Algebra and Trigonometry: Structure and Method, Book 2
Algebra and Trigonometry: Structure and Method, Book 2
2000th Edition
ISBN: 9780395977255
Author: MCDOUGAL LITTEL
Publisher: McDougal Littell
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Concept explainers

Percentage
A percentage is a number indicated as a fraction of 100. It is a dimensionless number often expressed using the symbol %.
Algebraic Expressions
In mathematics, an algebraic expression consists of constant(s), variable(s), and mathematical operators. It is made up of terms.
Numbers
Numbers are some measures used for counting. They can be compared one with another to know its position in the number line and determine which one is greater or lesser than the other.
Subtraction
Before we begin to understand the subtraction of algebraic expressions, we need to list out a few things that form the basis of algebra.
Addition
Before we begin to understand the addition of algebraic expressions, we need to list out a few things that form the basis of algebra.
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Question
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Chapter 3.6, Problem 12P
To determine

To find:the amount of a plumber and plumbers apprentice earn.

Expert Solution & Answer
Check Mark

Answer to Problem 12P

The amount of a plumber earned $168 and plumbers apprentice earned $45.

Explanation of Solution

Given information:

The plumber earned $28 per hour and the plumbers apprentice earned $15 per hours.

Also, plumber worked 3 hours more than plumbers apprentice, together they were paid the amount $213.

Calculation:

Let x be the number of hours plumber worked and y be the number of hours apprentice worked.

The plumber worked 3 hours more than plumbers apprentice worked.

  x=y+3x−y=3 .

Since they were paid the amount $213, 28x+15y=213

Compute the solutions of the system x−y=3 and 28x+15y=213 by linear combination method.

Multiply the equation x−y=3 by 15, 15x−15y=45

Add these two equations 15x−15y=45 and 28x+15y=213 , simplify further.

  28x+15y=21315x−15y=4543x+0y  =258¯

Divide on both sides by43,

  x=25843x=6

Substitute x=6 in x−y=3 and simplify the value of x ,

  6−y=3−y=3−6y=3

The amount of a plumber earned is computed as follows,

  Plumber earned=28x=28(6)=168

The amount of a plumber apprentice is computed as follows,

   Apprentice earned=15y=15(3)=45

Therefore, the amount of a plumber earned $168and plumbers apprentice earned $45.

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Chapter 3.6, Problem 11P
Next
Chapter 3.6, Problem 13P

