Physics for Scientists and Engineers with Modern Physics, Technology Update
9th Edition
ISBN: 9781305401969
Author: SERWAY, Raymond A.; Jewett, John W.
Publisher: Cengage Learning
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Chapter 37, Problem 57AP
To determine
The distance to the first dark band above the mirror.
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67. Interference fringes are produced using Lloyd's mirror
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source. Find the vertical distance h of the source above
the reflecting surface.
Viewing
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·L
P
S
Mirror
Figure P37.67
The Michelson interferometer can be used to measure the index of refraction of a gas by placing an evacuated transparent tube in the light path along one arm of the device. Fringe shifts occur as the
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The walls of a soap bubble have about the same index of refraction as that of plain water, n = 1.33. There is air both inside and outside the bubble. What wavelength (in air) of visible light is most strongly reflected from a point on a soap bubble where its wall is 340. nm thick?
Note: Your answer is assumed to be reduced to the highest power possible.
Chapter 37 Solutions
Physics for Scientists and Engineers with Modern Physics, Technology Update
Ch. 37.2 - Which of the following causes the fringes in a...Ch. 37.3 - Using Figure 36.6 as a model, sketch the...Ch. 37.5 - One microscope slide is placed on top of another...Ch. 37 - Prob. 1OQCh. 37 - Four trials of Youngs double-slit experiment are...Ch. 37 - Suppose Youngs double-slit experiment is performed...Ch. 37 - Prob. 4OQCh. 37 - Prob. 5OQCh. 37 - Prob. 6OQCh. 37 - Prob. 7OQ
Ch. 37 - Prob. 8OQCh. 37 - Prob. 9OQCh. 37 - A film of oil on a puddle in a parking lot shows a...Ch. 37 - Prob. 1CQCh. 37 - Prob. 2CQCh. 37 - Prob. 3CQCh. 37 - Prob. 4CQCh. 37 - Prob. 5CQCh. 37 - Prob. 6CQCh. 37 - Prob. 7CQCh. 37 - Prob. 8CQCh. 37 - Prob. 9CQCh. 37 - Two slits are separated by 0.320 mm. A beam of...Ch. 37 - Prob. 2PCh. 37 - A laser beam is incident on two slits with a...Ch. 37 - Prob. 4PCh. 37 - Prob. 5PCh. 37 - Prob. 6PCh. 37 - Prob. 7PCh. 37 - Prob. 8PCh. 37 - Prob. 9PCh. 37 - Light with wavelength 442 nm passes through a...Ch. 37 - Prob. 11PCh. 37 - Prob. 12PCh. 37 - Prob. 13PCh. 37 - Prob. 14PCh. 37 - Prob. 15PCh. 37 - A student holds a laser that emits light of...Ch. 37 - Prob. 17PCh. 37 - Prob. 18PCh. 37 - Prob. 19PCh. 37 - Prob. 20PCh. 37 - Prob. 21PCh. 37 - Prob. 22PCh. 37 - Prob. 23PCh. 37 - Prob. 24PCh. 37 - Prob. 25PCh. 37 - Monochromatic coherent light of amplitude E0 and...Ch. 37 - Prob. 27PCh. 37 - Prob. 28PCh. 37 - Prob. 29PCh. 37 - Prob. 30PCh. 37 - Prob. 31PCh. 37 - Prob. 32PCh. 37 - Prob. 33PCh. 37 - Prob. 34PCh. 37 - Prob. 35PCh. 37 - Prob. 36PCh. 37 - Prob. 37PCh. 37 - Prob. 38PCh. 37 - When a liquid is introduced into the air space...Ch. 37 - Prob. 40PCh. 37 - Prob. 41PCh. 37 - Prob. 42PCh. 37 - Prob. 43PCh. 37 - Prob. 44PCh. 37 - Prob. 45APCh. 37 - Prob. 46APCh. 37 - Prob. 47APCh. 37 - Prob. 48APCh. 37 - Prob. 49APCh. 37 - Prob. 50APCh. 37 - Prob. 51APCh. 37 - In a Youngs interference experiment, the two slits...Ch. 37 - In a Youngs double-slit experiment using light of...Ch. 37 - Prob. 54APCh. 37 - Prob. 55APCh. 37 - Prob. 56APCh. 37 - Prob. 57APCh. 37 - Prob. 58APCh. 37 - Prob. 59APCh. 37 - Prob. 60APCh. 37 - Prob. 61APCh. 37 - Prob. 62APCh. 37 - Prob. 63APCh. 37 - Prob. 64APCh. 37 - Prob. 65APCh. 37 - Prob. 66APCh. 37 - Prob. 67APCh. 37 - Prob. 68APCh. 37 - Prob. 69APCh. 37 - Prob. 70APCh. 37 - Prob. 71CPCh. 37 - Prob. 72CPCh. 37 - Prob. 73CPCh. 37 - Prob. 74CPCh. 37 - Prob. 75CPCh. 37 - Prob. 76CP
