Physics for Scientists and Engineers with Modern Physics, Technology Update
9th Edition
ISBN: 9781305401969
Author: SERWAY, Raymond A.; Jewett, John W.
Publisher: Cengage Learning
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Chapter 37, Problem 55AP
To determine
The surface area of the ocean the oil slick cover.
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A glass sheet is covered by a very thin opaque coating. In the middle of this sheet there is a thin scratch 0.00125 mm thick. The sheet is totally immersed beneath the surface of a liquid. Parallel rays of monochromatic coherent light with wavelength 612 nm in air strike the sheet perpendicular to its surface and pass through the scratch. A screen is placed in the liquid a distance of 30.0 cm away from the sheet and parallel to it. You observe that the first dark fringes on either side of the central bright fringe on the screen are 22.4 cm apart. What is the refractive index of the liquid?
One way to determine the index of refraction of a gas is to use an interferometer. As shown below, one of the beams of an interferometer passes through a glass container that has a length of L = 1.8 cm. Initially the glass container is a vacuum. When gas is slowly allowed into the container, a total of 6894 dark fringes move past the reference line. The laser has a wavelength of 635 nm (this is the wavelength when the light from the laser is moving through a vacuum).
A.) Determine how many wavelengths will fit into the glass container when it is a vacuum. Since the light passes through the container twice, you need to determine how many wavelengths will fit into a glass container that has a length of 2L.number of wavelengths (vacuum) =
B.) The number of dark fringes is the difference between the number of wavelengths that fit in the container (length of 2L) when it has gas and the number of wavelengths that fit in the container (length of 2L) when it is a vacuum. Use this knowledge to…
One way to determine the index of refraction of a gas is to use an interferometer. As shown below, one of the beams of an interferometer passes through a glass container that has a length of L = 1.8 cm. Initially the
glass container is a vacuum. When gas is slowly allowed into the container, a total of 7571 dark fringes move past the reference line. The laser has a wavelength of 687 nm (this is the wavelength when the light from
the laser is moving through a vacuum).
Laser
Mirror
Glass Container
Beam Splitter
Diffraction Pattern
Mirror
A.) Determine how many wavelengths will fit into the glass container when it is a vacuum. Since the
light passes through the container twice, you need to determine how many wavelengths will fit into a
glass container that has a length of 2L.
number of wavelengths (vacuum) =
B.) The number of dark fringes is the difference between the number of wavelengths that fit in the
container (length of 2L) when it has gas and the number of wavelengths that fit in…
Chapter 37 Solutions
Physics for Scientists and Engineers with Modern Physics, Technology Update
Ch. 37.2 - Which of the following causes the fringes in a...Ch. 37.3 - Using Figure 36.6 as a model, sketch the...Ch. 37.5 - One microscope slide is placed on top of another...Ch. 37 - Prob. 1OQCh. 37 - Four trials of Youngs double-slit experiment are...Ch. 37 - Suppose Youngs double-slit experiment is performed...Ch. 37 - Prob. 4OQCh. 37 - Prob. 5OQCh. 37 - Prob. 6OQCh. 37 - Prob. 7OQ
Ch. 37 - Prob. 8OQCh. 37 - Prob. 9OQCh. 37 - A film of oil on a puddle in a parking lot shows a...Ch. 37 - Prob. 1CQCh. 37 - Prob. 2CQCh. 37 - Prob. 3CQCh. 37 - Prob. 4CQCh. 37 - Prob. 5CQCh. 37 - Prob. 6CQCh. 37 - Prob. 7CQCh. 37 - Prob. 8CQCh. 37 - Prob. 9CQCh. 37 - Two slits are separated by 0.320 mm. A beam of...Ch. 37 - Prob. 2PCh. 37 - A laser beam is incident on two slits with a...Ch. 37 - Prob. 4PCh. 37 - Prob. 5PCh. 37 - Prob. 6PCh. 37 - Prob. 7PCh. 37 - Prob. 8PCh. 37 - Prob. 9PCh. 37 - Light with wavelength 442 nm passes through a...Ch. 37 - Prob. 11PCh. 37 - Prob. 12PCh. 37 - Prob. 13PCh. 37 - Prob. 14PCh. 37 - Prob. 15PCh. 37 - A student holds a laser that emits light of...Ch. 37 - Prob. 17PCh. 37 - Prob. 18PCh. 37 - Prob. 19PCh. 37 - Prob. 20PCh. 37 - Prob. 21PCh. 37 - Prob. 22PCh. 37 - Prob. 23PCh. 37 - Prob. 24PCh. 37 - Prob. 25PCh. 37 - Monochromatic coherent light of amplitude E0 and...Ch. 37 - Prob. 27PCh. 37 - Prob. 28PCh. 37 - Prob. 29PCh. 37 - Prob. 30PCh. 37 - Prob. 31PCh. 37 - Prob. 32PCh. 37 - Prob. 33PCh. 37 - Prob. 34PCh. 37 - Prob. 35PCh. 37 - Prob. 36PCh. 37 - Prob. 37PCh. 37 - Prob. 38PCh. 37 - When a liquid is introduced into the air space...Ch. 37 - Prob. 40PCh. 37 - Prob. 41PCh. 37 - Prob. 42PCh. 37 - Prob. 43PCh. 37 - Prob. 44PCh. 37 - Prob. 45APCh. 37 - Prob. 46APCh. 37 - Prob. 47APCh. 37 - Prob. 48APCh. 37 - Prob. 49APCh. 37 - Prob. 50APCh. 37 - Prob. 51APCh. 37 - In a Youngs interference experiment, the two slits...Ch. 37 - In a Youngs double-slit experiment using light of...Ch. 37 - Prob. 54APCh. 37 - Prob. 55APCh. 37 - Prob. 56APCh. 37 - Prob. 57APCh. 37 - Prob. 58APCh. 37 - Prob. 59APCh. 37 - Prob. 60APCh. 37 - Prob. 61APCh. 37 - Prob. 62APCh. 37 - Prob. 63APCh. 37 - Prob. 64APCh. 37 - Prob. 65APCh. 37 - Prob. 66APCh. 37 - Prob. 67APCh. 37 - Prob. 68APCh. 37 - Prob. 69APCh. 37 - Prob. 70APCh. 37 - Prob. 71CPCh. 37 - Prob. 72CPCh. 37 - Prob. 73CPCh. 37 - Prob. 74CPCh. 37 - Prob. 75CPCh. 37 - Prob. 76CP
