Calculus
6th Edition
ISBN: 9781465208880
Author: SMITH KARL J, STRAUSS MONTY J, TODA MAGDALENA DANIELE
Publisher: Kendall Hunt Publishing
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Chapter 3.1, Problem 58PS
To determine
The equation of the tangent line.
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Many of the geometric formulas that you've used in classes up to this point are can be derived through calculus. In this assignment, you will derive the general formula for the surface area of a sphere. In order to
make sure the details are clear, be sure to follow the steps precisely, as the process is broken into steps along the way.
So to frame what you're doing, the surface of a sphere can be through of as a rotational surface formed by taking a hemisphere and rotating it around an axis. Let's "center" the hemisphere over the origin, as pictured
below.
f (x) = Vr2 – x²
x = -r
x = r
If we rotate the above graph around the x-axis, the result is a sphere. This is exactly what you'll do in this assignment. Note here that r is the unspecified radius of the circle (an unspecified constant that will still be
present in our resulting formula).
Task:
1. Using the surface area integral form that we see in section 2.4, write the integral (with no simplification) that would give the surface…
Demonstrate your learning by formulating your own real-life problem and its corresponding solution. Create a situation, or story about it.
Focus your problem on the topics you have learned from module 5. Create only one problem.
Topics are:
"illustrating secants, tangents, segments, and sectors of a circle"
Just pick one.
3. A map projection is a set of equations used to visualize the surface of
the earth on a two-dimensional map. The act of displaying a curved surface on a flat
surface will always result in some sort of stretching, splitting or distortion. Think
about the challenges of flattening an orange peel!
The Mercator projection, proposed in 1569, is a very famous map projection. It was
very popular because of how useful it is as a navigational chart. Any straight line on
a Mercator map corresponds to a straight-line course - it makes it easy to cross an
осean.
The big problem with the Mercator projection is that scale is highly distorted. On
a Mercator map, areas far from the equator appear far larger than they actually are.
Have a look at the map below. It looks like Greenland is larger than Africa, but Africa
is actually 14 times larger.
In this question, we'll look at the math behind the Mercator projection. In this
