(a) Explanation Given : The function is C ( t ) = 0.0225 t e − 0.0467 t . Calculation: The derivative of the function C ( t ) = 0.0225 t e − 0.0467 t using chain rule is as follows: C ′ ( t ) = 0.0225 t ( e − 0.0467 t ) ′ + 0.0225 t ′ ( e − 0.0467 t ) = 0.0225 t ( e − 0.0467 t ) ( − 0.0467 ) + 0.0225 ( t ) ′ ( e − 0.0467 t ) = 0.0225 e − 0 (b) To determine The rate of change of BAC after half hour later if the concentration function is C ( t ) = 0.0225 t e − 0.0467 t .

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ISBN: 9781305420878

Author: Stewart

Publisher: CENGAGE L

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Chapter 3.5, Problem 59E

(a)

To determine

The rate of change of BAC at t=10 if the concentration function is C(t)=0.0225te−0.0467t .

(b)

To determine

The rate of change of BAC after half hour later if the concentration function is C(t)=0.0225te−0.0467t .

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Chapter 3.5, Problem 58E

Chapter 3.5, Problem 60E

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Chapter 3 Solutions

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The rate of change of BAC at t = 10 if the concentration function is C ( t ) = 0.0225 t e − 0.0467 t .

Solution Summary: The author calculates the rate of change of BAC at t=10 if the concentration function is C(t)=0.0225t

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The rate of change of BAC at t=10 if the concentration function is C(t)=0.0225te−0.0467t .

The rate of change of BAC after half hour later if the concentration function is C(t)=0.0225te−0.0467t .

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