The Solar System
10th Edition
ISBN: 9781337672252
Author: The Solar System
Publisher: Cengage
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Question
Chapter 4, Problem 11RQ
To determine
Whether epicycle or deferent travels in uniform circular motion as viewed from particular point. Whether the uniform circular motions have same speed and in same directions.
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Describe three propositions, now known as Kepler’s laws of planetary motion?
Which of the following statements is supported by Kepler's laws of planetary motion?
Earth orbits the Sun at a constant speed, never speeding up or slowing down.
Earth's orbit is a perfect circle, with the Sun located at the center of the circle.
Earth orbits the Sun at a slightly faster speed every year.
Earth has an elliptical orbit, with the Sun located at one focus of the ellipse.
Please answer this question in full steps using proper formulas for universal circular motion. Send ASAP.
Chapter 4 Solutions
The Solar System
Ch. 4 - Prob. 1RQCh. 4 - Why did early human cultures observe astronomical...Ch. 4 - Prob. 3RQCh. 4 - Name one example each of a famous politician,...Ch. 4 - Why did Plato propose that all heavenly motion was...Ch. 4 -
On what did Plato base his knowledge? Was it...Ch. 4 - Which two-dimensional (2D) and three-dimensional...Ch. 4 - Prob. 8RQCh. 4 - In Ptolemys model, how do the epicycles of Mercury...Ch. 4 - Describe in detail the motions of the planets...
Ch. 4 - Prob. 11RQCh. 4 - Prob. 12RQCh. 4 - Prob. 13RQCh. 4 -
When Tycho observed the new star of 1572, he...Ch. 4 - Assume the night is clear and the Moons phase is...Ch. 4 - Does Tychos model of the Universe explain the...Ch. 4 - Name an empirical law. Why is it considered...Ch. 4 -
How does Kepler’s first law of planetary motion...Ch. 4 - Prob. 19RQCh. 4 - Prob. 20RQCh. 4 - Prob. 21RQCh. 4 - Prob. 22RQCh. 4 - Prob. 23RQCh. 4 - Prob. 24RQCh. 4 - Prob. 25RQCh. 4 - Prob. 26RQCh. 4 - Prob. 27RQCh. 4 - Prob. 1PCh. 4 -
If you lived on Mars, which planets would exhibit...Ch. 4 - Prob. 3PCh. 4 - If a planet has an average distance from the Sun...Ch. 4 - If a space probe is sent into an orbit around the...Ch. 4 - Prob. 6PCh. 4 - An object takes 29.5 years to orbit the Sun. What...Ch. 4 -
One planet is three times farther from the Sun...Ch. 4 - Galileos telescope showed him that Venus has a...Ch. 4 - Which is the phase of Venus when it is closest?...Ch. 4 - Prob. 11PCh. 4 - Prob. 1SPCh. 4 - Prob. 2SPCh. 4 - Prob. 1LLCh. 4 - Prob. 2LLCh. 4 - What three astronomical objects are represented...Ch. 4 - Use the figure below to explain how the Ptolemaic...
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- Which of Keplers or Newtons laws best describes Aristotelean violent motions?arrow_forwardKepler's Third Law and Newton's Law of Universal Gravitation (a) Use Newton's Universal Law of Gravitation and what you know about centripetal acceleration/force to derive Kepler's Third Law for a planet in a circular orbit about the sun: T² = Kr³ K = constant = 4²/GM where T is the orbital period of the planet (the time for one complete orbit), r is the radius of the planet's orbit, M is the mass of the sun, and G is the universal gravitational constant. (b) Determine the metric system units of K and show that they make the units of T² – Kr³ work out correctly. (c) The earth orbits the sun once per year (365 days) and its average orbital radius is 1.50 x 10¹¹ m. Use this information and Kepler's Third Law to estimate the mass of the sun in kilograms. [answer: about 2 x 10³⁰ kg] (d) The radius of the sun is about 7 x 108 m. Use this radius and the mass of the sun estimated in part (c) to estimate the acceleration of an object near the surface of the sun. [answer: about 300 m/s²] F₂ =G…arrow_forward) A boy is flying a drone in a circular path at 35 miles per hour. If the drone is experiencing a centripetal acceleration of 0.70 m/s2, what is the diameter (in meters) of the circle that the boy’s drone is flying?arrow_forward
- Which of the following are, or follow directly from, Kepler's Laws of planetary motion? Check all that apply. More distant planets move at slower speeds. The force of attraction between any two objects decreases with the square of the distance between their centers. The orbit of each planet about the Sun is an ellipse with the Sun at one focus. A planet travels faster when it is nearer to the Sun and slower when it is farther from the Sun. As a planet moves around its orbit, it sweeps out equal areas in equal times.arrow_forwardExplain and analyse the simiilarities and difference between circular motion and planetary motion.arrow_forward1)The Moon takes 27.3 days to complete one revolution around the Earth (sidereal month). Assuming the orbit is circular with a radius of 3.85 × 108 m, calculate the centripetal acceleration experienced by the Moon. 2)A particle describes a circular trajectory with a radius of 0.4 m and its speed is constant. Knowing that it performs five revolutions per second, determine: -its speed. -its acceleration. 3)A hunter uses a stone held by a strap (sling) as a weapon to capture prey that strays from him. The stone rotates above him in a uniform circular motion 1.60 m in diameter, the frequency of which is three revolutions per second. -What is the centripetal acceleration of the stone? -How fast will the stone leave the slingshot? Ps: the picture is the first question answer.arrow_forward
- For circular orbits, relate Kepler’s third law of planetary motion to Newton’s law of gravitation and centripetal acceleration to the configuration system or any situational scenarios. Explain and justify. Cite an example to support your answer.arrow_forwardA planet is about 7.79 x 108 km (orbital radius) from the sun. It takes 1,425 days for the planet to go around its orbit (assume circular orbit). What is the orbital velocity in km/sec of the planet along its orbital path? What is its acceleration toward the sun in km/sec2? (Force attraction of sun = ma = mv2); r = orbital radius rarrow_forwardan object has a radius R and a velocity V and a mass M.What happens to centripetal when mass doubles, velocity doubles, radius is halvedarrow_forward
- Using Kepler's 3rd law, how long will it take a new planet that is 3.68 x 107 km to travel around the Earth?arrow_forwardWe found the centripetal acceleration of the Earth as it revolves around the Sun. Compute the centripetal acceleration of a point on the surface of the Earth at the equator caused by the rotation of the Earth about its axis. (Enter the magnitude. The radius of the Earth is 6,371 km.) m/s²arrow_forwardIf an airplane pilot is told to fly 123 km in a straight line to get from San Francisco to Sacramento, explain why he could end up anywhere on the circle shown in Figure 3.51. What other information would he need to get to Sacramento?arrow_forward
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