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Chapter 3 Solutions
Calculus
Ch. 3.1 - Prob. 1PSCh. 3.1 - Prob. 2PSCh. 3.1 - Prob. 3PSCh. 3.1 - Prob. 4PSCh. 3.1 - Prob. 5PSCh. 3.1 - Prob. 6PSCh. 3.1 - Prob. 7PSCh. 3.1 - Prob. 8PSCh. 3.1 - Prob. 9PSCh. 3.1 - Prob. 10PS
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Prob. 1PSCh. 3.2 - Prob. 2PSCh. 3.2 - Prob. 3PSCh. 3.2 - Prob. 4PSCh. 3.2 - Prob. 5PSCh. 3.2 - Prob. 6PSCh. 3.2 - Prob. 7PSCh. 3.2 - Prob. 8PSCh. 3.2 - Prob. 9PSCh. 3.2 - Prob. 10PSCh. 3.2 - Prob. 11PSCh. 3.2 - Prob. 12PSCh. 3.2 - Prob. 13PSCh. 3.2 - Prob. 14PSCh. 3.2 - Prob. 15PSCh. 3.2 - Prob. 16PSCh. 3.2 - Prob. 17PSCh. 3.2 - Prob. 18PSCh. 3.2 - Prob. 19PSCh. 3.2 - Prob. 20PSCh. 3.2 - Prob. 21PSCh. 3.2 - Prob. 22PSCh. 3.2 - Prob. 23PSCh. 3.2 - Prob. 24PSCh. 3.2 - Prob. 25PSCh. 3.2 - Prob. 26PSCh. 3.2 - Prob. 27PSCh. 3.2 - Prob. 28PSCh. 3.2 - Prob. 29PSCh. 3.2 - Prob. 30PSCh. 3.2 - Prob. 31PSCh. 3.2 - Prob. 32PSCh. 3.2 - Prob. 33PSCh. 3.2 - Prob. 34PSCh. 3.2 - Prob. 35PSCh. 3.2 - Prob. 36PSCh. 3.2 - Prob. 37PSCh. 3.2 - Prob. 38PSCh. 3.2 - Prob. 39PSCh. 3.2 - Prob. 40PSCh. 3.2 - Prob. 41PSCh. 3.2 - Prob. 42PSCh. 3.2 - Prob. 43PSCh. 3.2 - Prob. 44PSCh. 3.2 - Prob. 45PSCh. 3.2 - Prob. 46PSCh. 3.2 - Prob. 47PSCh. 3.2 - Prob. 48PSCh. 3.2 - Prob. 49PSCh. 3.2 - Prob. 50PSCh. 3.2 - Prob. 51PSCh. 3.2 - 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Prob. 43PSCh. 3.3 - Prob. 44PSCh. 3.3 - Prob. 45PSCh. 3.3 - Prob. 46PSCh. 3.3 - Prob. 47PSCh. 3.3 - Prob. 48PSCh. 3.3 - Prob. 49PSCh. 3.3 - Prob. 50PSCh. 3.3 - Prob. 51PSCh. 3.3 - Prob. 52PSCh. 3.3 - Prob. 53PSCh. 3.3 - Prob. 54PSCh. 3.3 - Prob. 55PSCh. 3.3 - Prob. 56PSCh. 3.3 - Prob. 57PSCh. 3.3 - Prob. 58PSCh. 3.3 - Prob. 59PSCh. 3.3 - Prob. 60PSCh. 3.4 - Prob. 1PSCh. 3.4 - Prob. 2PSCh. 3.4 - Prob. 3PSCh. 3.4 - Prob. 4PSCh. 3.4 - Prob. 5PSCh. 3.4 - Prob. 6PSCh. 3.4 - Prob. 7PSCh. 3.4 - Prob. 8PSCh. 3.4 - Prob. 9PSCh. 3.4 - Prob. 10PSCh. 3.4 - Prob. 11PSCh. 3.4 - Prob. 12PSCh. 3.4 - Prob. 13PSCh. 3.4 - Prob. 14PSCh. 3.4 - Prob. 15PSCh. 3.4 - Prob. 16PSCh. 3.4 - Prob. 17PSCh. 3.4 - Prob. 18PSCh. 3.4 - Prob. 19PSCh. 3.4 - Prob. 20PSCh. 3.4 - Prob. 21PSCh. 3.4 - Prob. 22PSCh. 3.4 - Prob. 23PSCh. 3.4 - Prob. 24PSCh. 3.4 - Prob. 25PSCh. 3.4 - Prob. 26PSCh. 3.4 - Prob. 27PSCh. 3.4 - Prob. 28PSCh. 3.4 - Prob. 29PSCh. 3.4 - Prob. 30PSCh. 3.4 - Prob. 31PSCh. 3.4 - Prob. 32PSCh. 3.4 - Prob. 33PSCh. 3.4 - Prob. 34PSCh. 3.4 - Prob. 35PSCh. 3.4 - Prob. 36PSCh. 3.4 - Prob. 37PSCh. 3.4 - Prob. 38PSCh. 3.4 - Prob. 39PSCh. 3.4 - Prob. 40PSCh. 3.4 - Prob. 41PSCh. 3.4 - Prob. 42PSCh. 3.4 - Prob. 43PSCh. 3.4 - Prob. 