Physics For Scientists And Engineers: Foundations And Connections, Extended Version With Modern Physics
Physics For Scientists And Engineers: Foundations And Connections, Extended Version With Modern Physics
1st Edition
ISBN: 9781305259836
Author: Debora M. Katz
Publisher: Cengage Learning
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 38, Problem 40PQ
To determine

The magnification of the vase and see whether the vase acts like a magnifying lens.

Expert Solution & Answer
Check Mark

Answer to Problem 40PQ

The magnification produced by the vase is 0.517 and the vase will not act like a magnifying lens as the total magnification is less than 1.

Explanation of Solution

Write the expression for spherical refracting surface.

    nid0+ntdi=ntniR

Here, d0 is the distance of the object, di is the distance of the image, R is the radius, nt is the refractive index of the light in refracted medium and ni is the refractive index of the light in incident medium.

Rearrange the above equation for di.

    ntdi=ntniRnid0di=ntntniRnid0

Write the expression to calculate the distance of the image for the first surface.

    di1=ntntniRnid01                                                                                         (I)

Here, d01 is the distance of the object for the first surface and di1 is the distance of the image for the first surface.

Write the expression to calculate the magnification for the first surface.

    M1=nintdi1d01                                                                                                     (II)

Here, M1 is the magnification for the first surface.

Write the expression to calculate the object distance for the second surface.

    d02=Ddi1                                                                                                       (III)

Here, d02 is the object distance for the second surface and D is the diameter of the vase.

Write the expression to calculate the image for the second surface.

    di2=ntntniRnid02                                                                                             (IV)

Here, di2 is the distance of the image for the second surface.

Write the expression to calculate the magnification for the second surface.

    M2=nintdi2d02                                                                                                     (V)

Here, M2 is the magnification for the second surface.

Write the expression to calculate the total magnification.

    M=M1×M2                                                                                                     (VI)

Conclusion:

Substitute 1.3 for ni, 1 for nt, 3.0cm for d01 and 6.0cm for R in equation (I) to find di1.

    di1=111.36.0cm1.33.0cm=2.07cm

Substitute 1 for nt, 1.3 for ni, 3.0cm for d01 and 2.07cm for di1 in equation (II) to find M1.

    M1=1.31(2.07cm3.0cm)=0.897

Substitute 12cm for D and 2.07cm for di1 in equation (III) to find d02.

    d02=12cm+2.07cm=14.07cm

Substitute 1 for ni, 1.33 for nt, 3.0cm for d02 and 6.0cm for R in equation (IV) to find di2

    di2=1.331.3316cm114.07cm=10.55cm

Substitute 1 for ni, 1.33 for nt, 14.07cm for d02 and 10.55cm for di2 in equation (V) to find M2.

    M2=11.3(10.55cm14.07cm)=0.577

Substitute 0.897 for M1 and 0.577 for M2 in equation (VI) to find M.

