Electric Motor Control
10th Edition
ISBN: 9781305177611
Author: Herman
Publisher: Cengage
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Chapter 38, Problem 2SQ
To determine
Explain how the solid state adjustable speed controllers are compared with secondary resistor control.
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Electric Motor Control
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- Your objective is to obtain a Th´evenin equivalent for thecircuit shown in Fig. P7.46, given that is(t) = 3cos 4×104t A. Tothat end:(a) Transform the circuit to the phasor domain.(b) Apply the source-transformation technique to obtain theTh´evenin equivalent circuit at terminals (a,b). (c) Transform the phasor-domain Th´evenin circuit back to thetime domain.arrow_forward7.48 Determine the Thévenin equivalent of the circuit in Fig. P7.48 at terminals (a,b), given that Us(t) 12 cos 2500t V, = is(t)=0.5 cos (2500t - 30°) A.arrow_forwardPower system studies on an existing system have indicated that 2400 MW are to be transmitted for a distance of 400 Km. The voltage levels being considered include 345 kV, 500 kV, and 765 kV. For a preliminary design based on the practical line loadability, you may assume the following surge impedances 345 kV Zc=320 2 500 kV Zc=290 765 kV Zc=265 The line wavelength may be assumed to be 5000 km. The practical line loadability may be based on a load angle of 35º. Assume |Vs| = 1.0 pu and |Vr|=0.9 pu. a) Determine the number of three-phase transmission circuits required for each voltage level. Each transmission tower may have up to two circuits. To limit the corona loss, all 500-kV lines must have at least two conductors per phase, and all 765-kV lines must have at least four conductors per phase. b) The bundle spacing is 45 cm. The conductor size should be such that the line would be capable of carrying current corresponding to at least 5000 MVA. Determine the number of conductors in the…arrow_forward
- Don't use ai to answer I will report you answerarrow_forward2. If the Ce value in Fig. 11-7 is changed to 0.1 μF, is the output still a PWM waveform? Explain. C₁ 0.014 C₂ 100 R₁ 300 HF 8 Vcc 4 reset output 3 discharge 7 2 trigger 5 control voltage U₁ LM555 6 threshold GND ODUCT R₂ 10k ww Bo +12 V 22 R3 1k VR 5k www Re 300 C5 100 ww 8 Vcc 4 reset output 3 2 trigger 7 discharge ли R7 10k PWM Output threshold C6 -0.014 5 control voltage GND Rs 2k CA U2 LM555 1 100μ C3 0.01 Audio lutput Fig. 11-7 Pulse width modulatorarrow_forwardPROD 1. What is the function of VR, in Figs. 11-2 and 11-7. DL RO 0.014 +12V R₁ 1k ww Vin(+) 6 C₁ 0.1μ Audio input HH VRI Vin(-) 4 U1 HА741 10k ww R2 10k UCTS 0.01 μ -12V PWM output Fig. 11-2 The pulse width modulator based on μA741 +12 V ° C₂ 100 R₁ 300 Re 300 Cs 100 ww ww Vcc 4 reset 2 trigger 5 control voltage U₁ LM555 GND www R₂ T₁ 10k output 3 discharge Z Voc output 3 reset VR₁ 5k 2 trigger 7 discharge Ra 1k threshold 6 control 6 threshold voltage GND Rs CA U2 LM555 1 2k 100 Ca 0.01 Audio lutput www R7 10k O PWM C6 -0.014 Fig. 11-7 Pulse width modulator 11/9 Outputarrow_forward
- PRO3. In a point of view of voltage polarity, what is the difference between the output PWM signals in experiments 11-1 and 11-2? H ICTS Experiment 11-1.. Pulse Width Modulator Using uA741 Experiment 11-2 Pulse Width Modulator Using LM555arrow_forward9.58 Using Fig. 9.65, design a problem to help other ed students better understand impedance combinations. Figure 8 65 ww C L R₁ www R2arrow_forwardindicate which of the following switches may be used to control the loads listedarrow_forward
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