The D H 0 value for C-C bond in cyclopropane needs to be determined. Concept Introduction: For a general reaction, the enthalpy change with respect to the bond dissociation energy can be calculated as follows: A − A + B − B → 2 A − B Δ H 0 = B . E ( A − A ) + B . E ( B − B ) − 2 B . E ( A − B ) Here, B . E ( A − A ) is bond dissociation energy of A-A bond, B . E ( B − B ) is bond dissociation energy of B-B bond and B . E ( A − B ) is bond dissociation energy of A-B bond.

Question

Want to see the full answer?

Answer 1

Question

Formula Formula Bond dissociation energy (BDE) is the energy required to break a bond, making it an endothermic process. BDE is calculated for a particular bond and therefore consists of fragments such as radicals since it undergoes homolytic bond cleavage. For the homolysis of a X-Y molecule, the energy of bond dissociation is calculated as the difference in the total enthalpy of formation for the reactants and products. X-Y → X + Y BDE = Δ H f X + Δ H f Y – Δ H f X-Y where, ΔHf is the heat of formation.

Chapter 4, Problem 28P

(a)

Interpretation Introduction

Interpretation: The DH0 value for C-C bond in cyclopropane needs to be determined.

Concept Introduction:For a general reaction, the enthalpy change with respect to the bond dissociation energy can be calculated as follows:

A−A+B−B→2A−B

ΔH0=B.E(A−A)+B.E(B−B)−2B.E(A−B)

Here, B.E(A−A) is bond dissociation energy of A-A bond, B.E(B−B) is bond dissociation energy of B-B bond and B.E(A−B) is bond dissociation energy of A-B bond.

(b)

Interpretation Introduction

Interpretation: The DH0 value for C-C bond in cyclobutene needs to be determined.

Concept Introduction: For a general reaction, the enthalpy change with respect to the bond dissociation energy can be calculated as follows:

A−A+B−B→2A−B

ΔH0=B.E(A−A)+B.E(B−B)−2B.E(A−B)

Here, B.E(A−A) is bond dissociation energy of A-A bond, B.E(B−B) is bond dissociation energy of B-B bond and B.E(A−B) is bond dissociation energy of A-B bond.

(c)

Interpretation Introduction

Interpretation: The DH0 value for C-C bond in cyclopentane needs to be determined.

Concept Introduction: For a general reaction, the enthalpy change with respect to the bond dissociation energy can be calculated as follows:

A−A+B−B→2A−B

ΔH0=B.E(A−A)+B.E(B−B)−2B.E(A−B)

Here, B.E(A−A) is bond dissociation energy of A-A bond, B.E(B−B) is bond dissociation energy of B-B bond and B.E(A−B) is bond dissociation energy of A-B bond.

(d)

Interpretation Introduction

Interpretation: The DH0 value for C-C bond in cyclopentane needs to be determined.

Concept Introduction: For a general reaction, the enthalpy change with respect to the bond dissociation energy can be calculated as follows:

A−A+B−B→2A−B

ΔH0=B.E(A−A)+B.E(B−B)−2B.E(A−B)

Here, B.E(A−A) is bond dissociation energy of A-A bond, B.E(B−B) is bond dissociation energy of B-B bond and B.E(A−B) is bond dissociation energy of A-B bond.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

පිපිම Draw curved arrows to represent the flow of electrons in the reaction on the left Label the reactants on the left as either "Acid" or "Base" (iii) Decide which direction the equilibrium arrows will point in each reaction, based on the given pk, values (a) + H-O H 3-H + (c) H" H + H****H 000 44-00 NH₂ (e) i Дон OH Ө NH

3) Label the configuration in each of the following alkenes as E, Z, or N/A (for non-stereogenic centers). 00 E 000 N/A E Br N/A N/A (g) E N/A OH E (b) Oz N/A Br (d) 00 E Z N/A E (f) Oz N/A E (h) Z N/A

