Database Systems: Design Implementation & Management
11th Edition
ISBN: 9781305850378
Author: Coronel
Publisher: Cengage
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Chapter 4, Problem 1RQ
Explanation of Solution
Conditions:
Following are the conditions should be met before an entity is referred as a weak entity:
- The entity should be “existence-dependent” on its parent entity.
- If an entity is referred as an “existence-dependent”, then that entity can exist in the
database if and only if when it is related with another entity existence.
- If an entity is referred as an “existence-dependent”, then that entity can exist in the
- The entity should inherits a section of its primary key (PK) from its parent entity.
Example:
Consider the following ER diagram along with its attributes:
Explanation:
- The entity CLASS is “existence-dependent” on COURSE entity. Hence the CLASS entity uses a PK component from its parent entity (COURSE).
- The CLASS entity’s PK is (COURSE_ID, CLASS_SEC).
- In this strong implementation, the CLASS entity is referred as a weak entity between COURSE and CLASS.
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I need help fixing the minor issue where the text isn't in the proper place, and to ensure that the frequency cutoff is at the right place.
My code:
% Define frequency range for the plot
f = logspace(1, 5, 500); % Frequency range from 10 Hz to 100 kHz
w = 2 * pi * f; % Angular frequency
% Parameters for the filters - let's adjust these to get more reasonable cutoffs
R = 1e3; % Resistance in ohms (1 kΩ)
C = 1e-6; % Capacitance in farads (1 μF)
% For bandpass, we need appropriate L value for desired cutoffs
L = 0.1; % Inductance in henries - adjusted for better bandpass response
% Calculate cutoff frequencies first to verify they're in desired range
f_cutoff_RC = 1 / (2 * pi * R * C);
f_resonance = 1 / (2 * pi * sqrt(L * C));
Q_factor = (1/R) * sqrt(L/C);
f_lower_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) + 1/(2*Q_factor));
f_upper_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) - 1/(2*Q_factor));
% Transfer functions
% Low-pass filter (RC)
H_low = 1 ./ (1 + 1i * w *…
Chapter 4 Solutions
Database Systems: Design Implementation & Management
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Ch. 4 - Prob. 13RQCh. 4 - Prob. 14RQCh. 4 - Briefly, but precisely, explain the difference...Ch. 4 - What are multivalued attributes, and how can they...Ch. 4 - Prob. 17RQCh. 4 - Prob. 18RQCh. 4 - What two attributes must be contained in the...Ch. 4 - Describe precisely the composition of the...Ch. 4 - Prob. 21RQCh. 4 - Prob. 1PCh. 4 - Create a complete ERD in Crows Foot notation that...Ch. 4 - Prob. 4PCh. 4 - Prob. 5PCh. 4 - Prob. 6PCh. 4 - Prob. 7PCh. 4 - Prob. 8PCh. 4 - Prob. 9C
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