Electric Motor Control
10th Edition
ISBN: 9781133702818
Author: Herman
Publisher: CENGAGE L
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Textbook Question
Chapter 36, Problem 9SQ
Why is it necessary to remove the jumpers in Figure 36–2 if limit switches are used?
FIG. 36–2 Typical elementary diagram of a starter with two points of acceleration for a reversing wound rotor motor.
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Using the 802.11a specifications given below, in Matlab (or similar tool) create the time domain signal
for one OFDM symbol using QPSK modulation. See attached plot for the QPSK constellation.
Your results should include the power measure in the time and frequency domain and comment on
those results.
BW
802.11a OFDM PHY Parameters
20 MHZ
OBW
Subcarrer Spacing
Information Rate
Modulation
Coding Rate
Total Subcarriers
Data Subcarriers
Pilot Subcarriers
DC Subcarrier
16.6 MHZ
312.5 Khz (20MHz/64 Pt FFT)
6/9/12/18/24/36/48/54 Mbits/s
BPSK, QPSK, 16QAM, 64QAM
1/2, 2/3, 3/4
52 (Freq Index -26 to +26)
48
4 (-21, -7, +7, +21)
*Always BPSK
Null (0 subcarrier)
52 subarriers
-7
(48 Data, 4 Pilot (BPSK), 1 Null)
-26 -21
0
7
21 +26
14
One Subcarrier
1 OFDM symbol
1 OFDM Burst
-OBW 16.6 MHz
BW 20 MHZ
1 constellation point
= 52 subcarriers
= one or more OFDM symbols
802.11a OFDM Physical Parameters
Show signal at this point
x bits
do
Serial
Data
d₁
S₁
Serial-to-
Input
Signal
Parallel
Converter
IFFT…
Find Vb and Va using Mesh analysis
1. The communication channel bandwidth is 25 MHz centered at 1GHz and has a noise power spectral
density of 10^-9 W/Hz. The channel loss between the transmitter and receiver is 25dB. The application
requires a bit rate of 200Mbps and BER of less than 10^-4. Excluding Mary FSK, Determine the minimum
transmit power required.
Chapter 36 Solutions
Electric Motor Control
Ch. 36 - Are the secondary resistors connected in three...Ch. 36 - Do secondary resistors on starters with three or...Ch. 36 - Does reversing the secondary rotor leads mean that...Ch. 36 - If one of the secondary resistor contacts (S2)...Ch. 36 - In Figure 362, how many different interlocking...Ch. 36 - Referring to Figure 364, why is it not possible to...Ch. 36 - Prob. 7SQCh. 36 - If there is a locked rotor in the secondary...Ch. 36 - Why is it necessary to remove the jumpers in...Ch. 36 - Prob. 10SQ
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