6) Fill in the missing Acid, pKa value, or conjugate base in the table below: Acid HCI Approximate pK, -7 Conjugate Base H-C: Hydronium (H₂O') -1.75 H-O-H Carboxylic Acids (RCOOH) Ammonium (NH4) 9.24 Water (H₂O) H-O-H Alcohols (ROH) RO-H Alkynes R--H Amines 25 25 38 HO

Answer 2

Question

Formula Formula Bond dissociation energy (BDE) is the energy required to break a bond, making it an endothermic process. BDE is calculated for a particular bond and therefore consists of fragments such as radicals since it undergoes homolytic bond cleavage. For the homolysis of a X-Y molecule, the energy of bond dissociation is calculated as the difference in the total enthalpy of formation for the reactants and products. X-Y → X + Y BDE = Δ H f X + Δ H f Y – Δ H f X-Y where, ΔHf is the heat of formation.

Chapter 4, Problem 28P

(a)

Interpretation Introduction

Interpretation: The DH0 value for C-C bond in cyclopropane needs to be determined.

Concept Introduction:For a general reaction, the enthalpy change with respect to the bond dissociation energy can be calculated as follows:

A−A+B−B→2A−B

ΔH0=B.E(A−A)+B.E(B−B)−2B.E(A−B)

Here, B.E(A−A) is bond dissociation energy of A-A bond, B.E(B−B) is bond dissociation energy of B-B bond and B.E(A−B) is bond dissociation energy of A-B bond.

(b)

Interpretation Introduction

Interpretation: The DH0 value for C-C bond in cyclobutene needs to be determined.

Concept Introduction: For a general reaction, the enthalpy change with respect to the bond dissociation energy can be calculated as follows:

A−A+B−B→2A−B

ΔH0=B.E(A−A)+B.E(B−B)−2B.E(A−B)

Here, B.E(A−A) is bond dissociation energy of A-A bond, B.E(B−B) is bond dissociation energy of B-B bond and B.E(A−B) is bond dissociation energy of A-B bond.

(c)

Interpretation Introduction

Interpretation: The DH0 value for C-C bond in cyclopentane needs to be determined.

Concept Introduction: For a general reaction, the enthalpy change with respect to the bond dissociation energy can be calculated as follows:

A−A+B−B→2A−B

ΔH0=B.E(A−A)+B.E(B−B)−2B.E(A−B)

Here, B.E(A−A) is bond dissociation energy of A-A bond, B.E(B−B) is bond dissociation energy of B-B bond and B.E(A−B) is bond dissociation energy of A-B bond.

(d)

Interpretation Introduction

Interpretation: The DH0 value for C-C bond in cyclopentane needs to be determined.

Concept Introduction: For a general reaction, the enthalpy change with respect to the bond dissociation energy can be calculated as follows:

A−A+B−B→2A−B

ΔH0=B.E(A−A)+B.E(B−B)−2B.E(A−B)

Here, B.E(A−A) is bond dissociation energy of A-A bond, B.E(B−B) is bond dissociation energy of B-B bond and B.E(A−B) is bond dissociation energy of A-B bond.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Formula Formula Bond dissociation energy (BDE) is the energy required to break a bond, making it an endothermic process. BDE is calculated for a particular bond and therefore consists of fragments such as radicals since it undergoes homolytic bond cleavage. For the homolysis of a X-Y molecule, the energy of bond dissociation is calculated as the difference in the total enthalpy of formation for the reactants and products. X-Y → X + Y BDE = Δ H f X + Δ H f Y – Δ H f X-Y where, ΔHf is the heat of formation.

Chapter 4, Problem 28P

(a)

Interpretation Introduction

Interpretation: The DH0 value for C-C bond in cyclopropane needs to be determined.

Concept Introduction:For a general reaction, the enthalpy change with respect to the bond dissociation energy can be calculated as follows:

A−A+B−B→2A−B

ΔH0=B.E(A−A)+B.E(B−B)−2B.E(A−B)

Here, B.E(A−A) is bond dissociation energy of A-A bond, B.E(B−B) is bond dissociation energy of B-B bond and B.E(A−B) is bond dissociation energy of A-B bond.