44PSCh. 3.4 - Prob. 45PSCh. 3.4 - Prob. 46PSCh. 3.4 - Prob. 47PSCh. 3.4 - Prob. 48PSCh. 3.4 - Prob. 49PSCh. 3.4 - Prob. 50PSCh. 3.4 - Prob. 51PSCh. 3.4 - Prob. 52PSCh. 3.4 - Prob. 53PSCh. 3.4 - Prob. 54PSCh. 3.4 - Prob. 55PSCh. 3.4 - Prob. 56PSCh. 3.4 - Prob. 57PSCh. 3.4 - Prob. 58PSCh. 3.4 - Prob. 59PSCh. 3.4 - Prob. 60PSCh. 3.5 - Prob. 1PSCh. 3.5 - Prob. 2PSCh. 3.5 - Prob. 3PSCh. 3.5 - Prob. 4PSCh. 3.5 - Prob. 5PSCh. 3.5 - Prob. 6PSCh. 3.5 - Prob. 7PSCh. 3.5 - Prob. 8PSCh. 3.5 - Prob. 9PSCh. 3.5 - Prob. 10PSCh. 3.5 - Prob. 11PSCh. 3.5 - Prob. 12PSCh. 3.5 - Prob. 13PSCh. 3.5 - Prob. 14PSCh. 3.5 - Prob. 15PSCh. 3.5 - Prob. 16PSCh. 3.5 - Prob. 17PSCh. 3.5 - Prob. 18PSCh. 3.5 - Prob. 19PSCh. 3.5 - Prob. 20PSCh. 3.5 - Prob. 21PSCh. 3.5 - Prob. 22PSCh. 3.5 - Prob. 23PSCh. 3.5 - Prob. 24PSCh. 3.5 - Prob. 25PSCh. 3.5 - Prob. 26PSCh. 3.5 - Prob. 27PSCh. 3.5 - Prob. 28PSCh. 3.5 - Prob. 29PSCh. 3.5 - Prob. 30PSCh. 3.5 - Prob. 31PSCh. 3.5 - Prob. 32PSCh. 3.5 - Prob. 33PSCh. 3.5 - Prob. 34PSCh. 3.5 - Prob. 35PSCh. 3.5 - Prob. 36PSCh. 3.5 - Prob. 37PSCh. 3.5 - Prob. 38PSCh. 3.5 - Prob. 39PSCh. 3.5 - Prob. 40PSCh. 3.5 - Prob. 41PSCh. 3.5 - Prob. 42PSCh. 3.5 - Prob. 43PSCh. 3.5 - Prob. 44PSCh. 3.5 - Prob. 45PSCh. 3.5 - Prob. 46PSCh. 3.5 - Prob. 47PSCh. 3.5 - Prob. 48PSCh. 3.5 - Prob. 49PSCh. 3.5 - Prob. 50PSCh. 3.5 - Prob. 51PSCh. 3.5 - Prob. 52PSCh. 3.5 - Prob. 53PSCh. 3.5 - Prob. 54PSCh. 3.5 - Prob. 55PSCh. 3.5 - Prob. 56PSCh. 3.5 - Prob. 57PSCh. 3.5 - Prob. 58PSCh. 3.5 - Prob. 59PSCh. 3.5 - Prob. 60PSCh. 3.6 - Prob. 1PSCh. 3.6 - Prob. 2PSCh. 3.6 - Prob. 3PSCh. 3.6 - Prob. 4PSCh. 3.6 - Prob. 5PSCh. 3.6 - Prob. 6PSCh. 3.6 - Prob. 7PSCh. 3.6 - Prob. 8PSCh. 3.6 - Prob. 9PSCh. 3.6 - Prob. 10PSCh. 3.6 - Prob. 11PSCh. 3.6 - Prob. 12PSCh. 3.6 - Prob. 13PSCh. 3.6 - Prob. 14PSCh. 3.6 - Prob. 15PSCh. 3.6 - Prob. 16PSCh. 3.6 - Prob. 17PSCh. 3.6 - Prob. 18PSCh. 3.6 - Prob. 19PSCh. 3.6 - Prob. 20PSCh. 3.6 - Prob. 21PSCh. 3.6 - Prob. 22PSCh. 3.6 - Prob. 23PSCh. 3.6 - Prob. 24PSCh. 3.6 - Prob. 25PSCh. 3.6 - Prob. 26PSCh. 3.6 - Prob. 27PSCh. 3.6 - Prob. 28PSCh. 3.6 - Prob. 29PSCh. 3.6 - Prob. 30PSCh. 3.6 - Prob. 31PSCh. 3.6 - Prob. 32PSCh. 3.6 - Prob. 33PSCh. 3.6 - Prob. 34PSCh. 3.6 - Prob. 35PSCh. 3.6 - Prob. 36PSCh. 3.6 - Prob. 37PSCh. 3.6 - Prob. 38PSCh. 3.6 - Prob. 39PSCh. 3.6 - Prob. 40PSCh. 3.6 - Prob. 41PSCh. 3.6 - Prob. 42PSCh. 3.6 - Prob. 43PSCh. 3.6 - Prob. 44PSCh. 3.6 - Prob. 45PSCh. 3.6 - Prob. 46PSCh. 3.6 - Prob. 47PSCh. 3.6 - Prob. 48PSCh. 3.6 - Prob. 49PSCh. 3.6 - Prob. 50PSCh. 3.6 - Prob. 51PSCh. 3.6 - Prob. 52PSCh. 3.6 - Prob. 53PSCh. 3.6 - Prob. 54PSCh. 