Physics For Scientists And Engineers With Modern Physics, 9th Edition, The Ohio State University
9th Edition
ISBN: 9781305372337
Author: Raymond A. Serway | John W. Jewett
Publisher: Cengage Learning
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Chapter 38, Problem 21P
To determine
The limiting angle of resolution when the microscope is dipped in oil.
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To increase the resolving power of a microscope, the object and the objective are immersed in oil (n = 1.5). If the limiting angle of resolution without the oil is 0.60 μrad, what is the limiting angle of resolution with the oil?
To increase the resolving power of a microscope, the object and the objective are immersed in oil (n = 1.5). If the limiting angle of resolution without the oil is 0.60 μrad, what is the limiting angle of resolution with the oil? Hint: The oil changes the wavelength of the light.
A particular person's pupil is 4.5 mm in diameter, and the person's normal‑sighted eye is most sensitive at a wavelength of 552 nm. What is angular resolution ?R of the person's eye, in radians?
Chapter 38 Solutions
Physics For Scientists And Engineers With Modern Physics, 9th Edition, The Ohio State University
Ch. 38.2 - Suppose the slit width in Figure 37.4 is made half...Ch. 38.2 - Prob. 38.2QQCh. 38.3 - Cats eyes have pupils that can be modeled as...Ch. 38.3 - Suppose you are observing a binary star with a...Ch. 38.4 - Ultraviolet light of wavelength 350 nm is incident...Ch. 38.6 - A polarizer for microwaves can be made as a grid...Ch. 38.6 - Prob. 38.7QQCh. 38 - Prob. 1OQCh. 38 - Prob. 2OQCh. 38 - Prob. 3OQ
Ch. 38 - Prob. 4OQCh. 38 - Prob. 5OQCh. 38 - Prob. 6OQCh. 38 - Prob. 7OQCh. 38 - Prob. 8OQCh. 38 - Prob. 9OQCh. 38 - Prob. 10OQCh. 38 - Prob. 11OQCh. 38 - Prob. 12OQCh. 38 - Prob. 1CQCh. 38 - Prob. 2CQCh. 38 - Prob. 3CQCh. 38 - Prob. 4CQCh. 38 - Prob. 5CQCh. 38 - Prob. 6CQCh. 38 - Prob. 7CQCh. 38 - Prob. 8CQCh. 38 - Prob. 9CQCh. 38 - Prob. 10CQCh. 38 - Prob. 11CQCh. 38 - Prob. 12CQCh. 38 - Prob. 1PCh. 38 - Prob. 2PCh. 38 - Prob. 3PCh. 38 - Prob. 4PCh. 38 - Prob. 5PCh. 38 - Prob. 6PCh. 38 - Prob. 7PCh. 38 - Prob. 8PCh. 38 - Prob. 9PCh. 38 - Prob. 10PCh. 38 - Prob. 11PCh. 38 - Coherent light of wavelength 501.5 nm is sent...Ch. 38 - Prob. 13PCh. 38 - Prob. 14PCh. 38 - Prob. 15PCh. 38 - Prob. 16PCh. 38 - Prob. 17PCh. 38 - Prob. 18PCh. 38 - What is the approximate size of the smallest...Ch. 38 - Prob. 20PCh. 38 - Prob. 21PCh. 38 - Prob. 22PCh. 38 - Prob. 23PCh. 38 - Prob. 24PCh. 38 - Prob. 25PCh. 38 - Prob. 26PCh. 38 - Consider an array of parallel wires with uniform...Ch. 38 - Prob. 28PCh. 38 - Prob. 29PCh. 38 - A grating with 250 grooves/mm is used with an...Ch. 38 - Prob. 31PCh. 38 - Prob. 32PCh. 38 - Light from an argon laser strikes a diffraction...Ch. 38 - Show that whenever white light is passed through a...Ch. 38 - Prob. 35PCh. 38 - Prob. 36PCh. 38 - Prob. 37PCh. 38 - Prob. 38PCh. 38 - Prob. 39PCh. 38 - Prob. 40PCh. 38 - Prob. 41PCh. 38 - Prob. 42PCh. 38 - Prob. 43PCh. 38 - Prob. 44PCh. 38 - Prob. 45PCh. 38 - Prob. 46PCh. 38 - Prob. 47PCh. 38 - Prob. 48PCh. 38 - Prob. 49PCh. 38 - Prob. 50PCh. 38 - Prob. 51PCh. 38 - Prob. 52PCh. 38 - Prob. 53APCh. 38 - Prob. 54APCh. 38 - Prob. 55APCh. 38 - Prob. 56APCh. 38 - Prob. 57APCh. 38 - Prob. 58APCh. 38 - Prob. 59APCh. 38 - Prob. 60APCh. 38 - Prob. 61APCh. 38 - Prob. 62APCh. 38 - Prob. 63APCh. 38 - Prob. 64APCh. 38 - Prob. 65APCh. 38 - Prob. 66APCh. 38 - Prob. 67APCh. 38 - Prob. 68APCh. 38 - Prob. 69APCh. 38 - Prob. 70APCh. 38 - Prob. 71APCh. 38 - Prob. 72APCh. 38 - Prob. 73APCh. 38 - Light of wavelength 632.8 nm illuminates a single...Ch. 38 - Prob. 75CPCh. 38 - Prob. 76CPCh. 38 - Prob. 77CPCh. 38 - Prob. 78CPCh. 38 - Prob. 79CP
