Chapter 4, Problem 17CT

(a)

To determine

To write the fraction of my teams’ point scored by me in each game.

Answer to Problem 17CT

Game 1- $\frac{2}{7}$

Game 2- $\frac{1}{3}$

Game 3- $\frac{3}{13}$

Game 4- $\frac{1}{13}$

Game 5- $\frac{4}{15}$

Explanation of Solution

Given information:

Fraction of my points in each game.

Game 1- $\frac{12}{42}$

Game 2- $\frac{19}{57}$

Game 3- $\frac{15}{65}$

Game 4- $\frac{4}{52}$

Game 5- $\frac{16}{60}$

Formula Used: Factorization

Calculation:

To write the fraction in its simplest form, calculate the fractions one by one

(a) Game 1- The fraction is $\frac{12}{42}$ .

break it into its prime factors for simplification.

  $\frac{2\times 3\times 2}{7\times 2\times 3}=\frac{2}{7}$

(b) Game 2- The fraction is $\frac{19}{57}$

break it into its prime factors for simplification.

  $\frac{19}{3\times 19}=\frac{1}{3}$

(c) Game 3- The fraction is $\frac{15}{65}$

break it into its prime factors for simplification.

  $\frac{3\times 5}{13\times 5}=\frac{3}{13}$

(d) Game 4- The fraction is $\frac{4}{52}$

break it into its prime factors for simplification.

  $\frac{2\times 2}{2\times 2\times 13}=\frac{1}{13}$

(e) Game 5- The fraction is $\frac{16}{60}$

break it into its prime factors for simplification.

  $\frac{2\times 2\times 2\times 2}{5\times 2\times 2\times 3}=\frac{2\times 2}{5\times 3}=\frac{4}{15}$

Conclusion-

Game 1- $\frac{2}{7}$

Game 2- $\frac{1}{3}$

Game 3- $\frac{3}{13}$

Game 4- $\frac{1}{13}$

Game 5- $\frac{4}{15}$