Explanation 1) Concept: First we have to calculate the angle of incidence on the reflection plane. By using the angle of incidence on the reflection plane in the Bragg’s diffraction condition, we can calculate the interplanar spacing. Then by using the relation for the interplanar distance of unit cell, we can find the unit cell size. 2) Formula: i) 2 d sin ⁡ θ = m λ ii) d = a 0 h 2 + k 2 3) Given: i) λ = 0.260 n m ii) θ ' = 63.8 ° iii) m = 1 4) Calculations: Since the x-ray beam makes an angle 63.8° with the top face of the crystal, we can calculate the angle of incidence on the reflection plane. θ = θ ' - 45 θ = 63.8 0 - 45 0 θ = 18.8 ° Now, Bragg’s diffraction condition is 2 d sin ⁡ θ = m λ Rearranging the equation, d = m λ 2 sin ⁡ θ For first order reflection, m = 1 ; therefore, substituting the given values, d = 0

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Author: David Halliday

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Chapter 36, Problem 70P

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The unit cell size a0

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Chapter 36, Problem 69P

Chapter 36, Problem 71P

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Chapter 36 Solutions

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The unit cell size a 0

Solution Summary: The author explains how the x-ray beam makes an angle 63.8° with the top face of the crystal, and calculates the angle of incidence on the reflection plane.

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To find:

The unit cell size a0

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Chapter 36 Solutions

The unit cell size a 0

Solution Summary: The author explains how the x-ray beam makes an angle 63.8° with the top face of the crystal, and calculates the angle of incidence on the reflection plane.

Concept explainers

To find: The unit cell size a0

Want to see the full answer?

Chapter 36 Solutions

To find:

The unit cell size a0