(b)

Interpretation Introduction

Interpretation: The DH0 value for C-C bond in cyclobutene needs to be determined.

Concept Introduction: For a general reaction, the enthalpy change with respect to the bond dissociation energy can be calculated as follows:

A−A+B−B→2A−B

ΔH0=B.E(A−A)+B.E(B−B)−2B.E(A−B)

Here, B.E(A−A) is bond dissociation energy of A-A bond, B.E(B−B) is bond dissociation energy of B-B bond and B.E(A−B) is bond dissociation energy of A-B bond.

(c)

Interpretation Introduction

Interpretation: The DH0 value for C-C bond in cyclopentane needs to be determined.

Concept Introduction: For a general reaction, the enthalpy change with respect to the bond dissociation energy can be calculated as follows:

A−A+B−B→2A−B

ΔH0=B.E(A−A)+B.E(B−B)−2B.E(A−B)

Here, B.E(A−A) is bond dissociation energy of A-A bond, B.E(B−B) is bond dissociation energy of B-B bond and B.E(A−B) is bond dissociation energy of A-B bond.

(d)

Interpretation Introduction

Interpretation: The DH0 value for C-C bond in cyclopentane needs to be determined.

Concept Introduction: For a general reaction, the enthalpy change with respect to the bond dissociation energy can be calculated as follows:

A−A+B−B→2A−B

ΔH0=B.E(A−A)+B.E(B−B)−2B.E(A−B)

Here, B.E(A−A) is bond dissociation energy of A-A bond, B.E(B−B) is bond dissociation energy of B-B bond and B.E(A−B) is bond dissociation energy of A-B bond.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Formula Formula Bond dissociation energy (BDE) is the energy required to break a bond, making it an endothermic process. BDE is calculated for a particular bond and therefore consists of fragments such as radicals since it undergoes homolytic bond cleavage. For the homolysis of a X-Y molecule, the energy of bond dissociation is calculated as the difference in the total enthalpy of formation for the reactants and products. X-Y → X + Y BDE = Δ H f X + Δ H f Y – Δ H f X-Y where, ΔHf is the heat of formation.

Chapter 4, Problem 28P

(a)

Interpretation Introduction

Interpretation: The DH0 value for C-C bond in cyclopropane needs to be determined.

Concept Introduction:For a general reaction, the enthalpy change with respect to the bond dissociation energy can be calculated as follows:

A−A+B−B→2A−B

ΔH0=B.E(A−A)+B.E(B−B)−2B.E(A−B)

Here, B.E(A−A) is bond dissociation energy of A-A bond, B.E(B−B) is bond dissociation energy of B-B bond and B.E(A−B) is bond dissociation energy of A-B bond.

(b)

Interpretation Introduction

Interpretation: The DH0 value for C-C bond in cyclobutene needs to be determined.

Concept Introduction: For a general reaction, the enthalpy change with respect to the bond dissociation energy can be calculated as follows:

A−A+B−B→2A−B

ΔH0=B.E(A−A)+B.E(B−B)−2B.E(A−B)

Here, B.E(A−A) is bond dissociation energy of A-A bond, B.E(B−B) is bond dissociation energy of B-B bond and B.E(A−B) is bond dissociation energy of A-B bond.

(c)

Interpretation Introduction

Interpretation: The DH0 value for C-C bond in cyclopentane needs to be determined.

Concept Introduction: For a general reaction, the enthalpy change with respect to the bond dissociation energy can be calculated as follows:

A−A+B−B→2A−B

ΔH0=B.E(A−A)+B.E(B−B)−2B.E(A−B)

Here, B.E(A−A) is bond dissociation energy of A-A bond, B.E(B−B) is bond dissociation energy of B-B bond and B.E(A−B) is bond dissociation energy of A-B bond.