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- Mirror M₁ in the figure below is moved through a displacement AL. During this displacement, 248 fringe reversals (formation of successive dark or bright bands) are counted. The light being used has a wavelength of 631.4 nm. Calculate the displacement AL. μm A single ray of light is split into two rays by mirror Mo, which is called a beam splitter. Telescope As M₁ is moved, an interference pattern changes in the field of view. Light source L₂ M₂ Mo 4₁ The path difference between the two rays is varied with the adjustable mirror M₁. M₁arrow_forwardWe consider a Newton's rings experiment. It consists of a plano-convex glass lens of index of refractionn = 1.50 and radius r = 5.08 cm placed on a flat plate, as shown. When light of wavelength 636 nm is incident normally, 54 bright rings are observed, with the last one precisely on the edge of the lens. R a. What is the thickness t of the air layer at the edge of the lens? This corresponds to the maximum distance between the curved surface and the flat plate. um b. What is the radius of curvature R of the convex surface of the lens? m c. What is the focal length of the lens? Hint: use the lens maker equation. marrow_forwardA plano-concave lens having index of refraction 1.50 is placed on a flat glass plate as shown in Figure P36.39. Its curved surface, with radius of curvature 8.00 m, is on the bottom. The lens is illuminated from above with yellow sodium light of wavelength 589 nm, and a series of concentric bright and dark rings is observed by reflection. The interference pattern has a dark spot at the center that is surrounded by 50 dark rings, the largest of which is at the outer edge of the lens. (a) What is the thickness of the air layer at the center of the interference pattern? (b) Calculate the radius of the outermost dark ring. (c) Find the focal lengthof the lens.arrow_forward
- A thin film of oil (no=1.50) with varying thickness floats on water (nw=1.33). When it is illuminated from above by white light, the reflected colors are as shown in the figure. In air, the wavelength of yellow light is 580nm. What is the oil's thickness t at point B?arrow_forward4. a. Determine the size of the Airy disk (in m) found at the center of a 4.00-cm diameter lens, with a focal length of 15.0 cm. Assume the incident light wavelength is the middle of the visible spectrum = 550. nm. b. In observational astronomy, we assume that stars, being so far away, are point sources of light, and that the image of a star in a telescope eyepiece is therefore also a point. Given that the average human near-field resolution is 0.10 mm, does your result in part a justify this assumption? Explain your answer, using the value from part a. c. Assume that the objective lens diffraction limit is the only one that matters on a telescope (actually a good assumption, not justified here). What is the angular size (in radians) of the smallest object that can be truly observed as a disk on the 4.00-cm telescope in part a? Can Jupiter (maximum angular size = 51 arc-seconds) be seen as a disk through this telescope? Note that real telescopes have glass or mirror imperfections which…arrow_forward35. Figure P36.35 shows a radio-wave transmitter and a receiver separated by a distance d - 50.0 m and both a distance A - 35.0 m above the ground. The receiver can receive sig- nals both directly from the transmitter and indirectly from signals that reflect from the ground. Assume the ground is level between the transmitter and receiver and a 180° phase shift occurs upon reflection. Determine the longest wave- lengths that interfere (a) constructively and (b) destructively. Transmitter Recriver Figure P36.35 Problems 35 and 36.arrow_forward
