2-}}$.

One carbonate ion (2- charge) is required to balance the charge on one copper ion (2+ charge).  Hence, the chemical formula of the compound is ${\text{CuCO}}_{\text{3}}$.

The given two ions are ${\text{Cu}}^{\text{2+}}$ and ${\text{HSO}}_{\text{4}}^{\text{-}}$.

Two mono hydrogen sulfate ions (1- charge) are required to balance the charge on one copper ion (2+ charge).  Hence, the chemical formula of the compound is ${\text{Cu(HSO}}_{\text{4}}{\text{)}}_{\text{2}}$.

(b)

Interpretation Introduction

Interpretation:

The following table of chemical formulas for polyatomic ion containing ionic compounds is to be filled.

  $\begin{array}{ccccc}& {\text{OH}}^{\text{-}}& {\text{PO}}_{\text{4}}^{\text{3-}}& {\text{CO}}_{\text{3}}^{\text{2-}}& {\text{HSO}}_{\text{4}}^{\text{-}}\\ {\text{Ba}}^{\text{2+}}& & & & \end{array}$

Concept Introduction:

Chemical formulas and names for ionic compounds containing polyatomic ions:

Ionic compounds containing positive and negative charges present must add to zero.

If more than one polyatomic ion is present in a compound, the chemical formula can be written as a polyatomic ion is enclose in parentheses and a subscript, placed outside of the parentheses.  Example- ${\text{Fe(OH)}}_{\text{3}}$.

Sometimes same element is present in two different locations.  For example, ${\text{NH}}_{\text{4}}{\text{NO}}_{\text{3}}$- in this chemical formula “N” is present in two different locations as ${\text{NH}}_{\text{4}}^{\text{+}}{\text{ and NO}}_{\text{3}}^{\text{-}}$ ions.

Answer to Problem 4.110EP

The complete table as shown below:

  $\begin{array}{ccccc}& {\text{OH}}^{\text{-}}& {\text{PO}}_{\text{4}}^{\text{3-}}& {\text{CO}}_{\text{3}}^{\text{2-}}& {\text{HSO}}_{\text{4}}^{\text{-}}\\ {\text{Ba}}^{\text{2+}}& {\text{Ba(OH)}}_{\text{2}}& {\text{Ba}}_{\text{3}}{{\text{(PO}}_{\text{4}}\text{)}}_{\text{2}}& {\text{BaCO}}_{\text{3}}& {\text{Ba(HSO}}_{\text{4}}{\text{)}}_{\text{2}}\end{array}$

Explanation of Solution

The given two ions are ${\text{Ba}}^{\text{2+}}$ and ${\text{OH}}^{\text{-}}$.

Two hydroxide ions (1- charge) are required to balance the charge on one barium ion (2+ charge).  Hence, the chemical formula of the compound is ${\text{Ba(OH)}}_{\text{2}}$.

The given two ions are ${\text{Ba}}^{\text{2+}}$ and ${\text{PO}}_{\text{4}}^{\text{3-}}$.

Two phosphate ions (3- charge) are required to balance the charge on three barium ions (2+ charge).  Hence, the chemical formula of the compound is ${\text{Ba}}_{\text{3}}{{\text{(PO}}_{\text{4}}\text{)}}_{\text{2}}$.

The given two ions are ${\text{Ba}}^{\text{2+}}$ and ${\text{CO}}_{\text{3}}^{\text{2-}}$.

One carbonate ion (2- charge) is required to balance the charge on one barium ion (2+ charge).  Hence, the chemical formula of the compound is ${\text{BaCO}}_{\text{3}}$.

The given two ions are ${\text{Ba}}^{\text{2+}}$ and ${\text{HSO}}_{\text{4}}^{\text{-}}$.

Two mono hydrogen sulfate ions (1- charge) are required to balance the charge on one barium ion (2+ charge).  Hence, the chemical formula of the compound is ${\text{Ba(HSO}}_{\text{4}}{\text{)}}_{\text{2}}$.

(c)

Interpretation Introduction

Interpretation:

The following table of chemical formulas for polyatomic ion containing ionic compounds is to be filled.

  $\begin{array}{ccccc}& {\text{OH}}^{\text{-}}& {\text{PO}}_{\text{4}}^{\text{3-}}& {\text{CO}}_{\text{3}}^{\text{2-}}& {\text{HSO}}_{\text{4}}^{\text{-}}\\ {\text{Fe}}^{\text{3+}}& & & & \end{array}$

Concept Introduction:

Chemical formulas and names for ionic compounds containing polyatomic ions:

Ionic compounds containing positive and negative charges present must add to zero.

If more than one polyatomic ion is present in a compound, the chemical formula can be written as a polyatomic ion is enclose in parentheses and a subscript, placed outside of the parentheses.  Example- ${\text{Fe(OH)}}_{\text{3}}$.

Sometimes same element is present in two different locations.  For example, ${\text{NH}}_{\text{4}}{\text{NO}}_{\text{3}}$- in this chemical formula “N” is present in two different locations as ${\text{NH}}_{\text{4}}^{\text{+}}{\text{ and NO}}_{\text{3}}^{\text{-}}$ ions.

