Explanation In the given problem, the mass is suspended on a spring. The mass is pulled down and released. It oscillates up and down. Refer the fig 4.26 provided in the problem. When the spring is stretched the least, there will be the minimum potential energy of the spring. When the mass is stopped, then there will be zero kinetic energy. When the mass has reached at its maximum speed, then there will be maximum kinetic energy. When the spring is stretched to its maximum extension, then there will be maximum potential energy. The kinetic energy is maximum at the mean position of the mass suspended from the spring. The potential energy is maximum at the extreme position due to some height attained by the mass. When the mass suspended from the spring moves from the mean position to the extreme position, the kinetic energy will decrease and then, the kinetic energy will get converted into the potential energy. When the mass suspended from the spring from extreme position to the mean position, then the potential energy of the mass-spring system starts decreasing and then, the potential energy will get converted into the kinetic energy. Conclusion: Therefore, the positions of the spring according to the given condition of the problem are as follows, (a)Position of instantaneous rest is at (a)...

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Chapter 4, Problem 17SA

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The positions of the spring according to the given condition of the problem.

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Chapter 4, Problem 16SA

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An Introduction to Physical Science

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The positions of the spring according to the given condition of the problem.

Solution Summary: The author explains how the mass is suspended on a spring and oscillates up and down according to the given condition of the problem.

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The positions of the spring according to the given condition of the problem.

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