BIOCALCULUS:CALCULUS F/LIFE...-W/ACCESS
15th Edition
ISBN: 9781305420878
Author: Stewart
Publisher: CENGAGE L
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Chapter 3.1, Problem 25E
To determine
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Consider the matrix A, given by
+63)
A =
1
-3
4
-3
4
5
-105
(a) Find the determinant of the matrix, A.
(b) Find all possible solutions, x, to the system Ax = b, where b is the column vector, (1,2, −4).
If a
(1,4,2) and b = (−1, −5,3), find |a|, a + b, 3a - 2b, a b, a x b and b × a. What
is the angle between a and b?
Showing all working, find the eigenvalues and corresponding eigenvectors of
-3
(a)
(27)
6
Chapter 3 Solutions
BIOCALCULUS:CALCULUS F/LIFE...-W/ACCESS
Ch. 3.1 - Prob. 1ECh. 3.1 - Prob. 2ECh. 3.1 - Prob. 3ECh. 3.1 - Prob. 4ECh. 3.1 - Prob. 5ECh. 3.1 - Prob. 6ECh. 3.1 - Prob. 7ECh. 3.1 - Prob. 8ECh. 3.1 - Prob. 9ECh. 3.1 - Prob. 10E
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- Showing all working and using row operations determine all solutions to the follow- ing system of equations. 2x + 3y-2z = 8, -2x+y+6z= 12, -x+3y-2z = −4.arrow_forward8:38 *** TEMU 8 5G. 61% Score on last try: 0 of 1 pts. See Details for more. > Next question Get a similar question You can retry this question below Give the equation for the function which would have graph shown below. Use f(x) for the output. 54 3 2 1 12-11-10 -8 -7 -6 -5 -4 -3 -2 -3 23456 -4 -5 -6 -2 f(x) = 3 sin ( 7/7 x ) +2 Question Help: ☑Video ☑Message instructor Submit Question ||| <arrow_forward2:21 MM -8 -7 -6 -5 -4 0 5 4 3 2 N -3 -4 +5 +6 5G 100% Identify the function whose graph appears above. f(x) = = tan X 3 ✓ Question Help: ☐ Video ☐ Message instructor Submit Question |||arrow_forward
- 4 3. 2. 1 0 Π 元 -1 3 x -53. 5π 2π The graph of the function y = f(x) is shown in the xy-plane. Which of the following is the graph of the polar function r = f(e) in the polar coordinate system? A B Polar axis Polar axis Polar axis Polar axisarrow_forward٣:٥٣ النموذج الاول . . . O O O بشما ند الحمر الحمر الجمهورية الجنية وزارة التربية والتعليم اليوم التاريخ اللجنة العليا للاختبارات الزمن اختبار مادة الجبر والهندسة لجنة المطابع السرية المركزية للشهادة الثانوية العامة (القسم العلمي) الفترة %97 (1) ظلل في ورقة الإجابة الدائرة التي تحتوي على الحرف ( ص ) للإجابة الصحيحة والحرف ( خ ) للإجابة الخطأ بحسب رقم الفقرة لكل مما يأتي ( درجة لكل فقرة ) )1 ) 2 ) 3 ) 4 ) بؤرة القطع س" = ١٢ ص هي ( ۲ ) طول المحور الأصغر للقطع ٩ س + ص = ٩ يساوي 6 وحدات طول . ) إذا كان & عدد مركب ، 181 + 11 = ٦ ، فإن ١١ = ٣ . ) إذا كان م + ۳ ت = ۲ + ت ب م ، ب دع ، فإن م + ب = 5 ( ) إذا كان & = ۱ + ٣ ت ، فإن ٠ = ١٠ . 6 ( - ) إذا كان ٥٠ - ٣ - ١٢٠ ٤ - ٣ ، فإن قيمة ٧ = ٥ . 1 ) = N ) إذا كان ح هو الحد الخالي من س في المفكوك ( س + v. N 8 ( ( قيمة المقدار , = + ۱ ، * . . + ، فإن قيمة ٧ = ١٦ . ۱ + 9 ( ) المستقيمان المقاربان للقطع الذي معادلته س" = ١ هما ص = : ۹ 10 ( ) إذا كان ٥ + س = ٢٤ ، فإن قيمة س = - 1 س 11 ( ) إذا كانت النسبة بين الحدين الأوسطين تساوي 9 في المفكوك ( س + - ) ،…arrow_forwardالاسم يمنع استخدام الآلة الحاسبة ظلل في ورقة الإجابة الدائرة التي تحتوي على الحرف (ص) للإجابة الصحيحة والحرف (خ) للإجابة الخطأ بحسب رقم الفقرة لكل مما يأتي: درجة لكل فقرة. ( ) نها جا 元 جتا = صفر س ۱ س س -۱ ( ) يمكن إعادة تعريف الدالة د(س) = س قاس لكي تكون متصلة عند س = 7 ( ) إذا كانت د(س) = (٢) س - س ) ؛ فإن د(١) = ٦ ٢ س ص ( ) إذا كانت س + 0= ؛ فإن عند ) - ١ ، - ٦ ) تساوي (٦) ( ) إذا كانت د(س) = س ه ، و (س) = ٣ س ٢ + ٢ س ؛ فإن ( د ) (۱) = ۸ ) ( معادلة ناظم الدالة ص = د(س) عند النقطة ) ( ، د (۲)) هي ص - (د (م) - - د (۲) ( س - م ) ( ) إذا كانت ص = ظتا٢ س ؛ فإن ص = ٢ ص قتا ٢س ) ( إذا كانت د(س) = س ؛ فإن د (T) = جتاس 1- T ( ) إذا كانت د(س) = 1 - جناس جاس ؛ فإن د () = - 1 ( ) إذا كانت الدالة د (س) تحقق شروط مبرهنة القيمة المتوسطة على [ ، ب ] ، فإنه يوجد جـ ] ، ب [ بحيث (جـ) = (P) + (~)- - ب + P 1 2 3 4 5 6 7 8 9 10 11 ( ) للدالة د(س) = لو ( س ) + (٣) نقطة حرجة عند س = . ( ) إذا كان س = - ٢ مقارباً رأسياً للدالة د(س) 12 10 13 14 15 16 17 س = لو|س | + ث - = ۲ س + ٣ ب س + ٤ ، فإن معادلة…arrow_forward
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Algebra: Structure And Method, Book 1
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ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:McDougal Littell
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03a: Numerical Differentiation Review; Author: Jaisohn Kim;https://www.youtube.com/watch?v=IMYsqbV4CEg;License: Standard YouTube License, CC-BY