3.6 - Prob. 55PSCh. 3.6 - Prob. 56PSCh. 3.6 - Prob. 57PSCh. 3.6 - Prob. 58PSCh. 3.6 - Prob. 59PSCh. 3.6 - Prob. 60PSCh. 3.7 - Prob. 1PSCh. 3.7 - Prob. 2PSCh. 3.7 - Prob. 3PSCh. 3.7 - Prob. 4PSCh. 3.7 - Prob. 5PSCh. 3.7 - Prob. 6PSCh. 3.7 - Prob. 7PSCh. 3.7 - Prob. 8PSCh. 3.7 - Prob. 9PSCh. 3.7 - Prob. 10PSCh. 3.7 - Prob. 11PSCh. 3.7 - Prob. 12PSCh. 3.7 - Prob. 13PSCh. 3.7 - Prob. 14PSCh. 3.7 - Prob. 15PSCh. 3.7 - Prob. 16PSCh. 3.7 - Prob. 17PSCh. 3.7 - Prob. 18PSCh. 3.7 - Prob. 19PSCh. 3.7 - Prob. 20PSCh. 3.7 - Prob. 21PSCh. 3.7 - Prob. 22PSCh. 3.7 - Prob. 23PSCh. 3.7 - Prob. 24PSCh. 3.7 - Prob. 25PSCh. 3.7 - Prob. 26PSCh. 3.7 - Prob. 27PSCh. 3.7 - Prob. 28PSCh. 3.7 - Prob. 29PSCh. 3.7 - Prob. 30PSCh. 3.7 - Prob. 31PSCh. 3.7 - Prob. 32PSCh. 3.7 - Prob. 33PSCh. 3.7 - Prob. 34PSCh. 3.7 - Prob. 35PSCh. 3.7 - Prob. 36PSCh. 3.7 - Prob. 37PSCh. 3.7 - Prob. 38PSCh. 3.7 - Prob. 39PSCh. 3.7 - Prob. 40PSCh. 3.7 - Prob. 41PSCh. 3.7 - Prob. 42PSCh. 3.7 - Prob. 43PSCh. 3.7 - Prob. 44PSCh. 3.7 - Prob. 45PSCh. 3.7 - Prob. 46PSCh. 3.7 - Prob. 47PSCh. 3.7 - Prob. 48PSCh. 3.7 - Prob. 49PSCh. 3.7 - Prob. 50PSCh. 3.7 - Prob. 51PSCh. 3.7 - Prob. 52PSCh. 3.7 - Prob. 53PSCh. 3.7 - Prob. 54PSCh. 3.7 - Prob. 55PSCh. 3.7 - Prob. 56PSCh. 3.7 - Prob. 57PSCh. 3.7 - Prob. 58PSCh. 3.7 - Prob. 59PSCh. 3.7 - Prob. 60PSCh. 3.8 - Prob. 1PSCh. 3.8 - Prob. 2PSCh. 3.8 - Prob. 3PSCh. 3.8 - Prob. 4PSCh. 3.8 - Prob. 5PSCh. 3.8 - Prob. 6PSCh. 3.8 - Prob. 7PSCh. 3.8 - Prob. 8PSCh. 3.8 - Prob. 9PSCh. 3.8 - Prob. 10PSCh. 3.8 - Prob. 11PSCh. 3.8 - Prob. 12PSCh. 3.8 - Prob. 13PSCh. 3.8 - Prob. 14PSCh. 3.8 - Prob. 15PSCh. 3.8 - Prob. 16PSCh. 3.8 - Prob. 17PSCh. 3.8 - Prob. 18PSCh. 3.8 - Prob. 19PSCh. 3.8 - Prob. 20PSCh. 3.8 - Prob. 21PSCh. 3.8 - Prob. 22PSCh. 3.8 - Prob. 23PSCh. 3.8 - Prob. 24PSCh. 3.8 - Prob. 25PSCh. 3.8 - Prob. 26PSCh. 3.8 - Prob. 27PSCh. 3.8 - Prob. 28PSCh. 3.8 - Prob. 29PSCh. 3.8 - Prob. 30PSCh. 3.8 - Prob. 31PSCh. 3.8 - Prob. 32PSCh. 3.8 - Prob. 33PSCh. 3.8 - Prob. 34PSCh. 3.8 - Prob. 35PSCh. 3.8 - Prob. 36PSCh. 3.8 - Prob. 37PSCh. 3.8 - Prob. 38PSCh. 3.8 - Prob. 39PSCh. 3.8 - Prob. 40PSCh. 3.8 - Prob. 41PSCh. 3.8 - Prob. 42PSCh. 3.8 - Prob. 43PSCh. 3.8 - Prob. 44PSCh. 3.8 - Prob. 45PSCh. 3.8 - Prob. 46PSCh. 3.8 - Prob. 47PSCh. 3.8 - Prob. 48PSCh. 3.8 - Prob. 49PSCh. 3.8 - Prob. 50PSCh. 3.8 - Prob. 51PSCh. 3.8 - Prob. 52PSCh. 3.8 - Prob. 53PSCh. 3.8 - Prob. 55PSCh. 3.8 - Prob. 56PSCh. 3.8 - Prob. 57PSCh. 3.8 - Prob. 58PSCh. 3.8 - Prob. 59PSCh. 3.8 - Prob. 60PSCh. 3 - Prob. 1PECh. 3 - Prob. 2PECh. 3 - Prob. 3PECh. 3 - Prob. 4PECh. 3 - Prob. 5PECh. 3 - Prob. 6PECh. 3 - Prob. 7PECh. 3 - Prob. 8PECh. 3 - Prob. 9PECh. 3 - Prob. 10PECh. 3 - Prob. 11PECh. 3 - Prob. 12PECh. 3 - Prob. 13PECh. 3 - Prob. 14PECh. 3 - Prob. 15PECh. 3 - Prob. 16PECh. 3 - Prob. 17PECh. 3 - Prob. 18PECh. 3 - Prob. 19PECh. 3 - Prob. 20PECh. 3 - Prob. 21PECh. 3 - Prob. 22PECh. 3 - Prob. 23PECh. 3 - Prob. 24PECh. 3 - Prob. 25PECh. 3 - Prob. 26PECh. 3 - Prob. 27PECh. 3 - Prob. 28PECh. 3 - Prob. 29PECh. 3 - Prob. 30PECh. 3 - Prob. 1SPCh. 3 - Prob. 2SPCh. 3 - Prob. 3SPCh. 3 - Prob. 4SPCh. 3 - Prob. 5SPCh. 3 - Prob. 6SPCh. 3 - Prob. 7SPCh. 3 - Prob. 8SPCh. 3 - Prob. 9SPCh. 3 - Prob. 10SPCh. 3 - Prob. 11SPCh. 3 - Prob. 12SPCh. 3 - Prob. 13SPCh. 3 - Prob. 14SPCh. 3 - Prob. 15SPCh. 3 - Prob. 16SPCh. 3 - Prob. 17SPCh. 3 - Prob. 18SPCh. 3 - Prob. 19SPCh. 3 - Prob. 20SPCh. 3 - Prob. 21SPCh. 3 - Prob. 22SPCh. 3 - Prob. 23SPCh. 3 - Prob. 24SPCh. 3 - Prob. 25SPCh. 3 - Prob. 26SPCh. 3 - Prob. 27SPCh. 3 - Prob. 28SPCh. 3 - Prob. 29SPCh. 3 - Prob. 30SPCh. 3 - Prob. 31SPCh. 3 - Prob. 32SPCh. 3 - Prob. 33SPCh. 3 - Prob. 34SPCh. 3 - Prob. 35SPCh. 3 - Prob. 36SPCh. 3 - Prob. 37SPCh. 3 - Prob. 38SPCh. 3 - Prob. 39SPCh. 3 - Prob. 40SPCh. 3 - Prob. 41SPCh. 3 - Prob. 42SPCh. 3 - Prob. 43SPCh. 3 - Prob. 44SPCh. 3 - Prob. 45SPCh. 3 - Prob. 46SPCh. 3 - Prob. 47SPCh. 3 - Prob. 48SPCh. 3 - Prob. 49SPCh. 3 - Prob. 50SPCh. 3 - Prob. 51SPCh. 3 - Prob. 52SPCh. 3 - Prob. 53SPCh. 3 - Prob. 54SPCh. 3 - Prob. 55SPCh. 3 - Prob. 56SPCh. 3 - Prob. 57SPCh. 3 - Prob. 58SPCh. 3 - Prob. 59SPCh. 3 - Prob. 60SPCh. 3 - Prob. 61SPCh. 3 - Prob. 62SPCh. 3 - Prob. 63SPCh. 3 - Prob. 64SPCh. 3 - Prob. 65SPCh. 3 - Prob. 66SPCh. 3 - Prob. 67SPCh. 3 - Prob. 68SPCh. 3 - Prob. 69SPCh. 3 - Prob. 70SPCh. 3 - Prob. 71SPCh. 3 - 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- I need to find the distance of y in the diagram. I've been told that the radius of the circle is 100ft and that the angle theta is 30 degrees. I'm having a hard time setting up my equation. I'm trying to use the pythagorean theorem though I can't find a way to make all of variables in terms of a single variable. Since I know that in a 30-60-90 triangle the hypotuse is equal to 2t, the medium length leg is equal to t(radical 3) and the smallest leg is "t," I've tried setting up the following t=(100+x)/2 for the hypotnuse and t=((14+b)(radical 3))/3 for the meduim length leg. Though, I can't put this into the pythagorean theorem and solve it because I still have two unknown variables. Am I setting the problem up right?arrow_forwardMany smartphones are now able to use information sent out by GPS satellites (of which there are