Explanation Given information : f ( x ) = x 4 + x 3 + 3 x Formula used : f ( x 0 + Δ x ) ≈ f ( x 0 ) + f ′ ( x 0 ) d x Calculation : Here, x 0 = 4096 and d x ≈ Δ x = 4 ⇒ f ( x 0 + Δ x ) = x 0 + Δ x 4 + x 0 + Δ x 3 + 3 x 0 + Δ x ⇒ x 0 + Δ x 4 + x 0 + Δ x 3 + 3 x 0 + Δ x ≈ x 0 4 + x 0 3 + 3 x 0 + d d x 0 ( x 0 4 + x 0 3 + 3 x 0 ) ⋅ d x ⇒ x 0 + Δ x 4 + x 0 + Δ x 3 + 3 x 0 + Δ x

6th Edition

ISBN: 9781465208880

Author: SMITH KARL J, STRAUSS MONTY J, TODA MAGDALENA DANIELE

Publisher: Kendall Hunt Publishing

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Chapter 3.8, Problem 22PS

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Chapter 3.8, Problem 21PS

Chapter 3.8, Problem 23PS

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Chapter 3 Solutions

Calculus

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value of 4100 4 + 4100 3 + 3 4100 .

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Chapter 3 Solutions