Chapter 3 Solutions

Algebra and Trigonometry: Structure and Method, Book 2

Ch. 3.1 - Prob. 1OECh. 3.1 - Prob. 2OECh. 3.1 - Prob. 3OECh. 3.1 - Prob. 4OECh. 3.1 - Prob. 5OECh. 3.1 - Prob. 6OECh. 3.1 - Prob. 7OECh. 3.1 - Prob. 8OECh. 3.1 - Prob. 9OECh. 3.1 - Prob. 10OE
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Prob. 2MRECh. 3.9 - Prob. 3MRECh. 3.9 - Prob. 4MRECh. 3.9 - Prob. 5MRECh. 3.9 - Prob. 6MRECh. 3.9 - Prob. 7MRECh. 3.9 - Prob. 8MRECh. 3.9 - Prob. 9MRECh. 3.9 - Prob. 10MRECh. 3.9 - Prob. 11MRECh. 3.9 - Prob. 12MRECh. 3.9 - Prob. 13MRECh. 3.10 - Prob. 1OECh. 3.10 - Prob. 2OECh. 3.10 - Prob. 3OECh. 3.10 - Prob. 4OECh. 3.10 - Prob. 5OECh. 3.10 - Prob. 6OECh. 3.10 - Prob. 7OECh. 3.10 - Prob. 8OECh. 3.10 - Prob. 9OECh. 3.10 - Prob. 10OECh. 3.10 - Prob. 11OECh. 3.10 - Prob. 12OECh. 3.10 - Prob. 13OECh. 3.10 - Prob. 14OECh. 3.10 - Prob. 15OECh. 3.10 - Prob. 16OECh. 3.10 - Prob. 17OECh. 3.10 - Prob. 18OECh. 3.10 - Prob. 19OECh. 3.10 - Prob. 20OECh. 3.10 - Prob. 21OECh. 3.10 - Prob. 22OECh. 3.10 - Prob. 23OECh. 3.10 - Prob. 24OECh. 3.10 - Prob. 1WECh. 3.10 - Prob. 2WECh. 3.10 - Prob. 3WECh. 3.10 - Prob. 4WECh. 3.10 - Prob. 5WECh. 3.10 - Prob. 6WECh. 3.10 - Prob. 7WECh. 3.10 - Prob. 8WECh. 3.10 - Prob. 9WECh. 3.10 - Prob. 10WECh. 3.10 - Prob. 11WECh. 3.10 - Prob. 12WECh. 3.10 - Prob. 13WECh. 3.10 - Prob. 14WECh. 3.10 - Prob. 15WECh. 3.10 - Prob. 16WECh. 3.10 - Prob. 17WECh. 3.10 - Prob. 18WECh. 3.10 - Prob. 19WECh. 3.10 - Prob. 20WECh. 3.10 - Prob. 21WECh. 3.10 - Prob. 22WECh. 3.10 - Prob. 23WECh. 3.10 - Prob. 24WECh. 3.10 - Prob. 25WECh. 3.10 - Prob. 26WECh. 3.10 - Prob. 27WECh. 3.10 - Prob. 28WECh. 3.10 - Prob. 29WECh. 3.10 - Prob. 30WECh. 3.10 - Prob. 31WECh. 3.10 - Prob. 32WECh. 3.10 - Prob. 33WECh. 3.10 - Prob. 34WECh. 3.10 - Prob. 35WECh. 3.10 - Prob. 36WECh. 3.10 - Prob. 37WECh. 3.10 - Prob. 1STCh. 3.10 - Prob. 2STCh. 3.10 - Prob. 3STCh. 3.10 - Prob. 4STCh. 3.10 - Prob. 5STCh. 3.10 - Prob. 6STCh. 3.10 - Prob. 7STCh. 3.10 - Prob. 8STCh. 3.10 - Prob. 9STCh. 3.10 - Prob. 1ECh. 3.10 - Prob. 2ECh. 3.10 - Prob. 3ECh. 3.10 - Prob. 4ECh. 3.10 - Prob. 5ECh. 3 - Prob. 1CRCh. 3 - Prob. 2CRCh. 3 - Prob. 3CRCh. 3 - Prob. 4CRCh. 3 - Prob. 5CRCh. 3 - Prob. 6CRCh. 3 - Prob. 7CRCh. 3 - Prob. 8CRCh. 3 - Prob. 9CRCh. 3 - Prob. 10CRCh. 3 - Prob. 11CRCh. 3 - Prob. 12CRCh. 3 - Prob. 13CRCh. 3 - Prob. 14CRCh. 3 - Prob. 15CRCh. 3 - Prob. 16CRCh. 3 - Prob. 17CRCh. 3 - Prob. 18CRCh. 3 - Prob. 1CTCh. 3 - Prob. 2CTCh. 3 - Prob. 3CTCh. 3 - Prob. 4CTCh. 3 - Prob. 5CTCh. 3 - Prob. 6CTCh. 3 - Prob. 7CTCh. 3 - Prob. 8CTCh. 3 - Prob. 9CTCh. 3 - Prob. 10CTCh. 3 - Prob. 11CTCh. 3 - Prob. 12CTCh. 3 - Prob. 13CTCh. 3 - Prob. 14CTCh. 3 - Prob. 15CTCh. 3 - Prob. 16CTCh. 3 - Prob. 1CLRCh. 3 - Prob. 2CLRCh. 3 - Prob. 3CLRCh. 3 - Prob. 4CLRCh. 3 - Prob. 5CLRCh. 3 - Prob. 6CLRCh. 3 - Prob. 7CLRCh. 3 - Prob. 8CLRCh. 3 - Prob. 9CLRCh. 3 - Prob. 10CLRCh. 3 - Prob. 11CLRCh. 3 - Prob. 12CLRCh. 3 - Prob. 13CLRCh. 3 - Prob. 14CLRCh. 3 - Prob. 15CLRCh. 3 - Prob. 16CLRCh. 3 - Prob. 17CLRCh. 3 - Prob. 18CLRCh. 3 - Prob. 19CLRCh. 3 - Prob. 20CLRCh. 3 - Prob. 21CLRCh. 3 - Prob. 22CLRCh. 3 - Prob. 23CLRCh. 3 - Prob. 24CLRCh. 3 - Prob. 25CLRCh. 3 - Prob. 26CLRCh. 3 - Prob. 27CLRCh. 3 - Prob. 28CLR

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