41 through 52 GO 43, 51 SSM 47, 51 Reflection by thin layers . In Fig. 35-42, light is incident perpendicularly on a thin layer of material 2 that lies between (thicker) materials 1 and 3. (The rays are tilted only for clarity.) The waves of rays r 1 and r 2 interfere, and here we consider the type of interference to be either maximum (max) or minimum (min). For this situation, each problem in Table 35-2 refers to the indexes of refraction n 1 , n 2 , and n 3 , the type of interference, the thin-layer thickness L in nanometers, and the wavelength λ in nanometers of the light as measured in air. Where λ is missing, give the wavelength that is in the visible range. Where L is missing, give the second least thickness or the third least thickness as indicated. Figure 35-42 Problems 41 through 52 Table 35-2 Problems 41 through 52: Reflection by Thin Layers. See the setup for these problems. n 1 n 2 n 3 Type L λ 41 1.68 1.59 1.50 min 2nd 342
41 through 52 GO 43, 51 SSM 47, 51 Reflection by thin layers . In Fig. 35-42, light is incident perpendicularly on a thin layer of material 2 that lies between (thicker) materials 1 and 3. (The rays are tilted only for clarity.) The waves of rays r 1 and r 2 interfere, and here we consider the type of interference to be either maximum (max) or minimum (min). For this situation, each problem in Table 35-2 refers to the indexes of refraction n 1 , n 2 , and n 3 , the type of interference, the thin-layer thickness L in nanometers, and the wavelength λ in nanometers of the light as measured in air. Where λ is missing, give the wavelength that is in the visible range. Where L is missing, give the second least thickness or the third least thickness as indicated. Figure 35-42 Problems 41 through 52 Table 35-2 Problems 41 through 52: Reflection by Thin Layers. See the setup for these problems. n 1 n 2 n 3 Type L λ 41 1.68 1.59 1.50 min 2nd 342
41 through 52 GO 43, 51 SSM 47, 51 Reflection by thin layers. In Fig. 35-42, light is incident perpendicularly on a thin layer of material 2 that lies between (thicker) materials 1 and 3. (The rays are tilted only for clarity.) The waves of rays r1 and r2 interfere, and here we consider the type of interference to be either maximum (max) or minimum (min). For this situation, each problem in Table 35-2 refers to the indexes of refraction n1, n2, and n3, the type of interference, the thin-layer thickness L in nanometers, and the wavelength λ in nanometers of the light as measured in air. Where λ is missing, give the wavelength that is in the visible range. Where L is missing, give the second least thickness or the third least thickness as indicated.
Figure 35-42 Problems 41 through 52
Table 35-2 Problems 41 through 52: Reflection by Thin Layers. See the setup for these problems.
3. By using the fact that around any closed loop the sum of the EMFS = the sum of the PDs. Write
equations for the two loops shown in the cct below.
40
ΔΩ
I₂
4V
(loop1
20 (loop2) 2v
I+12
Use these equations to show that the current flowing through the 20 resistor is 0.75A
5. A potential divider circuit is made by stretching a 1 m long wire with a resistance of 0.1 per cm
from A to B as shown.
8V
A
100cm
B
sliding contact
5Ω
A varying PD is achieved across the 5 Q resistor by moving the slider along the resistance wire.
Calculate the distance from A when the PD across the 5 Q resistor is 6 V.
4. A voltmeter with resistance 10 kQ is used to measure the pd across the 1 kQ resistor in the circuit
below.
6V
5ΚΩ
1ΚΩ
V
Calculate the percentage difference between the value with and without the voltmeter.
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