    M=0.897×0.577=0.517

Therefore, the magnification produced by the vase is 0.517 and the vase will not act like a magnifying lens as the total magnification is less than 1.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
Question B3 Consider the following FLRW spacetime: t2 ds² = -dt² + (dx² + dy²+ dz²), t2 where t is a constant. a) State whether this universe is spatially open, closed or flat. [2 marks] b) Determine the Hubble factor H(t), and represent it in a (roughly drawn) plot as a function of time t, starting at t = 0. [3 marks] c) Taking galaxy A to be located at (x, y, z) = (0,0,0), determine the proper distance to galaxy B located at (x, y, z) = (L, 0, 0). Determine the recessional velocity of galaxy B with respect to galaxy A. d) The Friedmann equations are 2 k 8πG а 4πG + a² (p+3p). 3 a 3 [5 marks] Use these equations to determine the energy density p(t) and the pressure p(t) for the FLRW spacetime specified at the top of the page. [5 marks] e) Given the result of question B3.d, state whether the FLRW universe in question is (i) radiation-dominated, (ii) matter-dominated, (iii) cosmological-constant-dominated, or (iv) none of the previous. Justify your answer. f) [5 marks] A conformally…
SECTION B Answer ONLY TWO questions in Section B [Expect to use one single-sided A4 page for each Section-B sub question.] Question B1 Consider the line element where w is a constant. ds²=-dt²+e2wt dx², a) Determine the components of the metric and of the inverse metric. [2 marks] b) Determine the Christoffel symbols. [See the Appendix of this document.] [10 marks] c) Write down the geodesic equations. [5 marks] d) Show that e2wt it is a constant of geodesic motion. [4 marks] e) Solve the geodesic equations for null geodesics. [4 marks]
Page 2 SECTION A Answer ALL questions in Section A [Expect to use one single-sided A4 page for each Section-A sub question.] Question A1 SPA6308 (2024) Consider Minkowski spacetime in Cartesian coordinates th = (t, x, y, z), such that ds² = dt² + dx² + dy² + dz². (a) Consider the vector with components V" = (1,-1,0,0). Determine V and V. V. (b) Consider now the coordinate system x' (u, v, y, z) such that u =t-x, v=t+x. [2 marks] Write down the line element, the metric, the Christoffel symbols and the Riemann curvature tensor in the new coordinates. [See the Appendix of this document.] [5 marks] (c) Determine V", that is, write the object in question A1.a in the coordinate system x'. Verify explicitly that V. V is invariant under the coordinate transformation. Question A2 [5 marks] Suppose that A, is a covector field, and consider the object Fv=AAμ. (a) Show explicitly that F is a tensor, that is, show that it transforms appropriately under a coordinate transformation. [5 marks] (b)…

Chapter 38 Solutions

Physics For Scientists And Engineers: Foundations And Connections, Extended Version With Modern Physics

