a. Explanation Given : It is given in the question that a rock is thrown on the planet Mars with a velocity of 10 m / s ,its height (in meters ) after t seconds is of the function H = 10 t − 1.86 t 2 . Concept Used: In this we must use the concept of derivatives. We have used the formula of limit lim h → 0 f ( a − h ) − f ( a ) h . Calculation: Position at t seconds H(t) = 10 t − 1.86 t 2 Initial velocity at t = 0 is 10 m/s. The instantaneous rate of change would be the velocity v ( a ) = lim t → a H ( t ) − H ( a ) t − a v ( 1 ) = lim t → 1 H ( 1 ) − H ( 1 ) t − 1 = lim t → 1 10 t − 1 b. To determine Find the velocity of the rock at t = a . c. To determine Calculate the time duration at which rock hit the surface. d. To determine Find the velocity of the rock when it hits the surface.

15th Edition

ISBN: 9781305420878

Author: Stewart

Publisher: CENGAGE L

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Chapter 3.1, Problem 28E

To determine

Calculate the velocity of the rock after one second.

To determine

Find the velocity of the rock at t = a .

To determine

Calculate the time duration at which rock hit the surface.

To determine

Find the velocity of the rock when it hits the surface.

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Chapter 3.1, Problem 27E

Chapter 3.1, Problem 29E

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Chapter 3 Solutions

BIOCALCULUS:CALCULUS F/LIFE...-W/ACCESS

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