Concept explainers
One round face of a 3.25-m, solid, cylindrical plastic-pipe is covered with a thin black coating that completely blocks light. The opposite face is covered with a fluorescent coating that glows when it is struck by light. Two straight, thin, parallel scratches, 0.225 mm apart, are made in the center of the black face. When laser light of wavelength 632.8 nm shines through the slits perpendicular to the black lace, you find that the central bright fringe on the opposite face is 5.82 mm wide, measured between the dark fringes that border it on either side. What is the index of refraction of the plastic?
Want to see the full answer?
Check out a sample textbook solutionChapter 35 Solutions
University Physics (14th Edition)
Additional Science Textbook Solutions
Physics for Scientists and Engineers with Modern Physics
Modern Physics
College Physics: A Strategic Approach (4th Edition)
An Introduction to Thermal Physics
College Physics: A Strategic Approach (3rd Edition)
Physics (5th Edition)
- The Michelson interferometer can be used to measure the index of refraction of a gas by placing an evacuated transparent tube in the light path along one arm of the device. Fringe shifts occur as the gas is slowly added to the tube. Assume 580-nm light is used, the tube is 5.40 cm long, and 152 fringe shifts occur as the pressure of the gas in the tube increases to atmospheric pressure. What is the index of refraction of the gas? Hint: The fringe shifts occur because the wavelength of the light changes inside the gas-filled tube. (Give your answer to five decimal places.) 4.0arrow_forwardProblem 8 :We wish to coat a flat slab of glass (n 1.5) with a %3D transparent material (n-1.25) so that light of wavelength 620nm (in vacuum) incident normally is not reflected. What should be the minimum thickness of the coating? Air=1 Film= Glass=1.5 1.25 a 111arrow_forwardThe Michelson interferometer can be used to measure the index of refraction of a gas by placing an evacuated transparent tube in the light path along one arm of the device. Fringe shifts occur as the gas is slowly added to the tube. Assume 610-nm light is used, the tube is 5.40 cm long, and 168 bright fringes pass on the screen as the pressure of the gas in the tube increases to atmospheric pressure. What is the index of refraction of the gas? Hint: The fringe shifts occur because the wavelength of the light changes inside the gas-filled tube. (Give your answer to at least five decimal places.)arrow_forward
- A thin layer of liquid methylene iodide (n = 1.76) is sandwiched between two flat, parallel plates of glass (n = 1.42). What is the minimum thickness of the liquid layer if normally incident light with λ= 550 nm in air is to be strongly reflected? 63.0 nm 99.2 nm 78.1 nm 126.0 nmarrow_forwardOne way to determine the index of refraction of a gas is to use an interferometer. As shown below, one of the beams of an interferometer passes through a glass container that has a length of L = 1.8 cm. Initially the glass container is a vacuum. When gas is slowly allowed into the container, a total of 6894 dark fringes move past the reference line. The laser has a wavelength of 635 nm (this is the wavelength when the light from the laser is moving through a vacuum). A.) Determine how many wavelengths will fit into the glass container when it is a vacuum. Since the light passes through the container twice, you need to determine how many wavelengths will fit into a glass container that has a length of 2L.number of wavelengths (vacuum) = B.) The number of dark fringes is the difference between the number of wavelengths that fit in the container (length of 2L) when it has gas and the number of wavelengths that fit in the container (length of 2L) when it is a vacuum. Use this knowledge to…arrow_forwardA thin layer of a transparent material that has an index of refraction of 1.25 is used as a nonreflective coating on the surface of glass that has an index of refraction of 1.50. What should the minimum thickness of the material be for the material to be nonreflecting for light that has a wavelength of 578 nm?arrow_forward
- One way to determine the index of refraction of a gas is to use an interferometer. As shown below, one of the beams of an interferometer passes through a glass container that has a length of L = 1.8 cm. Initially the glass container is a vacuum. When gas is slowly allowed into the container, a total of 7571 dark fringes move past the reference line. The laser has a wavelength of 687 nm (this is the wavelength when the light from the laser is moving through a vacuum). Laser Mirror Glass Container Beam Splitter Diffraction Pattern Mirror A.) Determine how many wavelengths will fit into the glass container when it is a vacuum. Since the light passes through the container twice, you need to determine how many wavelengths will fit into a glass container that has a length of 2L. number of wavelengths (vacuum) = B.) The number of dark fringes is the difference between the number of wavelengths that fit in the container (length of 2L) when it has gas and the number of wavelengths that fit in…arrow_forwardMonochromatic light with wavelength 620 nm passes through a circular aperture with diameter 7.4 um. The resulting diffraction pattern is observed on a screen that is 4.5 m from the aperture. What is the diameter of the Airy disk on the screen?arrow_forwardOne leg of a Michelson interferometer contains an evacuated cylinder of length L, =0.30m having glass plates on each end. A gas is slowly leaked into the cylinder until a pressure of 1 atm is reached. If 140 bright fringes pass on the screen when light of wavelength A=440nm is used, what is n, the index of refraction of the gas? State your answer to the nearest 0.000001 ( one part per million).arrow_forward
- The yellow D, line from a sodium discharge lamp has a vacuum wavelength of 589.5923 nm. Suppose such light falls at 30.00° on the surface of a film of soybean oil (n = 1.4729) suspended (within a wire frame) in air. What minimum thickness should the film have in some region if that area is to strongly reflect the light? %Darrow_forwardIn a double-slit experiment, the optical path difference between the rays from two coherent sources at a point P on one side of the central bright band is 7.5 x 10 m and at a point Q on the other side of the central bright band is 1.8 x 10 m. How many bright and dark bands are observed between points P and Q if the wavelength of light used is 6 × 107 m?arrow_forwardIn Figure P37.18, let L = 120 cm and d = 0.250 cm. The slits are illuminated with coherent 600-nm light. Calculate the distance y from the central maximum for which the average intensity on the screen is 75.0% of the maximum.arrow_forward
- Physics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning