41 through 52 GO 43, 51 SSM 47, 51 Reflection by thin layers . In Fig. 35-42, light is incident perpendicularly on a thin layer of material 2 that lies between (thicker) materials 1 and 3. (The rays are tilted only for clarity.) The waves of rays r 1 and r 2 interfere, and here we consider the type of interference to be either maximum (max) or minimum (min). For this situation, each problem in Table 35-2 refers to the indexes of refraction n 1 , n 2 , and n 3 , the type of interference, the thin-layer thickness L in nanometers, and the wavelength λ in nanometers of the light as measured in air. Where λ is missing, give the wavelength that is in the visible range. Where L is missing, give the second least thickness or the third least thickness as indicated. Figure 35-42 Problems 41 through 52 Table 35-2 Problems 41 through 52: Reflection by Thin Layers. See the setup for these problems. n 1 n 2 n 3 Type L λ 41 1.68 1.59 1.50 min 2nd 342
41 through 52 GO 43, 51 SSM 47, 51 Reflection by thin layers . In Fig. 35-42, light is incident perpendicularly on a thin layer of material 2 that lies between (thicker) materials 1 and 3. (The rays are tilted only for clarity.) The waves of rays r 1 and r 2 interfere, and here we consider the type of interference to be either maximum (max) or minimum (min). For this situation, each problem in Table 35-2 refers to the indexes of refraction n 1 , n 2 , and n 3 , the type of interference, the thin-layer thickness L in nanometers, and the wavelength λ in nanometers of the light as measured in air. Where λ is missing, give the wavelength that is in the visible range. Where L is missing, give the second least thickness or the third least thickness as indicated. Figure 35-42 Problems 41 through 52 Table 35-2 Problems 41 through 52: Reflection by Thin Layers. See the setup for these problems. n 1 n 2 n 3 Type L λ 41 1.68 1.59 1.50 min 2nd 342
41 through 52 GO 43, 51 SSM 47, 51 Reflection by thin layers. In Fig. 35-42, light is incident perpendicularly on a thin layer of material 2 that lies between (thicker) materials 1 and 3. (The rays are tilted only for clarity.) The waves of rays r1 and r2 interfere, and here we consider the type of interference to be either maximum (max) or minimum (min). For this situation, each problem in Table 35-2 refers to the indexes of refraction n1, n2, and n3, the type of interference, the thin-layer thickness L in nanometers, and the wavelength λ in nanometers of the light as measured in air. Where λ is missing, give the wavelength that is in the visible range. Where L is missing, give the second least thickness or the third least thickness as indicated.
Figure 35-42 Problems 41 through 52
Table 35-2 Problems 41 through 52: Reflection by Thin Layers. See the setup for these problems.
2
C01: Physical Quantities, Units and Measurementscobris alinu zotinUD TRO
Bendemeer Secondary School
Secondary Three Express Physics
Chpt 1: Physical Quantities, Unit and Measurements Assignment
Name: Chen ShiMan
loov neowled soria
25
( 03 ) Class: 3 Respect 6 Date: 2025.01.22
1
Which group consists only of scalar quantities?
ABCD
A
acceleration, moment and energy store
distance, temperature and time
length, velocity and current
mass, force and speed
B
D.
B
Which diagram represents the resultant vector of P and Q? lehtele
시
bas siqpeq olarist of beau eldeo qirie-of-qi
P
A
C
-B
qadmis
rle mengaib priwollot erT S
Quilons of qira ono mont aboog
eed indicator
yh from West
eril to Inioqbim srij
enisinoo MA
(6)
08 bas 8A aldao ni nolent or animaleb.gniweb slepe eld
260 km/h
D
1
D.
e
51
The figure gives the acceleration a versus time t for a particle moving along an x axis. The a-axis scale is set by as = 12.0 m/s². At t = -2.0
s, the particle's velocity is 11.0 m/s. What is its velocity at t = 6.0 s?
a (m/s²)
as
-2
0
2
t(s)
4
Two solid cylindrical rods AB and BC are welded together at B and loaded as shown. Knowing that the average normal stress must not
exceed 150 MPa in either rod, determine the smallest allowable values of the diameters d₁ and d2. Take P= 85 kN.
P
125 kN
B
125 kN
C
0.9 m
1.2 m
The smallest allowable value of the diameter d₁ is
The smallest allowable value of the diameter d₂ is
mm.
mm.
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