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- A telescope can be used to enlarge the diameter of a laser beam and limit diffraction spreading. The laser beam is sent through the telescope in opposite the normal direction and can then be projected onto a satellite or the moon. (a) If this is done with the Mount Wilson telescope, producing a 2.54-m-diameter beam of 633-nm light, what is the minimum angular spread of the beam? (b) Neglecting atmospheric effects, what is the size of the spot this beam would make on the moon, assuming a lunar distance of 3.84108 m?arrow_forwardOn a bright clear day, you are at the top of a mountain and looking at a city 12 km away. There are two tall towers 20.0 m apart in the city. Can your eye resolve the two towers if the diameter of the pupil is 4.0 mm? If not, what should be the minimum magnification power of the telescope needed to resolve the two towers? In your calculations use 550 nm for the wavelength of the light.arrow_forwardTo increase the resolving power of a microscope, the object and the objective are immersed in oil (n = 1.5). If the limiting angle of resolution without the oil is 0.60 urad, what is the limiting angle of resolution with the oil? Hint: The oil changes the wavelength of the light. %3Darrow_forward
- What is the resolving power of a microscope with a 5 mm diameter objective and f = 9 mm for light with a wavelength of 550 nm?arrow_forwardLight of wavelength 589 nm is used to view an object under a microscope. If the aperture of the objective has a diameter of 0.9 cm, what is the limiting angle of resolution? If the light is in the visible range, what would be the maximum limit of resolution for this microscope?arrow_forwardWhat is the resolving power of a microscope (λ=550nm) with a 5-mm-diameter objective which has f= 9mm ?arrow_forward
- One important goal of astronomers is to have a telescope in space that can resolve planets like the earth orbiting other stars. If a planet orbits its star at a distance of 1.5 x 1011 m (the radius of the earth’s orbit around the sun) and the telescope has a mirror of diameter 8.0 m, how far from the telescope could the star and its planet be if the wavelength used was (a) 690 nm and (b) 1400 nm? Use the Rayleigh criterion and give your answers in light-years (1 ly = 9.46 x 1015 m).arrow_forwardWhat is the resolving power of a microscope (wavelength = 550 nm) with a 3.6 mm diameter objective which has a f = 11 mm?arrow_forwardOne important goal of astronomers is to have a telescope in space that can resolve planets like the earth orbiting other stars. If a planet orbits its star at a distance of 1.5 * 1011 m (the radius of the earth’s orbit around the sun) and the telescope has a mirror of diameter 8.0 m, how far from the telescope could the star and its planet be if the wavelength used was (a) 690 nm and (b) 1400 nm? Use the Rayleigh criterion and give your answers in light-years (1 ly = 9.46 * 1015 m).arrow_forward
- a) You look at the moon with a refracting telescope. What is the smallest detail you can see at the surface of the moon because of the diffraction limit of the spatial resolution due to of the aperture (the diameter of the aperture is D = 20 cm and the moon is at about d = 400 000 km from earth)?b) You now look at the stars in the sky with your telescope. The magnification and resolving power of the telescope do not allow you to resolve any details of those celestial objects: The image remains a point as it cannot be magnified enough. What could be the use of a telescope in this situation?arrow_forwardThe Hubble Space Telescope (HST) orbits Earth at an altitude of 613 km. It has an objective mirror that is 2.40 m in diameter. If the HST were to look down on Earth's surface (rather than up at the stars), what is the minimum separation of two objects that could be resolved using 549 nm light? [IVote: The HST is used only for astronomical work, but a (classified) number of similar telescopes are in orbit for spy purposes.]arrow_forwardThe resolution of the eye is ultimately limited by the pupil diameter. What is the smallest diameter spot the eye can produce on the retina if the pupil diameter is 2.41 mm? Assume light with a wavelength of λ = 550 nm. (Note: The distance from the pupil to the retina is 25.4 mm. In addition, the space between the pupil and the retina is filled with a fluid whose index of refraction is n = 1.336.)Hint: The size of the spot is twice the distance from the main axis to the first minimum.arrow_forward
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