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High School Math Algebra Algebra and Trigonometry: Structure and Method, Book 2

The system of equations and find h ( 7 ) .

The system of equations and find h ( 7 ) .

Algebra and Trigonometry: Structure and Method, Book 2

Algebra and Trigonometry: Structure and Method, Book 2

2000th Edition

ISBN: 9780395977255

Author: MCDOUGAL LITTEL

Publisher: McDougal Littell

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Question

Chapter 3, Problem 27CLR

To determine

To solve: The system of equations and find h(7) .

Expert Solution & Answer

Answer to Problem 27CLR

The value is h(7)=−13

Explanation of Solution

Given information: The function h(x) is a linear function and h(−3)=2,h(1)=−4 .

Calculation:

Since the function h(x) is a linear function, it can be written as,

h(x)=mx+c ...... (1)

Here, m is the slope andc is the intercept.

Substitute h(−3)=2,h(1)=−4 to obtain a system of equation,

h(x)=mx+c2=−3m+c (∵h(−3)=2)−4=m+c (∵h(1)=−4)

Simplify both the equations to obtain the values of m and c,

2=−3m+c −4=m+c ____________+ − −6=−4m

This gives,

−4m=6m=6−4=−32

Substitute the value of m to obtain c,’

−4=m+c−4=−32+cc=−4+32=−8+32=−52

Substitute the values of m and c in equation (1) to obtain a general equation for h(x) ,

h(x)=mx+c=−32x−52

To obtain the value of h(7) , substitute x=7 ,

h(x)=−32x−52h(7)=−32(7)−52=−21−52=−262=−13

Chapter 3, Problem 26CLR

Chapter 3, Problem 28CLR

Chapter 3 Solutions

Algebra and Trigonometry: Structure and Method, Book 2

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Prob. 9OE Ch. 3.10 - Prob. 10OE Ch. 3.10 - Prob. 11OE Ch. 3.10 - Prob. 12OE Ch. 3.10 - Prob. 13OE Ch. 3.10 - Prob. 14OE Ch. 3.10 - Prob. 15OE Ch. 3.10 - Prob. 16OE Ch. 3.10 - Prob. 17OE Ch. 3.10 - Prob. 18OE Ch. 3.10 - Prob. 19OE Ch. 3.10 - Prob. 20OE Ch. 3.10 - Prob. 21OE Ch. 3.10 - Prob. 22OE Ch. 3.10 - Prob. 23OE Ch. 3.10 - Prob. 24OE Ch. 3.10 - Prob. 1WE Ch. 3.10 - Prob. 2WE Ch. 3.10 - Prob. 3WE Ch. 3.10 - Prob. 4WE Ch. 3.10 - Prob. 5WE Ch. 3.10 - Prob. 6WE Ch. 3.10 - Prob. 7WE Ch. 3.10 - Prob. 8WE Ch. 3.10 - Prob. 9WE Ch. 3.10 - Prob. 10WE Ch. 3.10 - Prob. 11WE Ch. 3.10 - Prob. 12WE Ch. 3.10 - Prob. 13WE Ch. 3.10 - Prob. 14WE Ch. 3.10 - Prob. 15WE Ch. 3.10 - Prob. 16WE Ch. 3.10 - Prob. 17WE Ch. 3.10 - Prob. 18WE Ch. 3.10 - Prob. 19WE Ch. 3.10 - Prob. 20WE Ch. 3.10 - Prob. 21WE Ch. 3.10 - Prob. 22WE Ch. 3.10 - Prob. 23WE Ch. 3.10 - Prob. 24WE Ch. 3.10 - Prob. 25WE Ch. 3.10 - Prob. 26WE Ch. 3.10 - Prob. 27WE Ch. 3.10 - Prob. 28WE Ch. 3.10 - Prob. 29WE Ch. 3.10 - Prob. 30WE Ch. 3.10 - Prob. 31WE Ch. 3.10 - Prob. 32WE Ch. 3.10 - Prob. 33WE Ch. 3.10 - Prob. 34WE Ch. 3.10 - Prob. 35WE Ch. 3.10 - Prob. 36WE Ch. 3.10 - Prob. 37WE Ch. 3.10 - Prob. 1ST Ch. 3.10 - Prob. 2ST Ch. 3.10 - Prob. 3ST Ch. 3.10 - Prob. 4ST Ch. 3.10 - Prob. 5ST Ch. 3.10 - Prob. 6ST Ch. 3.10 - Prob. 7ST Ch. 3.10 - Prob. 8ST Ch. 3.10 - Prob. 9ST Ch. 3.10 - Prob. 1E Ch. 3.10 - Prob. 2E Ch. 3.10 - Prob. 3E Ch. 3.10 - Prob. 4E Ch. 3.10 - Prob. 5E Ch. 3 - Prob. 1CR Ch. 3 - Prob. 2CR Ch. 3 - Prob. 3CR Ch. 3 - Prob. 4CR Ch. 3 - Prob. 5CR Ch. 3 - Prob. 6CR Ch. 3 - Prob. 7CR Ch. 3 - Prob. 8CR Ch. 3 - Prob. 9CR Ch. 3 - Prob. 10CR Ch. 3 - Prob. 11CR Ch. 3 - Prob. 12CR Ch. 3 - Prob. 13CR Ch. 3 - Prob. 14CR Ch. 3 - Prob. 15CR Ch. 3 - Prob. 16CR Ch. 3 - Prob. 17CR Ch. 3 - Prob. 18CR Ch. 3 - Prob. 1CT Ch. 3 - Prob. 2CT Ch. 3 - Prob. 3CT Ch. 3 - Prob. 4CT Ch. 3 - Prob. 5CT Ch. 3 - Prob. 6CT Ch. 3 - Prob. 7CT Ch. 3 - Prob. 8CT Ch. 3 - Prob. 9CT Ch. 3 - Prob. 10CT Ch. 3 - Prob. 11CT Ch. 3 - Prob. 12CT Ch. 3 - Prob. 13CT Ch. 3 - Prob. 14CT Ch. 3 - Prob. 15CT Ch. 3 - Prob. 16CT Ch. 3 - Prob. 1CLR Ch. 3 - Prob. 2CLR Ch. 3 - Prob. 3CLR Ch. 3 - Prob. 4CLR Ch. 3 - Prob. 5CLR Ch. 3 - Prob. 6CLR Ch. 3 - Prob. 7CLR Ch. 3 - Prob. 8CLR Ch. 3 - Prob. 9CLR Ch. 3 - Prob. 10CLR Ch. 3 - Prob. 11CLR Ch. 3 - Prob. 12CLR Ch. 3 - Prob. 13CLR Ch. 3 - Prob. 14CLR Ch. 3 - Prob. 15CLR Ch. 3 - Prob. 16CLR Ch. 3 - Prob. 17CLR Ch. 3 - Prob. 18CLR Ch. 3 - Prob. 19CLR Ch. 3 - Prob. 20CLR Ch. 3 - Prob. 21CLR Ch. 3 - Prob. 22CLR Ch. 3 - Prob. 23CLR Ch. 3 - Prob. 24CLR Ch. 3 - Prob. 25CLR Ch. 3 - Prob. 26CLR Ch. 3 - Prob. 27CLR Ch. 3 - Prob. 28CLR

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