(a) Explanation Given information: A cell of this bacterium in a nutrient-broth medium divides into two cells every 20 minutes. The initial population of a culture is 60 cells. Calculation: A cell of E. coli bacterium in a nutrient-broth medium divides into two cells every 20 minutes. This implies the following: After 20 minutes: we have 2 cells After 40 minutes: we have 2 ⋅ 2 = 2 2 cells After 1 hour: we have 2 2 ⋅ 2 = 2 3 = 8 cells After 2 hours: we have 8 ⋅ 2 3 = 8 2 cells ⋯ In general after t hours: the number of cells is C ( t ) = 8 t cells, where t is measured in hours We notice that C (b) To determine To find: expression for the number of cells after t hours. (c) To determine To describe: Find the number of cells after 8 hours. (d) To determine To describe: Find the rate of growth after 8 hours. (e) To determine To describe: When will the population reach 20,000 cells?

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ISBN: 9781305420878

Author: Stewart

Publisher: CENGAGE L

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Chapter 3.6, Problem 2E

(a)

To determine

To find: the relative growth rate.

(b)

To determine

To find: expression for the number of cells after t hours.

(c)

To determine

To describe: Find the number of cells after 8 hours.

(d)

To determine

To describe: Find the rate of growth after 8 hours.

(e)

To determine

To describe: When will the population reach 20,000 cells?

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Chapter 3.6, Problem 1E

Chapter 3.6, Problem 3E

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the relative growth rate.

Solution Summary: The author calculates the relative growth rate of E. coli bacterium in a nutrient-broth medium.

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To find: the relative growth rate.

To find: expression for the number of cells after t hours.

To describe: Find the number of cells after 8 hours.

To describe: Find the rate of growth after 8 hours.

To describe: When will the population reach 20,000 cells?

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