Answer to Problem 4.110EP

The complete table as shown below:

  $\begin{array}{ccccc}& {\text{OH}}^{\text{-}}& {\text{PO}}_{\text{4}}^{\text{3-}}& {\text{CO}}_{\text{3}}^{\text{2-}}& {\text{HSO}}_{\text{4}}^{\text{-}}\\ {\text{Fe}}^{\text{3+}}& {\text{Fe(OH)}}_{\text{3}}& {\text{FePO}}_{\text{4}}& {\text{Fe}}_{\text{2}}{{\text{(CO}}_{\text{3}}\text{)}}_{\text{3}}& {\text{Fe(HSO}}_{\text{4}}{\text{)}}_{\text{3}}\end{array}$

Explanation of Solution

The given two ions are ${\text{Fe}}^{\text{3+}}$ and ${\text{OH}}^{\text{-}}$.

Three hydroxide ions (1- charge) are required to balance the charge on one ferric ion (2+ charge).  Hence, the chemical formula of the compound is ${\text{Fe(OH)}}_{\text{3}}$.

The given two ions are ${\text{Fe}}^{\text{3+}}$ and ${\text{PO}}_{\text{4}}^{\text{3-}}$.

One phosphate ion (3- charge) is required to balance the charge on one ferric ion (2+ charge).

Hence, the chemical formula of the compound is ${\text{FePO}}_{\text{4}}$.

The given two ions are ${\text{Fe}}^{\text{3+}}$ and ${\text{CO}}_{\text{3}}^{\text{2-}}$.

Three carbonate ions (2- charge) are required to balance the charge on two ferric ions (2+ charge).  Hence, the chemical formula of the compound is ${\text{Fe}}_{\text{2}}{{\text{(CO}}_{\text{3}}\text{)}}_{\text{3}}$.

The given two ions are ${\text{Fe}}^{\text{3+}}$ and ${\text{HSO}}_{\text{4}}^{\text{-}}$.

Three mono hydrogen sulfate ions (1- charge) are required to balance the charge on one ferric ion (2+ charge).  Hence, the chemical formula of the compound is ${\text{Fe(HSO}}_{\text{4}}{\text{)}}_{\text{3}}$.

(d)

Interpretation Introduction

Interpretation:

The following table of chemical formulas for polyatomic ion containing ionic compounds is to be filled.

  $\begin{array}{ccccc}& {\text{OH}}^{\text{-}}& {\text{PO}}_{\text{4}}^{\text{3-}}& {\text{CO}}_{\text{3}}^{\text{2-}}& {\text{HSO}}_{\text{4}}^{\text{-}}\\ {\text{NH}}_{\text{4}}^{\text{+}}& & & & \end{array}$

Concept Introduction:

Chemical formulas and names for ionic compounds containing polyatomic ions:

Ionic compounds containing positive and negative charges present must add to zero.

If more than one polyatomic ion is present in a compound, the chemical formula can be written as a polyatomic ion is enclose in parentheses and a subscript, placed outside of the parentheses.  Example- ${\text{Fe(OH)}}_{\text{3}}$.

Sometimes same element is present in two different locations.  For example, ${\text{NH}}_{\text{4}}{\text{NO}}_{\text{3}}$- in this chemical formula “N” is present in two different locations as ${\text{NH}}_{\text{4}}^{\text{+}}{\text{ and NO}}_{\text{3}}^{\text{-}}$ ions.

Answer to Problem 4.110EP

The complete table as shown below.

  $\begin{array}{ccccc}& {\text{OH}}^{\text{-}}& {\text{PO}}_{\text{4}}^{\text{3-}}& {\text{CO}}_{\text{3}}^{\text{2-}}& {\text{HSO}}_{\text{4}}^{\text{-}}\\ {\text{NH}}_{\text{4}}^{\text{+}}& {\text{NH}}_{\text{4}}\text{OH}& {{\text{(NH}}_{\text{4}}\text{)}}_{\text{3}}{\text{PO}}_{\text{4}}& {{\text{(NH}}_{\text{4}}\text{)}}_{\text{2}}{\text{CO}}_{\text{3}}& {\text{NH}}_{\text{4}}{\text{HSO}}_{\text{4}}\end{array}$

Explanation of Solution

The given two ions are ${\text{NH}}_{\text{4}}^{\text{+}}$ and ${\text{OH}}^{\text{-}}$.

One hydroxide ion (1- charge) is required to balance the charge on one ammonium ion (1+ charge).  Hence, the chemical formula of the compound is ${\text{NH}}_{\text{4}}\text{OH}$.

The given two ions are ${\text{NH}}_{\text{4}}^{\text{+}}$ and ${\text{PO}}_{\text{4}}^{\text{3-}}$.

One phosphate ion (3- charge) is required to balance the charge on three ammonium ions (1+ charge).  Hence, the chemical formula of the compound is ${{\text{(NH}}_{\text{4}}\text{)}}_{\text{3}}{\text{PO}}_{\text{4}}$.

The given two ions are ${\text{NH}}_{\text{4}}^{\text{+}}$ and ${\text{CO}}_{\text{3}}^{\text{2-}}$.

One carbonate ion (2- charge) is required to balance the charge on two ammonium ions (1+ charge).  Hence, the chemical formula of the compound is ${{\text{(NH}}_{\text{4}}\text{)}}_{\text{2}}{\text{CO}}_{\text{3}}$.

The given two ions are ${\text{NH}}_{\text{4}}^{\text{+}}$ and ${\text{HSO}}_{\text{4}}^{\text{-}}$.

Three mono hydrogen sulfate ions (1- charge) are required to balance the charge on one ammonium ion (1+ charge).  Hence, the chemical formula of the compound is ${\text{NH}}_{\text{4}}{\text{HSO}}_{\text{4}}$.