a. Explanation Given: Initial velocity ( u ) = 160 ft/s . = 160 × 0 .3048 = 48 .768 m/s Concept used: Acceleration due to gravity = 9.81 m/s 2 Acceleration due to gravity in upward direction = − 9.81 m/s 2 Calculation: Final velocity of the ball at highest point or when it about to fall downward back. Final velocity (v) = 0 ft/s Calculating the distance travelled by the ball to reach the highest point. v 2 − u 2 = 2 a S (Formula) 0 2 − ( 48.768 ) 2 = 2 × ( − 9.81 ) × S S = 121.21 m Calculating the time taken t by the ball to reach highest point: v = u + a t (Formula) 0 = 48 b. To determine Velocity with which the ball hits the ground. c. To determine Time taken by the ball to reach maximum height.

Calculus: Special Edition: Chapters 1-5 (w/ WebAssign)

6th Edition

ISBN: 9781524908102

Author: SMITH KARL J, STRAUSS MONTY J, TODA MAGDALENA DANIELE

Publisher: Kendall Hunt Publishing

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Chapter 3.4, Problem 42PS

To determine

Time taken by the ball to hit the ground.

To determine

Velocity with which the ball hits the ground.

To determine

Time taken by the ball to reach maximum height.

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Chapter 3.4, Problem 41PS

Chapter 3.4, Problem 43PS

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Chapter 3 Solutions

Calculus: Special Edition: Chapters 1-5 (w/ WebAssign)

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Time taken by the ball to hit the ground.

Solution Summary: The author calculates the final velocity of the ball at highest point or when it about to fall downward back.

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Time taken by the ball to hit the ground.

Velocity with which the ball hits the ground.

Time taken by the ball to reach maximum height.

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Chapter 3 Solutions