a) Explanation Using ideal gas equation of state to obtain the temperature of the refrigerant ( T ) . T = P v R (I) Here, pressure of the refrigerant − 134 a is P , specific volume of the refrigerant − 134 a is v , and gas constant of the refrigerant − 134 a is R . Conclusion: Refer Table A-1E, “Molar mass, gas constant, and critical-point properties”, obtain the gas constant of refrigerant − 134 a ( R ) as 0.1052 psia ⋅ ft 3 / lbm ⋅ R . Substitute 400 psia for P , 0.1384 ft 3 / lbm for v , and 0 b) To determine The temperature of the refrigerant using generalized compressibility chart. c) To determine The temperature of the refrigerant using the refrigerant tables.

8th Edition

ISBN: 9780073398174

Author: Yunus A. Cengel Dr., Michael A. Boles

Publisher: McGraw-Hill Education

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Chapter 3.8, Problem 81P

To determine

The temperature of the refrigerant using ideal gas equation.

To determine

The temperature of the refrigerant using generalized compressibility chart.

To determine

The temperature of the refrigerant using the refrigerant tables.

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Chapter 3.8, Problem 80P

Chapter 3.8, Problem 82P

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Thermodynamics: An Engineering Approach

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