- One way to determine the index of refraction of a gas is to use an interferometer. As shown below, one of the beams of an interferometer passes through a glass container that has a length of L = 1.8 cm. Initially the glass container is a vacuum. When gas is slowly allowed into the container, a total of 6894 dark fringes move past the reference line. The laser has a wavelength of 635 nm (this is the wavelength when the light from the laser is moving through a vacuum). A.) Determine how many wavelengths will fit into the glass container when it is a vacuum. Since the light passes through the container twice, you need to determine how many wavelengths will fit into a glass container that has a length of 2L.number of wavelengths (vacuum) = B.) The number of dark fringes is the difference between the number of wavelengths that fit in the container (length of 2L) when it has gas and the number of wavelengths that fit in the container (length of 2L) when it is a vacuum. Use this knowledge to…arrow_forwardWhite light illuminates a thin film (n-1.56) on glass (n-1.48) to produce a reflected maxima at the same colour of light as the laser. What are the two smallest possible thicknesses of the film. The same laser shines on a glass equilateral triangular prism (n=1.44) with an incident angle of 30°. If the prism is in water (n=1.33), then at what angle does the laser light exit the prism? (arrow_forwardTwo flat glass plates are separated by a distance d = 123 nm. There is a layer of oil between the plates. White light shines directly down on the glass. One ray reflects off the top surface of the top oil layer, and a second ray reflects off the bottom surface of the oil layer. The index of refraction of the glass is na = 1.49, and the index of refraction of the oil is no = 1.25. glass glass a. For each ray state whether there is a ½2 phase change, or no phase change. ONLY 1 ATTEMPT IS ALLOWED FOR EACH. Ray 1: ---Select--- Ray 2: ---Select--- b. What is the extra path length that Ray 2 must travel in the oil? nm c. What is the longest wavelength of light in a vacuum which will give constructive interference for these two reflected rays? nmarrow_forward
- = 35. Figure P36.35 shows a radio-wave transmitter and a receiver separated by a distance d 50.0 m and both a distance h = 35.0 m above the ground. The receiver can receive sig- nals both directly from the transmitter and indirectly from signals that reflect from the ground. Assume the ground is level between the transmitter and receiver and a 180° phase shift occurs upon reflection. Determine the longest wave- lengths that interfere (a) constructively and (b) destructively. h Transmitter d Receiver Figure P36.35 Problems 35 and 36.arrow_forwardOne way to determine the index of refraction of a gas is to use an interferometer. As shown below, one of the beams of an interferometer passes through a glass container that has a length of L = 1.8 cm. Initially the glass container is a vacuum. When gas is slowly allowed into the container, a total of 7571 dark fringes move past the reference line. The laser has a wavelength of 687 nm (this is the wavelength when the light from the laser is moving through a vacuum). Laser Mirror Glass Container Beam Splitter Diffraction Pattern Mirror A.) Determine how many wavelengths will fit into the glass container when it is a vacuum. Since the light passes through the container twice, you need to determine how many wavelengths will fit into a glass container that has a length of 2L. number of wavelengths (vacuum) = B.) The number of dark fringes is the difference between the number of wavelengths that fit in the container (length of 2L) when it has gas and the number of wavelengths that fit in…arrow_forward|37. An air wedge is formed between two glass plates sepa- M rated at one edge by a very fine wire of circular cross section as shown in Figure P37.37. When the wedge is illuminated from above by 600-nm light and viewed from above, 30 dark fringes are observed. Calculate the diameter d of the wire. Figure P37.37 Problems 37, 41, 49, and 59.arrow_forward
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