Chapter 4, Problem 31PE

Interpretation Introduction

Interpretation:

The final volume up to which $\text{100}\text{.0 mL}$ of $\text{0}\text{.125 }M{\text{ H}}_{\text{2}}{\text{SO}}_{\text{4}}$ is diluted in order to prepare a $\text{ 0}\text{.0500 }M{\text{ H}}_{\text{2}}{\text{SO}}_{\text{4}}$ solution is to be determined.

Concept Introduction:

The number of moles present in one liter of a solution is known as the molarity of the solution. It is calculated as follows:

$M=\frac{n}{V}$

Here $M$ is the molarity of the solution, $V$ is the volume of the solution in liters and $n$ is the number of moles of the solute.

The process in which the concentration of the solutes in a solution is reduced by adding more solvent to it is known as dilution.

The dilution process takes place by adding more amount of solvent to the solution and results in a decrease of the concentration of the solution. But the product of the molarity and the volume should be the same for both the concentrated and the diluted forms. The volume of the diluted solution is calculated by using the following equation:

$V_{\text{dil}}\times M_{\text{dil}}=V_{\text{conc}}\times M_{\text{conc}}$

Here, $V_{\text{dil}}$ and $V_{\text{conc}}$ are the volumes of the dilute and the concentrated solutions, respectively and $M_{\text{dil}}$ and $M_{\text{conc}}$ are the molarities of the dilute and the concentrated solutions, respectively.