(d)

Interpretation Introduction

Interpretation: The DH0 value for C-C bond in cyclopentane needs to be determined.

Concept Introduction: For a general reaction, the enthalpy change with respect to the bond dissociation energy can be calculated as follows:

A−A+B−B→2A−B

ΔH0=B.E(A−A)+B.E(B−B)−2B.E(A−B)

Here, B.E(A−A) is bond dissociation energy of A-A bond, B.E(B−B) is bond dissociation energy of B-B bond and B.E(A−B) is bond dissociation energy of A-B bond.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 4, Problem 28P

(a)

Interpretation Introduction

Interpretation: The DH0 value for C-C bond in cyclopropane needs to be determined.

Concept Introduction:For a general reaction, the enthalpy change with respect to the bond dissociation energy can be calculated as follows:

A−A+B−B→2A−B

ΔH0=B.E(A−A)+B.E(B−B)−2B.E(A−B)

Here, B.E(A−A) is bond dissociation energy of A-A bond, B.E(B−B) is bond dissociation energy of B-B bond and B.E(A−B) is bond dissociation energy of A-B bond.

(b)

Interpretation Introduction

Interpretation: The DH0 value for C-C bond in cyclobutene needs to be determined.

Concept Introduction: For a general reaction, the enthalpy change with respect to the bond dissociation energy can be calculated as follows:

A−A+B−B→2A−B

ΔH0=B.E(A−A)+B.E(B−B)−2B.E(A−B)

Here, B.E(A−A) is bond dissociation energy of A-A bond, B.E(B−B) is bond dissociation energy of B-B bond and B.E(A−B) is bond dissociation energy of A-B bond.

(c)

Interpretation Introduction

Interpretation: The DH0 value for C-C bond in cyclopentane needs to be determined.

Concept Introduction: For a general reaction, the enthalpy change with respect to the bond dissociation energy can be calculated as follows:

A−A+B−B→2A−B

ΔH0=B.E(A−A)+B.E(B−B)−2B.E(A−B)

Here, B.E(A−A) is bond dissociation energy of A-A bond, B.E(B−B) is bond dissociation energy of B-B bond and B.E(A−B) is bond dissociation energy of A-B bond.

(d)

Interpretation Introduction

Interpretation: The DH0 value for C-C bond in cyclopentane needs to be determined.

Concept Introduction: For a general reaction, the enthalpy change with respect to the bond dissociation energy can be calculated as follows:

A−A+B−B→2A−B

ΔH0=B.E(A−A)+B.E(B−B)−2B.E(A−B)

Here, B.E(A−A) is bond dissociation energy of A-A bond, B.E(B−B) is bond dissociation energy of B-B bond and B.E(A−B) is bond dissociation energy of A-B bond.

Answer 6

Chapter 4, Problem 28P

(a)

Interpretation Introduction

Interpretation: The DH0 value for C-C bond in cyclopropane needs to be determined.

Concept Introduction:For a general reaction, the enthalpy change with respect to the bond dissociation energy can be calculated as follows:

A−A+B−B→2A−B

ΔH0=B.E(A−A)+B.E(B−B)−2B.E(A−B)

Here, B.E(A−A) is bond dissociation energy of A-A bond, B.E(B−B) is bond dissociation energy of B-B bond and B.E(A−B) is bond dissociation energy of A-B bond.

Answer 7

Chapter 4, Problem 28P

(a)

Interpretation Introduction

Interpretation: The DH0 value for C-C bond in cyclopropane needs to be determined.

Concept Introduction:For a general reaction, the enthalpy change with respect to the bond dissociation energy can be calculated as follows:

A−A+B−B→2A−B

ΔH0=B.E(A−A)+B.E(B−B)−2B.E(A−B)

Here, B.E(A−A) is bond dissociation energy of A-A bond, B.E(B−B) is bond dissociation energy of B-B bond and B.E(A−B) is bond dissociation energy of A-B bond.

Answer 8

(b)

Interpretation Introduction

Interpretation: The DH0 value for C-C bond in cyclobutene needs to be determined.

