Algebra and Trigonometry: Structure and Method, Book 2
Algebra and Trigonometry: Structure and Method, Book 2
2000th Edition
ISBN: 9780395977255
Author: MCDOUGAL LITTEL
Publisher: McDougal Littell
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Chapter 3.1, Problem 6P

(a)

To determine

To represent: The lengths of the sides of the triangle, choosing two variables.

(a)

Expert Solution
Check Mark

Answer to Problem 6P

The variables representing the lengths of the isosceles triangle are a and b.

Explanation of Solution

Given information: An isosceles triangle has perimeter 15 m.

Calculation:

It is given that the triangle is isosceles. Therefore, the triangle has two sides equal. Since the perimeter is the sum of all the sides of the triangle, the perimeter is equal to the sum of two sides having equal length and the third side.

Assume that the length of sides which have equal lengths are a and the length of the third side is b.

Hence, the variables representing the lengths of the isosceles triangle are a and b.

(b)

To determine

To write: An open sentence relating to the variables.

(b)

Expert Solution
Check Mark

Answer to Problem 6P

The open sentence is 2a+b=15 .

Explanation of Solution

Given information: An isosceles triangle has perimeter 15 m. The variables representing the lengths of the isosceles triangle are a and b.

Calculation:

The perimeter of the isosceles triangle is 15m. That is,

  Perimeter=15Sum of three sides of  the triangle =15a+a+b=152a+b=15

  • Here, a is the length of the two sides of the triangle which have equal length and b is the length of the third side.

(b)

To determine

To write: An open sentence relating to the variables.

(b)

Expert Solution
Check Mark

Answer to Problem 6P

The open sentence is 2a+b=15 .

Explanation of Solution

Given information: An isosceles triangle has perimeter 15 m. The variables representing the lengths of the isosceles triangle are a and b.

Calculation:

The perimeter of the isosceles triangle is 15m. That is,

  Perimeter=15Sum of three sides of  the triangle =15a+a+b=152a+b=15

  • Here, a is the length of the two sides of the triangle which have equal length and b is the length of the third side.

(c)

To determine

To solve: The open system for integral values.

(c)

Expert Solution
Check Mark

Answer to Problem 6P

The only possible integral pairs are (1,13),(2,11),(3,9),(4,7),(5,5),(6,3),(7,1).

Explanation of Solution

Given information:The open sentence is 2a+b=15 .

Calculation:

The open sentence is 2a+b=15 .

The variable b in terms of a is,

  2a+b=15b=152a

Choose a=1 , then value of b is,

  b=152a=152(1)=152=13

Choose a=2 , then value of b is,

  b=152a=152(2)=154=11

Choose a=3 , then value of b is,

  b=152a=152(3)=156=9

Choose a=4 , then value of b is,

  b=152a=152(4)=158=7

Choose a=5 , then value of b is,

  b=152a=152(5)=1510=5

Choose a=6 , then value of b is,

  b=152a=152(6)=1512=3

Choose a=7 , then value of b is,

  b=152a=152(7)=1514=1

Choose a=8 , then value of b is,

  b=152a=152(8)=1516=1

This is not possible as b represents the length and length cannot be negative.

Therefore, the only possible integral pairs are,

  (1,13),(2,11),(3,9),(4,7),(5,5),(6,3),(7,1).

(c)

To determine

To solve: The open system for integral values.

(c)

Expert Solution
Check Mark

Answer to Problem 6P

The only possible integral pairs are (1,13),(2,11),(3,9),(4,7),(5,5),(6,3),(7,1).

Explanation of Solution

Given information:The open sentence is 2a+b=15 .

Calculation:

The open sentence is 2a+b=15 .

The variable b in terms of a is,

  2a+b=15b=152a

Choose a=1 , then value of b is,

  b=152a=152(1)=152=13

Choose a=2 , then value of b is,

  b=152a=152(2)=154=11

Choose a=3 , then value of b is,

  b=152a=152(3)=156=9

Choose a=4 , then value of b is,

  b=152a=152(4)=158=7

Choose a=5 , then value of b is,

  b=152a=152(5)=1510=5

Choose a=6 , then value of b is,

  b=152a=152(6)=1512=3

Choose a=7 , then value of b is,

  b=152a=152(7)=1514=1

Choose a=8 , then value of b is,

  b=152a=152(8)=1516=1

This is not possible as b represents the length and length cannot be negative.