Ch. 38 - Prob. 3PQCh. 38 - A light ray is incident on an interface between...Ch. 38 - Prob. 5PQCh. 38 - Prob. 6PQCh. 38 - Prob. 7PQCh. 38 - A ray of light enters a liquid from air. If the...Ch. 38 - Prob. 9PQCh. 38 - Figure P38.10 on the next page shows a...Ch. 38 - Prob. 11PQCh. 38 - Prob. 12PQCh. 38 - Prob. 13PQCh. 38 - Prob. 14PQCh. 38 - Prob. 15PQCh. 38 - A fish is 3.25 m below the surface of still water...Ch. 38 - N A fish is 3.25 m below the surface of still...Ch. 38 - A beam of monochromatic light within a fiber optic...Ch. 38 - Prob. 19PQCh. 38 - Prob. 20PQCh. 38 - Consider a light ray that enters a pane of glass...Ch. 38 - Prob. 22PQCh. 38 - Prob. 23PQCh. 38 - Prob. 24PQCh. 38 - Prob. 25PQCh. 38 - Prob. 26PQCh. 38 - Prob. 27PQCh. 38 - Prob. 28PQCh. 38 - The wavelength of light changes when it passes...Ch. 38 - Prob. 30PQCh. 38 - Light is incident on a prism as shown in Figure...Ch. 38 - Prob. 32PQCh. 38 - Prob. 33PQCh. 38 - Prob. 34PQCh. 38 - Prob. 35PQCh. 38 - Prob. 36PQCh. 38 - Prob. 37PQCh. 38 - A Lucite slab (n = 1.485) 5.00 cm in thickness...Ch. 38 - Prob. 39PQCh. 38 - Prob. 40PQCh. 38 - The end of a solid glass rod of refractive index...Ch. 38 - Prob. 42PQCh. 38 - Figure P38.43 shows a concave meniscus lens. If...Ch. 38 - Show that the magnification of a thin lens is...Ch. 38 - Prob. 45PQCh. 38 - Prob. 46PQCh. 38 - Prob. 47PQCh. 38 - The radius of curvature of the left-hand face of a...Ch. 38 - Prob. 49PQCh. 38 - Prob. 50PQCh. 38 - Prob. 51PQCh. 38 - Prob. 52PQCh. 38 - Prob. 53PQCh. 38 - Prob. 54PQCh. 38 - Prob. 55PQCh. 38 - Prob. 56PQCh. 38 - Prob. 57PQCh. 38 - Prob. 58PQCh. 38 - Prob. 59PQCh. 38 - Prob. 60PQCh. 38 - Prob. 61PQCh. 38 - Prob. 62PQCh. 38 - Prob. 63PQCh. 38 - Prob. 64PQCh. 38 - Prob. 65PQCh. 38 - Prob. 66PQCh. 38 - Prob. 67PQCh. 38 - Prob. 68PQCh. 38 - CASE STUDY Susan wears corrective lenses. The...Ch. 38 - A Fill in the missing entries in Table P38.70....Ch. 38 - Prob. 71PQCh. 38 - Prob. 72PQCh. 38 - Prob. 73PQCh. 38 - Prob. 74PQCh. 38 - An object 2.50 cm tall is 15.0 cm in front of a...Ch. 38 - Figure P38.76 shows an object placed a distance...Ch. 38 - Prob. 77PQCh. 38 - Prob. 78PQCh. 38 - Prob. 79PQCh. 38 - CASE STUDY A group of students is given two...Ch. 38 - A group of students is given two converging...Ch. 38 - Prob. 82PQCh. 38 - Two lenses are placed along the x axis, with a...Ch. 38 - Prob. 84PQCh. 38 - Prob. 85PQCh. 38 - Prob. 86PQCh. 38 - Prob. 87PQCh. 38 - Prob. 88PQCh. 38 - Prob. 89PQCh. 38 - Prob. 90PQCh. 38 - Prob. 91PQCh. 38 - Prob. 92PQCh. 38 - Prob. 93PQCh. 38 - Prob. 94PQCh. 38 - Prob. 95PQCh. 38 - Prob. 96PQCh. 38 - Prob. 97PQCh. 38 - A Fermats principle of least time for refraction....Ch. 38 - Prob. 99PQCh. 38 - Prob. 100PQCh. 38 - Prob. 101PQCh. 38 - Prob. 102PQCh. 38 - Prob. 103PQCh. 38 - Prob. 104PQCh. 38 - Curved glassair interfaces like those observed in...Ch. 38 - Prob. 106PQCh. 38 - Prob. 107PQCh. 38 - Prob. 108PQCh. 38 - Prob. 109PQCh. 38 - Prob. 110PQCh. 38 - Prob. 111PQCh. 38 - Prob. 112PQCh. 38 - Prob. 113PQCh. 38 - Prob. 114PQCh. 38 - The magnification of an upright image that is 34.0...Ch. 38 - Prob. 116PQCh. 38 - Prob. 117PQCh. 38 - Prob. 118PQCh. 38 - Prob. 119PQCh. 38 - Prob. 120PQCh. 38 - Prob. 121PQCh. 38 - Prob. 122PQCh. 38 - Prob. 123PQCh. 38 - Prob. 124PQCh. 38 - Prob. 125PQCh. 38 - Prob. 126PQCh. 38 - Light enters a prism of crown glass and refracts...Ch. 38 - Prob. 128PQCh. 38 - An object is placed a distance of 10.0 cm to the...
Knowledge Booster
Background pattern image
Physics
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning
Text book image
Physics for Scientists and Engineers
Physics
ISBN:9781337553278
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Text book image
Physics for Scientists and Engineers with Modern ...
Physics
ISBN:9781337553292
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Text book image
College Physics
Physics
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
Text book image
College Physics
Physics
ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
Text book image
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Convex and Concave Lenses; Author: Manocha Academy;https://www.youtube.com/watch?v=CJ6aB5ULqa0;License: Standard YouTube License, CC-BY