Data Structures and Algorithms in Java
Data Structures and Algorithms in Java
6th Edition
ISBN: 9781118771334
Author: Michael T. Goodrich
Publisher: WILEY
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Chapter 4, Problem 40C

Explanation of Solution

Total number of grains requested by the inventor of chess:

If a chessboard is placed with square then one grain is placed on first square, two on second, and four on third. On each subsequent square, the numbers of grains are doubled.

Thus, the exponential increase on each square contains 2n1 grains of rice.

Since, there are 64 squares on the chessboard, apply the value of 64 in the formula 2n1 to fill the final square on the chessboard. Substitute “n” as 64.

  Fillingofriceonfinalsquareonchessboard=2641=263=9223372036854775808=9.22×1018

To determine the total number of grains of rice let us use the exponential sum using the formula 2n 1

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