Therefore, the only possible integral pairs are,

  (1,13),(2,11),(3,9),(4,7),(5,5),(6,3),(7,1).

Chapter 3 Solutions

Algebra and Trigonometry: Structure and Method, Book 2

Ch. 3.1 - Prob. 11OECh. 3.1 - Prob. 1WECh. 3.1 - Prob. 2WECh. 3.1 - Prob. 3WECh. 3.1 - Prob. 4WECh. 3.1 - Prob. 5WECh. 3.1 - Prob. 6WECh. 3.1 - Prob. 7WECh. 3.1 - Prob. 8WECh. 3.1 - Prob. 9WECh. 3.1 - Prob. 10WECh. 3.1 - Prob. 11WECh. 3.1 - Prob. 12WECh. 3.1 - Prob. 13WECh. 3.1 - Prob. 14WECh. 3.1 - Prob. 15WECh. 3.1 - Prob. 16WECh. 3.1 - Prob. 17WECh. 3.1 - Prob. 18WECh. 3.1 - Prob. 19WECh. 3.1 - Prob. 20WECh. 3.1 - Prob. 21WECh. 3.1 - Prob. 22WECh. 3.1 - Prob. 23WECh. 3.1 - Prob. 24WECh. 3.1 - Prob. 25WECh. 3.1 - Prob. 26WECh. 3.1 - Prob. 27WECh. 3.1 - Prob. 28WECh. 3.1 - Prob. 29WECh. 3.1 - Prob. 30WECh. 3.1 - Prob. 31WECh. 3.1 - Prob. 32WECh. 3.1 - Prob. 33WECh. 3.1 - Prob. 34WECh. 3.1 - Prob. 35WECh. 3.1 - Prob. 36WECh. 3.1 - Prob. 37WECh. 3.1 - Prob. 38WECh. 3.1 - Prob. 39WECh. 3.1 - Prob. 40WECh. 3.1 - Prob. 1PCh. 3.1 - Prob. 2PCh. 3.1 - Prob. 3PCh. 3.1 - Prob. 4PCh. 3.1 - Prob. 5PCh. 3.1 - Prob. 6PCh. 3.1 - Prob. 7PCh. 3.1 - Prob. 8PCh. 3.1 - Prob. 9PCh. 3.1 - Prob. 10PCh. 3.1 - 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Prob. 17OECh. 3.8 - Prob. 1WECh. 3.8 - Prob. 2WECh. 3.8 - Prob. 3WECh. 3.8 - Prob. 4WECh. 3.8 - Prob. 5WECh. 3.8 - Prob. 6WECh. 3.8 - Prob. 7WECh. 3.8 - Prob. 8WECh. 3.8 - Prob. 9WECh. 3.8 - Prob. 10WECh. 3.8 - Prob. 11WECh. 3.8 - Prob. 12WECh. 3.8 - Prob. 13WECh. 3.8 - Prob. 14WECh. 3.8 - Prob. 15WECh. 3.8 - Prob. 16WECh. 3.8 - Prob. 17WECh. 3.8 - Prob. 18WECh. 3.8 - Prob. 19WECh. 3.8 - Prob. 20WECh. 3.8 - Prob. 21WECh. 3.8 - Prob. 22WECh. 3.8 - Prob. 23WECh. 3.8 - Prob. 24WECh. 3.8 - Prob. 25WECh. 3.8 - Prob. 26WECh. 3.8 - Prob. 27WECh. 3.8 - Prob. 28WECh. 3.8 - Prob. 29WECh. 3.8 - Prob. 30WECh. 3.8 - Prob. 31WECh. 3.8 - Prob. 32WECh. 3.8 - Prob. 33WECh. 3.8 - Prob. 34WECh. 3.8 - Prob. 35WECh. 3.8 - Prob. 36WECh. 3.8 - Prob. 37WECh. 3.8 - Prob. 38WECh. 3.8 - Prob. 39WECh. 3.8 - Prob. 40WECh. 3.8 - Prob. 41WECh. 3.8 - Prob. 42WECh. 3.8 - Prob. 43WECh. 3.8 - Prob. 44WECh. 3.8 - Prob. 45WECh. 3.8 - Prob. 46WECh. 3.8 - Prob. 47WECh. 3.8 - Prob. 48WECh. 3.8 - Prob. 49WECh. 3.9 - Prob. 1OECh. 3.9 - Prob. 2OECh. 3.9 - Prob. 3OECh. 3.9 - Prob. 4OECh. 3.9 - Prob. 5OECh. 3.9 - Prob. 6OECh. 3.9 - Prob. 7OECh. 3.9 - Prob. 8OECh. 3.9 - Prob. 1WECh. 3.9 - Prob. 2WECh. 3.9 - Prob. 3WECh. 3.9 - Prob. 4WECh. 3.9 - Prob. 5WECh. 3.9 - Prob. 6WECh. 3.9 - Prob. 7WECh. 3.9 - Prob. 8WECh. 3.9 - Prob. 9WECh. 3.9 - Prob. 10WECh. 3.9 - Prob. 11WECh. 3.9 - Prob. 12WECh. 3.9 - Prob. 13WECh. 3.9 - Prob. 14WECh. 3.9 - Prob. 15WECh. 3.9 - Prob. 16WECh. 3.9 - Prob. 17WECh. 3.9 - Prob. 18WECh. 3.9 - Prob. 19WECh. 3.9 - Prob. 20WECh. 3.9 - Prob. 21WECh. 3.9 - Prob. 22WECh. 3.9 - Prob. 23WECh. 3.9 - Prob. 24WECh. 3.9 - Prob. 25WECh. 3.9 - Prob. 26WECh. 3.9 - Prob. 27WECh. 3.9 - Prob. 28WECh. 3.9 - Prob. 29WECh. 3.9 - Prob. 30WECh. 3.9 - Prob. 31WECh. 3.9 - Prob. 32WECh. 3.9 - Prob. 33WECh. 3.9 - Prob. 1PCh. 3.9 - Prob. 2PCh. 3.9 - Prob. 3PCh. 3.9 - Prob. 4PCh. 3.9 - Prob. 5PCh. 3.9 - Prob. 6PCh. 3.9 - Prob. 7PCh. 3.9 - Prob. 8PCh. 3.9 - Prob. 9PCh. 3.9 - Prob. 10PCh. 3.9 - Prob. 11PCh. 3.9 - Prob. 1MRECh. 3.9 - Prob. 2MRECh. 3.9 - Prob. 3MRECh. 3.9 - Prob. 4MRECh. 3.9 - Prob. 5MRECh. 3.9 - Prob. 6MRECh. 3.9 - Prob. 7MRECh. 3.9 - Prob. 8MRECh. 3.9 - Prob. 9MRECh. 3.9 - Prob. 10MRECh. 3.9 - Prob. 11MRECh. 3.9 - Prob. 12MRECh. 3.9 - Prob. 13MRECh. 3.10 - Prob. 1OECh. 3.10 - Prob. 2OECh. 3.10 - Prob. 3OECh. 3.10 - Prob. 4OECh. 3.10 - Prob. 5OECh. 3.10 - Prob. 6OECh. 3.10 - Prob. 7OECh. 3.10 - Prob. 8OECh. 3.10 - Prob. 9OECh. 3.10 - Prob. 10OECh. 3.10 - Prob. 11OECh. 3.10 - Prob. 12OECh. 3.10 - Prob. 13OECh. 3.10 - Prob. 14OECh. 3.10 - Prob. 15OECh. 3.10 - Prob. 16OECh. 3.10 - Prob. 17OECh. 3.10 - Prob. 18OECh. 3.10 - Prob. 19OECh. 3.10 - Prob. 20OECh. 3.10 - Prob. 21OECh. 3.10 - Prob. 22OECh. 3.10 - Prob. 23OECh. 3.10 - Prob. 24OECh. 3.10 - Prob. 1WECh. 3.10 - Prob. 2WECh. 3.10 - Prob. 3WECh. 3.10 - Prob. 4WECh. 3.10 - Prob. 5WECh. 3.10 - Prob. 6WECh. 3.10 - Prob. 7WECh. 3.10 - Prob. 8WECh. 3.10 - Prob. 9WECh. 3.10 - Prob. 10WECh. 3.10 - Prob. 11WECh. 3.10 - Prob. 12WECh. 3.10 - Prob. 13WECh. 3.10 - Prob. 14WECh. 3.10 - Prob. 15WECh. 3.10 - Prob. 16WECh. 3.10 - Prob. 17WECh. 3.10 - Prob. 18WECh. 3.10 - Prob. 19WECh. 3.10 - Prob. 20WECh. 3.10 - Prob. 21WECh. 3.10 - Prob. 22WECh. 3.10 - Prob. 23WECh. 3.10 - Prob. 24WECh. 3.10 - Prob. 25WECh. 3.10 - Prob. 26WECh. 3.10 - Prob. 27WECh. 3.10 - Prob. 28WECh. 3.10 - Prob. 29WECh. 3.10 - Prob. 30WECh. 3.10 - Prob. 31WECh. 3.10 - Prob. 32WECh. 3.10 - Prob. 33WECh. 3.10 - Prob. 34WECh. 3.10 - Prob. 35WECh. 3.10 - Prob. 36WECh. 3.10 - Prob. 37WECh. 3.10 - Prob. 1STCh. 3.10 - Prob. 2STCh. 3.10 - Prob. 3STCh. 3.10 - Prob. 4STCh. 3.10 - Prob. 5STCh. 3.10 - Prob. 6STCh. 3.10 - Prob. 7STCh. 3.10 - Prob. 8STCh. 3.10 - Prob. 9STCh. 3.10 - Prob. 1ECh. 3.10 - Prob. 2ECh. 3.10 - Prob. 3ECh. 3.10 - Prob. 4ECh. 3.10 - Prob. 5ECh. 3 - Prob. 1CRCh. 3 - Prob. 2CRCh. 3 - Prob. 3CRCh. 3 - Prob. 4CRCh. 3 - Prob. 5CRCh. 3 - Prob. 6CRCh. 3 - Prob. 7CRCh. 3 - Prob. 8CRCh. 3 - Prob. 9CRCh. 3 - Prob. 10CRCh. 3 - Prob. 11CRCh. 3 - Prob. 12CRCh. 3 - Prob. 13CRCh. 3 - Prob. 14CRCh. 3 - Prob. 15CRCh. 3 - Prob. 16CRCh. 3 - Prob. 17CRCh. 3 - Prob. 18CRCh. 3 - Prob. 1CTCh. 3 - Prob. 2CTCh. 3 - Prob. 3CTCh. 3 - Prob. 4CTCh. 3 - Prob. 5CTCh. 3 - Prob. 6CTCh. 3 - Prob. 7CTCh. 3 - Prob. 8CTCh. 3 - Prob. 9CTCh. 3 - Prob. 10CTCh. 3 - Prob. 11CTCh. 3 - Prob. 12CTCh. 3 - Prob. 13CTCh. 3 - Prob. 14CTCh. 3 - Prob. 15CTCh. 3 - Prob. 16CTCh. 3 - Prob. 1CLRCh. 3 - Prob. 2CLRCh. 3 - Prob. 3CLRCh. 3 - Prob. 4CLRCh. 3 - Prob. 5CLRCh. 3 - Prob. 6CLRCh. 3 - Prob. 7CLRCh. 3 - Prob. 8CLRCh. 3 - Prob. 9CLRCh. 3 - Prob. 10CLRCh. 3 - Prob. 11CLRCh. 3 - Prob. 12CLRCh. 3 - Prob. 13CLRCh. 3 - Prob. 14CLRCh. 3 - Prob. 15CLRCh. 3 - Prob. 16CLRCh. 3 - Prob. 17CLRCh. 3 - Prob. 18CLRCh. 3 - Prob. 19CLRCh. 3 - Prob. 20CLRCh. 3 - Prob. 21CLRCh. 3 - Prob. 22CLRCh. 3 - Prob. 23CLRCh. 3 - Prob. 24CLRCh. 3 - Prob. 25CLRCh. 3 - Prob. 26CLRCh. 3 - Prob. 27CLRCh. 3 - Prob. 28CLR
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