Explanation Given: The given function is f ( x ) = 1 2 − 3 x 3 . Formula used: d d x ( x n ) = n x n − 1 Chain rule: d d x ( f ( g ( x ) ) ) = f ′ ( g ( x ) ) g ′ ( x ) Quotient rule : d d x ( f g ) = f ′ g − f g ′ g 2 Calculation: Differentiate the given function with respect to x . f ′ ( x ) = d d x ( 1 2 − 3 x 3 ) = d d x ( 1 2 − 3 x ) 1 3 = 1 3 ⋅ ( 1 2 − 3 x ) 1 3 − 1 d d x ( 1 2 − 3 x ) = 1 3 ⋅ ( 1 2 − 3 x ) − 2 3 ⋅ 1 ⋅ d d x ( 2 − <

Calculus: Special Edition: Chapters 1-5 (w/ WebAssign)

6th Edition

ISBN: 9781524908102

Author: SMITH KARL J, STRAUSS MONTY J, TODA MAGDALENA DANIELE

Publisher: Kendall Hunt Publishing

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Chapter 3.5, Problem 28PS

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To find the derivative of the function f(x)=12−3x3 .

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Chapter 3.5, Problem 27PS

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Chapter 3 Solutions

Calculus: Special Edition: Chapters 1-5 (w/ WebAssign)

Ch. 3.1 - Prob. 1PS Ch. 3.1 - Prob. 2PS Ch. 3.1 - Prob. 3PS Ch. 3.1 - Prob. 4PS Ch. 3.1 - Prob. 5PS Ch. 3.1 - Prob. 6PS Ch. 3.1 - Prob. 7PS Ch. 3.1 - Prob. 8PS Ch. 3.1 - Prob. 9PS Ch. 3.1 - Prob. 10PS

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To find the derivative of the function f ( x ) = 1 2 − 3 x 3 .

Solution Summary: The author explains how to find the derivative of the function f(x)=sqrt[3]12-3.

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To find the derivative of the function f(x)=12−3x3 .

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Chapter 3 Solutions