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Concept explainers
What will the println statement in the following
int x = 5;
System.out.println(x++);
- a. 5
- b. 6
- c. 0
- d. None of these
![Check Mark](/static/check-mark.png)
The println statement in the given program segment displays the value “5”.
Hence, the correct answer is option “A”.
Explanation of Solution
Increment operator “++”:
The increment operator is used to increment or increase the value of the variable by “1”.
Example:
/*the variable val is increased by 1 with a postfix representation */
val++;
/*the variable val is increased by 1 with a prefix representation */
++val;
In the given program segment, the variable “x” is declared and initialized with the value “5”. In the println statement, post-increment operation is performed using the statement “x++”. As per postfix mode, the value of the variable “x” is printed and then the value is incremented. Therefore, the value of “x”, which is “5” is printed using the println statement and then the value of “x” is incremented.
Explanation for incorrect options:
b. 6:
The value of “x” is incremented to 6 after it is displayed.
Hence, the option “B” is wrong.
c. 0:
The value of “x” is initialized as 5, and then it is not modified as “0”.
Hence, the option “C” is wrong.
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