Fig. 35-43, light is incident perpendicularly on a thin layer of material 2 that lies between (thicker) materials 1 and 3. (The rays are tilted only for clarity.) Part of the light ends up in material 3 as ray r 3 (the light does not reflect inside material 2) and r 4 (the light reflects twice inside material 2). The waves of r 3 and r 4 interfere, and here we consider the type of interference to be either maximum (max) or minimum (min). For this situation, each problem in Table 35-3 refers to the indexes of refraction n 1 , n 2 , and n 3 , the type of interference, the thin-layer thickness L in nanometers, and the wavelength ๐ in nanometers of the light as measured in air. Where ๐ is missing, give the wavelength that is in the visible range. Where L is missing, give the second least thickness or the third least thickness as indicated. Figure 35-45 n 1 n 2 n 3 Type L ๐ 61 1.32 1.75 1.39 Min 325 62 1.68 1.59 1.50 Max 2nd 342 63 1.40 1.46 1.75 Max 2nd 482 64 1.40 1.46 1.75 Max 210 65 1.60 1.40 1.80 Min 2nd 632 Table 35-3: Transmission Through Thin Layers.
Fig. 35-43, light is incident perpendicularly on a thin layer of material 2 that lies between (thicker) materials 1 and 3. (The rays are tilted only for clarity.) Part of the light ends up in material 3 as ray r 3 (the light does not reflect inside material 2) and r 4 (the light reflects twice inside material 2). The waves of r 3 and r 4 interfere, and here we consider the type of interference to be either maximum (max) or minimum (min). For this situation, each problem in Table 35-3 refers to the indexes of refraction n 1 , n 2 , and n 3 , the type of interference, the thin-layer thickness L in nanometers, and the wavelength ๐ in nanometers of the light as measured in air. Where ๐ is missing, give the wavelength that is in the visible range. Where L is missing, give the second least thickness or the third least thickness as indicated. Figure 35-45 n 1 n 2 n 3 Type L ๐ 61 1.32 1.75 1.39 Min 325 62 1.68 1.59 1.50 Max 2nd 342 63 1.40 1.46 1.75 Max 2nd 482 64 1.40 1.46 1.75 Max 210 65 1.60 1.40 1.80 Min 2nd 632 Table 35-3: Transmission Through Thin Layers.
Fig. 35-43, light is incident perpendicularly on a thin layer of material 2 that lies between (thicker) materials 1 and 3. (The rays are tilted only for clarity.) Part of the light ends up in material 3 as ray
r
3
(the light does not reflect inside material 2) and
r
4
(the light reflects twice inside material 2). The waves of
r
3
and
r
4
interfere, and here we consider the type of interference to be either maximum (max) or minimum (min). For this situation, each problem in Table 35-3 refers to the indexes of refraction
n
1
,
n
2
, and
n
3
, the type of interference, the thin-layer thickness L in nanometers, and the wavelength ๐ in nanometers of the light as measured in air. Where ๐ is missing, give the wavelength that is in the visible range. Where L is missing, give the second least thickness or the third least thickness as indicated.
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astering.pearson.com/?courseld=13289599#/
Figure
y (mm)
x=0x = 0.0900 m
All
โ Correct
For either the time for one full cycle is 0.040 s; this is the period.
Part C
-
ON
You are told that the two points x = 0 and x = 0.0900 m are within one
wavelength of each other. If the wave is moving in the +x-direction, determine the
wavelength.
Express your answer to two significant figures and include the appropriate
units.
0
t(s)
ฮป =
Value
m
0.01 0.03 0.05 0.07
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Part C
Find the height yi
from which the rock was launched.
Express your answer in meters to three significant figures. ย ย ย ย ย ย ย ย ย ย ย ย ย ย ย ย ย ย
Learning Goal:
To practice Problem-Solving Strategy 4.1 for projectile motion problems.
A rock thrown with speed 12.0 m/s and launch angle 30.0 โ (above the horizontal) travels a horizontal distance of d = 19.0 m before hitting the ground. From what height was the rock thrown? Use the value g = 9.800 m/s2 for the free-fall acceleration.
ย
ย
PROBLEM-SOLVING STRATEGY 4.1 Projectile motion problems
MODEL: Is it reasonable to ignore air resistance? If so, use the projectile motion model.
VISUALIZE: Establish a coordinate system with the x-axis horizontal and the y-axis vertical. Define symbols and identify what the problem is trying to find. For a launch at angle ฮธ, the initial velocity components are vix=v0cosฮธ and viy=v0sinฮธ.
SOLVE: The acceleration is known: ax=0 and ay=โg. Thus, the problem becomes one ofโฆ
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