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- Both sides of a uniform film that has index of refraction n and thickness d are in contact with air. For normal incidence of light, an intensity minimum is observed in the reflected light at λ2 and an intensity maximum is observed at λ1, where λ1 > λ2. (a) Assuming no intensity minima are observed between λ1 and λ2, find an expression for the integer m in Equations 27.13 and 27.14 in terms of the wavelengths λ1 and λ2. (b) Assuming n = 1.40, λ1 = 500 nm, and λ2 = 370 nm, determine the best estimate for the thickness of the film.arrow_forwardA beam of 580-nm light passes through two closely spaced glass plates at close to normal incidence as shown in Figure P27.23. For what minimum nonzero value of the plate separation d is the transmitted light bright?arrow_forwardTo save money on making military aircraft invisible to radar, an inventor decides to coat them with a nonreflective material having an index of refraction of 1.20, which is between that of air and the surface of the plane. This, he reasons, should be much cheaper than designing Stealth bombers. (a) What thickness should the coating be to inhibit the reflection of 4.00-cm wavelength radar? (b) What is unreasonable about this result? (c) Which assumptions are unreasonable or inconsistent?arrow_forward
- A Fraunhofer diffraction pattern is produced on a screen located 1.00 m from a single slit. If a light source of wavelength 5.00 107 m is used and the distance from the center of the central bright fringe to the first dark fringe is 5.00 103 m, what is the slit width? (a) 0.010 0 mm (b) 0.100 mm (c) 0.200 mm (d) 1.00 mm (e) 0.005 00 mmarrow_forwardTwo polarizing sheets P1 and P2 are placed together with their transmission axes oriented at an angle to each other. What is when only 25% of the maximum transmitted light intensity passes through them?arrow_forwardA thin layer of oil with index of refraction no = 1.47 is floating above the water. The index of refraction of water is nw = 1.3. The index of refraction of air is na = 1. A light with wavelength λ = 325 nm goes in from the air to oil and water. Part (a) Express the wavelength of the light in the oil, λo, in terms of λ and no. Part (b) Express the minimum thickness of the film that will result in destructive interference, tmin, in terms of λo. Part (c) Express tmin in terms of λ and no. Part (d) Solve for the numerical value of tmin in nm.arrow_forward
- Red light having a wavelength of 690 nm (in air) is vertically incident on a thin film of oil that has an index of refraction of 1.19. The film of oil floats above water (having an index of refraction of 1.30). The red light is brightly reflected. The minimum (nonzero) thickness of the film of oil is 580 nm. 145 nm. 290 nm. 345 nm.arrow_forwardWhat visible wave length will be reflected in this scenario: A 700 nm thick soap film floats on a plate. From the air, white light is struck onto the film at a normal incidence. the wavelength of visible light to air is 400 nm to 700 nm. The index of the soap film is 1.74 and 1.58 for the plate.arrow_forwardA broad beam of light of wavelength 600 nm is sent directly downward through the glass plate (n = 1.41). That plate and a plastic plate (n = 1.24) form a thin wedge of air that acts as a thin film. An observer looking down through the top plate sees the fringe pattern, with 7 dark fringes, having two centered on the ends. (a) What is the thickness (in m) of wedge at the right end? (b) How many dark fringes will the observer see if the air between the plates is replaced with a liquid with n = 1.35?arrow_forward
- A glass sheet 0.870 μm thick is suspended in air with white light incident perpendicularly on the sheet. In reflected light, there are gaps in the visible spectrum at 498.8 nm and 665.0 nm. Calculate the minimum value of the index of refraction ? of the glass sheet that would produce this effect.arrow_forwardThe Michelson interferometer can be used to measure the index of refraction of a gas by placing an evacuated transparent tube in the light path along one arm of the device. Fringe shifts occur as the gas is slowly added to the tube. Assume 610-nm light is used, the tube is 5.40 cm long, and 168 bright fringes pass on the screen as the pressure of the gas in the tube increases to atmospheric pressure. What is the index of refraction of the gas? Hint: The fringe shifts occur because the wavelength of the light changes inside the gas-filled tube. (Give your answer to at least five decimal places.)arrow_forwardA laboratory dish, 20 cm in diameter, is half filled with water. One at a time, 0.48 µL drops of oil from a micropipette are dropped onto the surface of the water, where they spread out into a uniform thin film. After the first drop is added, the intensity of 610 nm light reflected from the surface is very low. As more drops are added, the reflected intensity increases, then decreases again to a minimum after a total of 13 drops have been added. Part A What is the index of refraction of the oil? Hνα ΑΣφ ? Noil = Submit Request Answerarrow_forward
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