Explanation 1) Concept: Determine path difference of the incidence ray and diffracted ray. The minimum path difference between adjacent rays is equal to wavelength λ . 2) Formula: ∆ x = d s i n ψ + d s i n θ 3) Given: i) incidence angle ψ ii) Diffraction angle θ iii) Grating distance d 4) Calculation: Consider two rays from the given figure; the path difference is d s i n ψ for the incidence ray and d s i n θ for the diffracted wave. Hence total path difference ∆ x between adjacent rays can be determined as ∆ x = d s i n ψ + d s i n θ The minimum path difference occurring at adjacent bottom and top rays is of wavelength λ

10th Edition

ISBN: 9781118230718

Author: David Halliday

Publisher: Wiley, John & Sons, Incorporated

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Chapter 36, Problem 81P

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The bright fringes occurring at angles θ that satisfy the equation d(sin⁡ψ+sin⁡θ)=mλ

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Chapter 36, Problem 80P

Chapter 36, Problem 82P

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Chapter 36 Solutions

Fundamentals of Physics

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The bright fringes occurring at angles θ that satisfy the equation d ( sin ⁡ ψ + sin ⁡ θ ) = m λ

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To show: The bright fringes occurring at angles θ that satisfy the equation d(sin⁡ψ+sin⁡θ)=mλ

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Chapter 36 Solutions

To show:

The bright fringes occurring at angles θ that satisfy the equation d(sin⁡ψ+sin⁡θ)=mλ