“If…else” statement: The statements under the “if” block gets executed only if the “if” condition is true. Otherwise, the statements under “else” part gets executed. The statements inside the “if” condition or “else” condition are enclosed within the opening and closing braces. Syntax: //If condition if (condition) { //Statements } //Else part else { //Statements } “compareTo ()” method: The string class contains the method called “compareTo ()” which is used to compare two strings. This can be done inside the “if” condition. Syntax: //Checking if both the strings are same if (string1.compareTo(string2)==0) { //Statements }

Question

Want to see the full answer?

Answer 1

Question

Chapter 3.6, Problem 3.21CP

Program Plan Intro

“If…else” statement:

The statements under the “if” block gets executed only if the “if” condition is true. Otherwise, the statements under “else” part gets executed.

The statements inside the “if” condition or “else” condition are enclosed within the opening and closing braces.

Syntax:

//If condition

if (condition)

{

//Statements

}

//Else part

else

{

//Statements

}

“compareTo ()” method: The string class contains the method called “compareTo ()” which is used to compare two strings. This can be done inside the “if” condition.

Syntax:

//Checking if both the strings are same

if (string1.compareTo(string2)==0)

{

//Statements

}

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Exercise docID document text docID document text 1 hot chocolate cocoa beans 7 sweet sugar 2345 9 cocoa ghana africa 8 sugar cane brazil beans harvest ghana 9 sweet sugar beet cocoa butter butter truffles sweet chocolate 10 sweet cake icing 11 cake black forest Clustering by k-means, with preprocessing tokenization, term weighting TFIDF. Manhattan Distance. Number of cluster is 2. Centroid docID 2 and docID 9.

Change the following code so that there is always at least one way to get from the left corner to the top right, but the labyrinth is still randomized. The player starts at the bottom left corner of the labyrinth. He has to get to the top right corner of the labyrinth as fast he can, avoiding a meeting with the evil dragon. Take care that the player and the dragon cannot start off on walls. Also the dragon starts off from a randomly chosen position public class Labyrinth { private final int size; private final Cell[][] grid; public Labyrinth(int size) { this.size = size; this.grid = new Cell[size][size]; generateLabyrinth(); } private void generateLabyrinth() { Random rand = new Random(); for (int i = 0; i < size; i++) { for (int j = 0; j < size; j++) { // Randomly create walls and paths grid[i][j] = new Cell(rand.nextBoolean()); } } // Ensure start and end are…

Change the following code so that it checks the following 3 conditions: 1. there is no space between each cells (imgs) 2. even if it is resized, the components wouldn't disappear 3. The GameGUI JPanel takes all the JFrame space, so that there shouldn't be extra space appearing in the frame other than the game. Main(): Labyrinth labyrinth = new Labyrinth(10); Player player = new Player(9, 0); Dragon dragon = new Dragon(9, 9); JFrame frame = new JFrame("Labyrinth Game"); GameGUI gui = new GameGUI(labyrinth, player, dragon); frame.add(gui); frame.setSize(600, 600); frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); frame.setVisible(true); public class GameGUI extends JPanel { private final Labyrinth labyrinth; private final Player player; private final Dragon dragon; //labyrinth, player, dragon are just public classes private final ImageIcon playerIcon = new ImageIcon("data/images/player.png");…