Concept Introduction: For a general reaction, the enthalpy change with respect to the bond dissociation energy can be calculated as follows:

A−A+B−B→2A−B

ΔH0=B.E(A−A)+B.E(B−B)−2B.E(A−B)

Here, B.E(A−A) is bond dissociation energy of A-A bond, B.E(B−B) is bond dissociation energy of B-B bond and B.E(A−B) is bond dissociation energy of A-B bond.

Answer 9

(b)

Interpretation Introduction

Interpretation: The DH0 value for C-C bond in cyclobutene needs to be determined.

Concept Introduction: For a general reaction, the enthalpy change with respect to the bond dissociation energy can be calculated as follows:

A−A+B−B→2A−B

ΔH0=B.E(A−A)+B.E(B−B)−2B.E(A−B)

Here, B.E(A−A) is bond dissociation energy of A-A bond, B.E(B−B) is bond dissociation energy of B-B bond and B.E(A−B) is bond dissociation energy of A-B bond.

Answer 10

(c)

Interpretation Introduction

Interpretation: The DH0 value for C-C bond in cyclopentane needs to be determined.

Concept Introduction: For a general reaction, the enthalpy change with respect to the bond dissociation energy can be calculated as follows:

A−A+B−B→2A−B

ΔH0=B.E(A−A)+B.E(B−B)−2B.E(A−B)

Here, B.E(A−A) is bond dissociation energy of A-A bond, B.E(B−B) is bond dissociation energy of B-B bond and B.E(A−B) is bond dissociation energy of A-B bond.

Answer 11

(c)

Interpretation Introduction

Interpretation: The DH0 value for C-C bond in cyclopentane needs to be determined.

Concept Introduction: For a general reaction, the enthalpy change with respect to the bond dissociation energy can be calculated as follows:

A−A+B−B→2A−B

ΔH0=B.E(A−A)+B.E(B−B)−2B.E(A−B)

Here, B.E(A−A) is bond dissociation energy of A-A bond, B.E(B−B) is bond dissociation energy of B-B bond and B.E(A−B) is bond dissociation energy of A-B bond.

Answer 12

(d)

Interpretation Introduction

Interpretation: The DH0 value for C-C bond in cyclopentane needs to be determined.

Concept Introduction: For a general reaction, the enthalpy change with respect to the bond dissociation energy can be calculated as follows:

A−A+B−B→2A−B

ΔH0=B.E(A−A)+B.E(B−B)−2B.E(A−B)

Here, B.E(A−A) is bond dissociation energy of A-A bond, B.E(B−B) is bond dissociation energy of B-B bond and B.E(A−B) is bond dissociation energy of A-B bond.

Answer 13

(d)

Interpretation Introduction

Interpretation: The DH0 value for C-C bond in cyclopentane needs to be determined.

Concept Introduction: For a general reaction, the enthalpy change with respect to the bond dissociation energy can be calculated as follows:

A−A+B−B→2A−B

ΔH0=B.E(A−A)+B.E(B−B)−2B.E(A−B)

Here, B.E(A−A) is bond dissociation energy of A-A bond, B.E(B−B) is bond dissociation energy of B-B bond and B.E(A−B) is bond dissociation energy of A-B bond.

Answer 14

Expert Solution & Answer

Answer 15

Expert Solution & Answer

Answer 16

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 17

Ch. 4.1 - Prob. 4.1E Ch. 4.1 - Prob. 4.3TIY Ch. 4.2 - Prob. 4.4E Ch. 4.2 - Prob. 4.6TIY Ch. 4.3 - Prob. 4.7E Ch. 4.4 - Prob. 4.8E Ch. 4.4 - Prob. 4.10TIY Ch. 4.4 - Prob. 4.11E Ch. 4.4 - Prob. 4.12E Ch. 4.4 - Prob. 4.14TIY

Concept explainers

Videos

Want to see the full answer?

Chapter 4 Solutions