about nine overhead at any one time) in a similar way. Since the satellites are moving around in space, and therefore can’t be located on a two-dimensional map of the Earth, we now need to consider three-dimensional geometry. How many satellites are needed to be sure of the location of a smartphone? Explain your findingsarrow_forwardPer.: HIGH DIVE Activity The following problem is not the same as our HIGH DIVE PROBLEM, it merely allows you to practice calculating heights and distances in correlation with our problem. The dimensions of the Ferris Wheel in this problem are different than our High Dive problem! Add your work The Ferris Wheel Al and Betty have gone to the amusement park to ride on a Ferris wheel. The wheel in the park has a radius of 15 feet, and its center is 20 feet above ground level. Assume it takes 24 seconds to make a complete revolution. Name: You can describe the various positions in the cycle of the Ferris wheel in terms of the face of a clock, as indicated in the accompanying diagram. Think of Al and Betty's location as they ride as simply a point on the circumference of the wheel's circular path. That is, ignore the size of the Ferris wheel seats, Al and Betty's own heights, and so on. ANSWER THE FOLLOWING QUESTIONS. Complete any necessary work on a separate sheet of paper and attach to…arrow_forward
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- Activity no. 12 Solve the following problems. 1. Circle O and P are externally tangent. If the radius of a circle O is 12 cm and the radius of circle P Is 8 cm. How far is the center of circle O from the center of circle P.? 2. Circle Q and R are externally tangent. If the radius of circle Q is 10 cm and the diameter of circle R is 8 cm. How far is the center of circle Q from that of circle R ?arrow_forwardTopology, studies (among other things) the mathematical properties of knots, which have been familiar to the human race at least as long as most of the subject matter of geometry. Why was such a familiar object not studied mathematically until the twentieth century?arrow_forward(4) 16 cm If one of the diagonals of a quadrilateral is 25 units and offsets are drawn on to its diagonal are 14.5 units, 17.5 units then the area is (1) 32 units? (2) 36.25 są units (3) 400 sq. units (4) 1200 sq. units 2DE. If AB = 30 cm and Area = 120 cm2, then h1 ABCD is a parallelogram in which AB and h2 are = 2BC, DF : %3D F h2 A = 4 cm (2) hi = 8 cm, h2 (4) h1 = 12 cm, h2 (1) h1 = 40 m, h2 = 80 m 4 сm (3) h1 6 m, h2 = 4 marrow_forward
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