
Concept explainers
Whether the force acting or not when the coffee cup sits motionlessly on tray and how it differs from the force when cup is placed on the kitchen table at home.

Explanation of Solution
Introduction:
Newton’s first law of motion defines that an object remains in the state of rest or the state of motion in the same direction unless an external force act upon it.
The forces that are acting on the coffee cup placed over tray are the normal forces exerted by the table on the cup and the gravitational pull of the Earth. The cup placed on the table in the plane is stationary with respect to the surface, as like the cup in the kitchen, which is also stationary with respect to the surface. In both cases, the cup is not accelerating relative to the ground.
Thus, the forces acting upon the cup are the normal forces and the gravitational forces of the Earth. The force on the cup is the same if the table and the cup are in the kitchen as the cup will still be stationary with respect to the ground.
Conclusion:
Therefore, the forces are acting on the cup and they will be same even if the cup is placed on the kitchen table.
Want to see more full solutions like this?
Chapter 4 Solutions
PHYSICS F/SCI.+ENGRS.,STAND.-W/ACCESS
- Hi! I need help with these calculations for part i and part k for a physics Diffraction Lab. We used a slit width 0.4 mm to measure our pattern.arrow_forwardExamine the data and % error values in Data Table 3 where the angular displacement of the simple pendulum decreased but the mass of the pendulum bob and the length of the pendulum remained constant. Describe whether or not your data shows that the period of the pendulum depends on the angular displacement of the pendulum bob, to within a reasonable percent error.arrow_forwardIn addition to the anyalysis of the graph, show mathematically that the slope of that line is 2π/√g . Using the slope of your line calculate the value of g and compare it to 9.8.arrow_forward
- An object is placed 24.1 cm to the left of a diverging lens (f = -6.51 cm). A concave mirror (f= 14.8 cm) is placed 30.2 cm to the right of the lens to form an image of the first image formed by the lens. Find the final image distance, measured relative to the mirror. (b) Is the final image real or virtual? (c) Is the final image upright or inverted with respect to the original object?arrow_forwardConcept Simulation 26.4 provides the option of exploring the ray diagram that applies to this problem. The distance between an object and its image formed by a diverging lens is 5.90 cm. The focal length of the lens is -2.60 cm. Find (a) the image distance and (b) the object distance.arrow_forwardPls help ASAParrow_forward
- Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningPhysics for Scientists and Engineers, Technology ...PhysicsISBN:9781305116399Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningCollege PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningClassical Dynamics of Particles and SystemsPhysicsISBN:9780534408961Author:Stephen T. Thornton, Jerry B. MarionPublisher:Cengage Learning





